SysSig - Ch 10.1 to 10.5 - SteadyState power

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Last updated 2:42 PM on 5/22/26
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33 Terms

1
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<p>For this box, state equations for the steady state sinusoidal signals of v and i</p>

For this box, state equations for the steady state sinusoidal signals of v and i

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2
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<p>For this circuit and v , i equations, describe what is meant by instananous power</p>

For this circuit and v , i equations, describe what is meant by instananous power

  • The power at any instant of time

  • p = vi

3
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Use the steady state sinusoidal signals of v and i to derive the formula for power at any given instant of time

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4
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<p>Describe the terms in the final instant power equation and show how it would look on a graph</p>

Describe the terms in the final instant power equation and show how it would look on a graph

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5
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<p>For an instant power graph, describe what happens when p is negative</p>

For an instant power graph, describe what happens when p is negative

  • When it is negative the energy stored in inductors or capacitors is being extracted

6
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<p>Rewrite the instant power equation in a simpler form. <br>State the identity of the terms</p>

Rewrite the instant power equation in a simpler form.
State the identity of the terms

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7
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State what is meant by average/real power

  • power that is transformed from electric to nonelectric energy

8
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Describe why P is called average power by using integrals and stuff

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9
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Describe the instantanous power for purely resistive circuits

  • p = P + P cos (wt)

    • where P= avg power and w = angular freq

  • Also called instantaneous real power

  • power is never negative

    • power cannot be extracted from a purely resistive circuit

<ul><li><p>p = P + P cos (wt)</p><ul><li><p>where P= avg power and w = angular freq</p></li></ul></li><li><p>Also called instantaneous real power</p></li><li><p>power is never negative</p><ul><li><p>power cannot be extracted from a purely resistive circuit</p></li></ul></li></ul><p></p>
10
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Show how a graph with w = 377, and P = 1 got a purely resistive circuit would look like

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11
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state the instant power expression in purely inductive circuits

  • for purely inductive circuits, current lags behind voltage by 90°

    • θi = θv - 90° and thus θv - θi = +90

  • thus instant power expression is p = -Qsin2wt

<ul><li><p>for purely inductive circuits, current lags behind voltage by 90°</p><ul><li><p>θi  = θv - 90° and thus θv - θi = +90</p></li></ul></li><li><p>thus instant power expression is p = -Qsin2wt</p></li></ul><p></p>
12
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Describe the instant power expression for purely inductive circuits

  • avg power P = 0 (no energy converted from electric to nonelectric)

  • power is exchanged from circuit and source at frequency 2w

  • when p > 0, energy is stored in the inductive elements

  • when p < 0, energy is extracted from the inductive elements

13
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State the units for average/real power and reactive power

  • units for P = watt

  • units for Q = volt-amp reactive/VAR

14
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Describe how a graph of instant power for a purely inductive circuit would look like. Q = 1 VAR, w = 377

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15
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State the instant power expression for purely capacitive circuits

  • in purely capacitive circuits, current leads voltage by 90°

    • thus θi = θv + 90° or θv - θi = -90°

  • thus p = -Qsin 2wt

<ul><li><p>in purely capacitive circuits, current leads voltage by 90°</p><ul><li><p>thus θi = θv + 90° or θv - θi = -90°</p></li></ul></li><li><p>thus p = -Qsin 2wt</p></li></ul><p></p>
16
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Describe the instant power expression for purely capacitive circuits and draw a graph where Q = -1 VAR and w = 377

  • P = 0 so no energy is converted from electric to non electric

  • power is exchanged from the source and capacitor

<ul><li><p>P = 0 so no energy is converted from electric to non electric</p></li><li><p>power is exchanged from the source and capacitor</p></li></ul><p></p>
17
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State when Q is positive or negative relative to inductors and capacitors

Q > 0 for inductors

Q < 0 for capacitors

18
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State what is meant by a:

  • power factor angle

  • power factor

  • reactive factor

  • power factor angle = θv - θi

  • power factor = pf = cos (θv - θi)

  • reactive factor = rf = sin (θv - θi)

<ul><li><p>power factor angle = θv - θi</p></li><li><p>power factor = pf = cos (θv - θi)</p></li><li><p>reactive factor = rf = sin (θv - θi)</p></li></ul><p></p>
19
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Describe what is meant by lagging and leading power factor

State why we us these terms

  • cos (θv - θi) = cos (θi - θv) so terms need to be used

  • lagging power factor means current lags voltage, so inductive

  • leading power factor means current leads voltage, so capacitive

<ul><li><p>cos (θv - θi) = cos (θi - θv) so terms need to be used</p></li><li><p>lagging power factor means current lags voltage, so inductive</p></li><li><p>leading power factor means current leads voltage, so capacitive</p></li></ul><p></p>
20
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Derive the average power of a sinusoidal voltage source delivered to a resistor in terms of Vrms and Irms

  • P = avg power, thus P = power through resistor over time

  • P = V²rms / R

  • P = I²rms * R

<ul><li><p>P = avg power, thus P = power through resistor over time</p></li><li><p>P  = V²rms / R</p></li><li><p>P = I²rms * R</p></li></ul><p></p>
21
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Describe the rms value of a sinusoidal voltage/current

  • The rms value delivers the same energy to R as a DC source of the same value

  • Referred to as the effective value

22
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Rewrite avg power P and reactive power Q in terms of the rms values

P = Vrms* Irms*cos(θv - θi)

Q = Vrms * Irms * sin (θv - θi)

<p>P = Vrms* Irms*cos(θv - θi)</p><p>Q = Vrms *<em> </em>Irms * sin (θv - θi)</p>
23
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State the expression for complex power

  • S = P + jQ where:

    • S = complex power units are volt-amps

    • P = avg/real power units are watts

    • Q = reactive power units are var

24
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Describe the complex power in relation the power triangle

  • |S| is the hypotenuse

  • P and Q are the sides of the triangle

  • θ is the angle between |S| and P

  • θ = θv - θi

<ul><li><p>|S| is the hypotenuse</p></li><li><p>P and Q are the sides of the triangle</p></li><li><p>θ is the angle between |S| and P</p></li><li><p>θ = θv - θi </p></li></ul><p></p>
25
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Describe what is meant by apparent power

  • modulus of complex power

  • |S| = sqrt ( P² + Q²)

  • represents the power transferred to components and the power produced by reactive components

26
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Derive the phasor form expression of S in terms of Vm, Im and in terms of Vrms, Irms

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27
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Derive the equations for the alternate form of the complex power in terms of the rms and amplitude values

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28
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Derive the expression for complex power through an impeding component in phasor form where Vrms = Z * Irms

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29
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Derive the expression for complex power through an impeding component in phasor form where Irms = Vrms / Z

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30
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<p>For this circuit derive the equations proving condition for achieving maximum average power transfer</p>

For this circuit derive the equations proving condition for achieving maximum average power transfer

  • I = Vth / (Zth + ZL)

  • P = |I|² * RL

  • sub (1) into (2)

  • P is max when Xth = -XL

  • Derive P it is max when Rth = sqrt( Rth² + ( XL + Xth)² )

  • Thus P is max when:

    • ZL = Zth*

<ul><li><p>I = Vth / (Zth + ZL)</p></li><li><p>P = |I|² * RL</p></li><li><p>sub (1) into (2)</p></li><li><p>P is max when Xth = -XL</p></li><li><p>Derive P it is max when Rth = sqrt( Rth² + ( XL + Xth)² )</p></li><li><p>Thus P is max when:</p><ul><li><p>ZL = Zth*</p></li></ul></li></ul><p></p>
31
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Derive the expression for Pmax when the conditions are met. In terms of Vrms and Vm

  • Vrms = Vm / sqrt(2)

  • I = V / Z

  • P = I² * RL

<ul><li><p>Vrms = Vm / sqrt(2)</p></li><li><p>I = V / Z</p></li><li><p>P = I² * RL</p></li><li><p></p></li></ul><p></p>
32
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Describe how to acquire maximum power transfer to a load when XL and RL are limited

  • Set XL as close to -Xth as possible

  • Set RL as close to sqrt( Rth² + ( XL + Xth)² )

<ul><li><p>Set XL as close to -Xth as possible</p></li><li><p>Set RL as close to sqrt( Rth² + ( XL + Xth)² )</p></li></ul><p></p>
33
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Describe how to get max P transferred to a load when the magnitude of ZL can be varied but its phase angle cannot

  • |ZL| = |Zth|

<ul><li><p>|ZL| = |Zth|</p></li></ul><p></p>