Enzyme kinetics and inhibition

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Last updated 2:34 PM on 4/28/26
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22 Terms

1
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what is enzyme rate? + give equation

the number of moles of product produced per unit time

rate (v) = d[P]/dt = k2 [ES]

2
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give the equation describing how an enzyme-controlled reaction proceeds, and explain what it shows

E + S <=> ES —> E + P

enzyme and substrate must combine to form ES complex, then enzyme must be recycled after the reaction is finished

k1 = forward reaction of E + S to ES

k2 = ES —> E + P - catalytic rate, rate limiting step

k-1 = reverse reaction ES to E + S

3
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what is the rate limiting step of an enzyme driven reaction?

the production of the product (driven by k2 rate)

4
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describe what zero, first and second order enzyme-driven reactions are

zero - no relationship between V and [S]

first - rate dependent on [S]

second - relationship between V and [S] not proportional to [S], but rather multiple substrates

5
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what order kinetics must be present to study enzymes and why?

first order

allows easy measure of enzyme’s catalytic efficiency, as describes the phase of a reaction where the rate is directly proportional to the substrate concentration

6
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describe how an enzyme-controlled reaction changes from first to zero order kinetics as the reaction proceeds

velocity increases as [S] increases up to a point where the enzyme is ‘saturated’ with substrate (Vmax)

at Vmax the rate of reaction is unaffected by increase in [S] as all enzyme active sites are in use

7
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what assumptions must be met for Michaelis-Menten equation?

equilibrium - the association and dissociation of the substrate and enzyme is assumed to be a rapid equilibrium (e + s to es is fast)

steady state - ES immediately comes to a steady state and is a constant (ie ES is formed as fast as enzyme releases the product)

8
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what is the ratio of rate constants from the Michaelis-Menten equation defined as?

the Michaelis constant (KM)

KM = k-1 + k2 / k1

9
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give the Michaelis-Menten equation

V0 = Vmax [S]/ KM + [S]

10
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what does the Michaelis-Menten constant KM represent?

[S] at which the rate of reaction is half its maximum (1/2 Vmax)

dissociation constant of ES (substrate affinity) - low values indicate ES complex is held together tightly and rarely dissociates without S first reacting to form P

11
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what is the enzyme catalytic constant?

Kcat

turnover number = the maximum number of S converted to P per second by each active site, when the enzyme is fully saturated with substrate

measures how fast a given enzyme can catalyse a specific reaction

units = s-1

larger kcat = more rapid catalytic events at the enzymes active site

12
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what is the Lineweaver-Burke plot?

a graphical representation of the Michaelis-Menten equation

used to calculate Vmax and KM

13
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describe 4 factors that influence enzyme kinetics

concentration of substrate molecules - more substrate available = increased frequency of enzyme binding

temperature - higher temperatures = increased molecular motion (limited by protein denaturation limits)

pH - protein conformation and molecular changes of active sites

presence of inhibitors

14
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what is an enzyme unit?

the conversion of one micromole of a substrate to product per minute, under specific conditions of pH and temperature

1 enzyme unit = micromole/min

15
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what are some real-world limitations of Michaelis-Menten kinetics?

relies on law of mass action - assumes free diffusion and thermodynamically-driven random collision

many biochemical or cellular processes deviate from these conditions

eg,

  • cytoplasm behaves more like a gel than a freely flowable aqueous solution, severely limiting molecular movements

  • heterogenous (different phases) enzymatic reactions - molecular mobility of E or S can be restricted, due to immobilisation or phase-separation of reactants

  • homogenous (same phase) enzymatic reactions - mobility of of E or S ma be limited

16
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describe the concept of random substrate binding

assumes independent binding of substrates and products

two independent binding sites - substrate binding independent of other substrate

17
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describe the concept of ordered substrate binding

one substrate must bind before second substrate can bind effectively

18
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describe the concept of the ping-pong mechanism of multisubstrate reactions

likely theoretical - not seen in reality

enzyme binds substrate A and then releases P

intermediate form of enzyme (E*) often carries A fragment and then binds B

product Q released and enzyme returns to original state (E)

19
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outline where competitive, non-competitive and uncompetitive inhibitors behind

comp - to enzyme’s active site

non - at separate site (not AS)

un - at separate site, but only bind enzyme-substrate complex

20
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outline how competitive inhibitors work

reversible

has a structure similar to the substrate

competes with S for active site

effect is reversed by increasing [S]

Vmax unchanged, Km increase by (1 + [I]/ki)

21
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outline how non-competitive inhibitors work

have a structure different to S

bind to allosteric site

distorts the shape of E and active site, preventing S from binding

not reversed by increasing [S]

Vmax decreases by (1 + [I]/ki)

Km no change

22
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outline how uncompetitive inhibitors work

only exist in theory, not in practice

inhibitor binds only to ES complex, not free E