Electroweak Theory

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Last updated 8:35 AM on 4/18/26
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26 Terms

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Parity

Parity is a discrete conserved quantum number, and is equal to the eigenvalue of any wavefunction that is an eigenstate of the space-inversion transformation, P^\hat P.

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Intrinsic parity of a particle

Either +1 = even parity, and −1 = odd parity.

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Total parity of a system of particles

Parity is a multiplicative quantum number, so the total parity of a system of particles a,b,...a, b, ... with orbital angular momentum LL is given by PaPb...(1)LP_aP_b...(−1)^L.

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What does conservation of parity mean for interactions?

Conservation of parity in an interaction means that:

  1. The interaction is invariant under a space-inversion transformation, i.e. under xx,yy,zzx → -x, y → -y, z → -z.

  2. The total parity before the interaction is equal to that after the interaction.

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Conservation of charge conjugation

The conservation of charge conjugation CC is a symmetry under particle antiparticle exchange.

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Eigenstates of C^\hat C

For a particle aa, a transformation under the charge conjugation operator changes it to its antiparticle aˉ\bar a: C^ψa=Caψa\hat Cψ_ a = C_aψ_a, so ψa\psi_a is only an eigenstate of C^\hat C is a=aˉa=\bar a, for example for photons.

The phase factor is Ca=±1C_a = ±1.

If a particle is not its own antiparticle, eigenstates can only be formed from linear combinations of the involved particles.

  • with aaˉa \neq \bar a the phase factor CaC_a cannot be measured, and can therefore be set to 1.

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Where is parity violated?

In the weak interaction, in the beta decay of Cobalt-60, for example.

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Where is charge conjugation violated>

In the weak interaction, for example, in muon decay μeνˉeνμ\mu^ − → e^ −\bar ν_eν_\mu or μ+e+νeνˉμ\mu^ + → e^ +ν_e\bar \nu_\mu (in which parity is also violated).

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Weak interaction and C and P violations

The weak interaction violates C and P transformations, but is invariant under a combined CP transformation (to a good approximation).

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Helicity

The projection of a particle’s spin on its direction of motion,

H=sppH = \frac{\vec s\cdot \vec p} {|\vec p|}

where s\vec s is the particle spin and p\vec p is the particle momentum.

  • a negative helicity means that the particle is left-handed, and a positive helicity means it is right-handed.

The projection of a fermion’s spin on any chosen axis can take two possible values: ±12\pm\frac{1} 2. Therefore, a fermion can have either H=±12H=\pm\frac{1}2.

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Right and left-handed neutrinos

Only left-handed neutrinos and right-handed antineutrinos interact weakly, and as neutrinos only interact via the weak force: only left-handed neutrinos (νLν_L) and right-handed antineutrinos (νˉR\bar ν_R) are observed in nature.

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Left-right-handedness and fermions

For any particle with non-negligible mass, (v < c), it is always possible for an observer to travel faster and overtake the particle. A left-handed particle would then appear right-handed.

A fermion (aside from neutrinos) cannot be said to be 100% left or right-handed,

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Suppressed transitions for quark mixing

Mixing across generations is highly suppressed, whilst transitions within the same generation are favoured.

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How is decay rate between different weak interactions determined?

By looking at CKM matrix for vertices which involve quarks. The largest decay rate of reaction is given by the largest VijVkl2|V_{ij}V_{kl}…|² for vertices with quark flavours i→j, k→l, etc.

If two interactions have identical quark mixing, the largest rate will be that which has the smallest final product masses.

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Bosons of the electroweak unified theory

Four massless bosons are predicted: W1,W2,W3W_1 , W_2 , W_3 and BB.

Electroweak spontaneous symmetry breaking (via the Higgs mechanism) occurs when going to lower energies, and the four bosons mix into the four physical states seen today:

the three massive

W+=12(W1+iW2),W=12(W1iW2),Z=W3sinθW+BcosθWW^+ = \frac{1} {\sqrt 2} (W_1 + iW_2), \qquad W^− = \frac{1} {\sqrt 2} (W_1 − iW_2),\qquad Z = W_3\sin θ_W + B\cos θ_W

and the one massless

γ=W3cosθWBsinθWγ = W_3\cos θ_W − B\sin θ_W

where θWθ_W is the weak mixing angle (or the Weinberg angle) and is defined by cosθW=MW/MZ\cos θ_W = M_W/ M_Z.

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Why is the weak force so much weaker than EM?

The intrinsic strengths of the weak and electromagnetic interactions are very similar, but the difference in the masses of the bosons leads to different interaction strengths.

Seen by the scattering amplitudes of an interaction with the W boson at:

  • q2MWq²\ll M_W: low energies MgW22MW2c2\mathcal{M} \backsim- \frac{g_W^2\hslash^2}{ M^2_ Wc^2 } giving a weaker interaction,

  • q2MWq²\gg M_W: high energies MgW22c2q2\mathcal{M} \backsim- \frac{g_W^2\hslash^2c^2}{ q^2 } where interaction is no longer dependent on MWM_W, giving a stronger interaction.

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Requirements of gauge theories

The equations of the theory must be invariant under local gauge transformations of the wavefunctions describing the particles.

A local gauge transformation acts on the wavefunction like: Ψ(x,t)Ψ(x,t)=eif(x,t)Ψ(x,t)\Psi (\vec x, t) \,\,→\,\,\Psi'(\vec x, t) = e ^{−if(\vec x,t)}\Psi(\vec x, t), where local means that the function ff depends on x\vec x and tt.

  • If ff were constant, it would be global gauge transformation.

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Free particle equations under local gauge transformation

Free particle equations are not invariant under such a transformation, because they contain time and space derivatives that give rise to troublesome terms leading to differences in the equations before and after the transformation.

To solve this, additional terms were added to the equations, which gave rise to particle interactions via gauge bosons.

  • However, the gauge bosons must be massless to avoid destroying the gauge invariance.

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Higgs mechanism

The expectation value of the Higgs field in the vacuum is non-zero, unlike all the other fields. Consider the potential of the field to have a shape that does not minimise at zero.

The Universe chooses a given point in the minimum for the value of the field in the vacuum. This choice spontaneously breaks the symmetry.

The masses arise from the interactions of the gauge bosons with the non-zero vacuum expectation value of the Higgs field. (So the value of the field in the vacuum is not gauge invariant, but the interactions are, allowing massive particles without breaking the gauge theory.)

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Dominant production mechanisms for the Higgs

(a) gluon-gluon fusion,

  • gluons are massless and do not couple to the Higgss so this occurs through a quark loop.

(b) weak boson fusion,

  • either a W±W^± or a ZZ boson is radiated from a quark (from colliding protons), then a W+WW^+W^− or a ZZZZ pair fuse to form a Higgs.

(c) associated W/Z Higgs production.

  • a virtual W±W^± or a ZZ boson is produced, for example by qqˉq\bar q annihilation, and the boson radiates a Higgs boson.

where VV represents either a W±W^\pm or ZZ boson.

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Dominant decay channels of the Higgs

  1. Into a bbˉb\bar b pair.

  2. Into a W+WW^+W^− pair (note M_H<2M_W, but if one of the W bosons is produced with a mass <M_W (which is allowed for virtual particles) this is possible, although suppressed.).

  3. Other important decays: into a ZZ pair, a τ+ττ^ +τ^− pair, a γγ pair.

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Searching for the Higgs

Very rare production, so must look in decay channels with low backgrounds.

  • A background is another type of process that mimics the Higgs production as it has the same, or similar, final-state particles.

Look for a statistically significant excess of events over the expected contribution from background processes, as we cant know if a given pp interaction produced a Higgs.

The invariant mass of the Higgs decay particles peaks at mHm_H, so must search for a peak in the invariant mass distribution of decay products.

2012 discovery channels were H→ ZZ and H → γγ, which had small branching fractions but low backgrounds.

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How can HγγH→ \gamma\gamma exist if photons are massless?

This decay channel occurs via a top quark loop, just like the gluon-gluon fusion production process of the Higgs does.

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Why are some decay channels for the Higgs much rarer than others?

The Higgs couples to mass, so particles with a low mass are much less strongly coupled to it. Therefore, decay channels involving lighter particles are much rarer.

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Why was it difficult to observe the Higgs boson in its most dominant decay channel?

Its dominant decay channel is HbbˉH→ b\bar b, which is a challenge to observe because:

  • 1. There is a huge background in this channel.

  • 2. The mass resolution in di-jets is much worse than in di-photons or charged leptons.

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Which interactions give unambiguous evidence for neutral currents?

Processes that look like: νe+μνe+μ\nu_e + \mu^- → \nu_e+\mu^- , or νμ+Nνμ+Hadrons\nu_\mu+N→ \nu_\mu + \text{Hadrons}.

These processes can only occur via Z0Z^0 bosons, (as W±W^\pm bosons would result in a violation of lepton number or charge).

  • The process νμ+μνμ+μ\nu_\mu+\mu^- → \nu_\mu+\mu^-, for example, can go via either W or Z exchange.

  • The process νmu+Nμ+Hadrons\nu_mu+N→ \mu^-+\text{Hadrons}, for example, can go via either W or Z exchange.

<p>Processes that look like: $$\nu_e + \mu^- → \nu_e+\mu^-$$ , or $$\nu_\mu+N→ \nu_\mu + \text{Hadrons}$$.</p><p>These processes can only occur via $$Z^0$$ bosons, (as $$W^\pm$$ bosons would result in a violation of lepton number or charge).</p><ul><li><p>The process $$\nu_\mu+\mu^- → \nu_\mu+\mu^-$$, for example, can go via either W or Z exchange.</p></li><li><p>The process $$\nu_mu+N→ \mu^-+\text{Hadrons}$$, for example, can go via either W or Z exchange.</p></li></ul><p></p>