Equillibrium Lab

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Last updated 7:50 PM on 4/27/26
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32 Terms

1
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Purpose

To determine the equilibrium constant (Kc) for the reaction with a series of Iron III and SCN- reactions

<p>To determine the equilibrium constant (Kc) for the reaction with a series of Iron III and SCN- reactions</p>
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What is Kc?

Kc = [FeSCN²⁺] / ([Fe³⁺][SCN⁻])

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What does K tell you when it’s greater than one?

K>1 means products are favored

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What does K tell you when it’s less than one?

K<1 means reactants are favored

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Where are the iron thiocyanite equations thrown away?

Blue label waste container.

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What’s the difference between the initial [SCN-] and [SCN-] consumed?

[SCN-] present at equillibrium

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What’s the difference between the initial [Fe+3] and [Fe+3]

consumed?

[Iron III] present at equillibrium

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What is plotted in Beer’s Law curve?

Absorbance vs. Concentration

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Purpose of Part I?

Create a calibration curve to find K

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Purpose of part II?

Determine equilibrium concentrations and calculate Kc

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Procedure Part 1

1.Added 10.0mL of Iron III solution to 6 50mL volumetric flasks with a 10.0mL graduated cylinder

2.Pipetted 1.0-5.0mL of 0.0020M KSCN to flasks B-F

3.Added 0.1M HNO3 to each volumetric flask until 50.0mL, covered with parafilm, and mixed

4.Transferred solutions to cuvettes and measured absorbances at 447nm with the spectrophotometer

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Procedure Part II

1.Added 5.0mL of 0.0020M Fe(NO3)3 to test tubes A-F

2.Added 1.0-5.0mL of 0.0020M KSCN to test tubes B-F in increasing order

3.Added HNO3 to test tubes A-E to add to 10.0mL, covered with parafilm and inverted to mix

4.Transferred solutions to cuvette and measured absorbances at 447nm with the spectrophotometer

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What settings is the spectrophotometer?

447nm

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What was the purpose of KSCN (the source of SCN-)?

In part 1, determines the known concentrations of FeSCN+2 and

In part 2, establishes the diff equillibrium mixtures to calculate Kc

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What was the concentration of the Fe(NO3)3 stock solution for the calibration curve(Part 1)?

0.2M

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What was the concentration of the KSCN stock solution?

0.002M for part 1 and 2

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What was the concentration of the Fe(NO3)3 stock solution part two?

0.002M, the same as KSCN

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Why does initial [SCN-] = [FeSCN²⁺]?

There’s more iron III so all of SCN- reacts completely

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Use dilution to calculate initial [SCN-]/[FeSCN+2] for calibration curve

C1 = 0.002M KSCN       V1 = Volume of KSCN added (mL)

C2 = X [SCN-]                V2 = 50.0mL

<p><span style="background-color: transparent; font-family: &quot;Times New Roman&quot;, serif;">C<sub>1</sub> = 0.002M KSCN &nbsp; &nbsp; &nbsp; V<sub>1</sub> = Volume of KSCN added (mL)</span></p><p><span style="background-color: transparent; font-family: &quot;Times New Roman&quot;, serif;">C<sub>2</sub> = X [SCN-]&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; V<sub>2</sub> = 50.0mL</span></p>
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Calculating initial [Fe+3] for calibration curve

1.Molarity x Volume = Moles

2.Moles/Total Volume = Molarity

Molarity of Fe(NO3)3 Stock Part 1 (0.2M) x 10.0mL = molsFe(NO3)3

Fe(NO3)3 mols/ 50.0mL total volume solution = [Fe+3]

<p>1.Molarity x Volume = Moles</p><p>2.Moles/Total Volume = Molarity</p><p></p><p>Molarity of Fe(NO<sub>3</sub>)<sub>3 </sub>Stock Part 1 (0.2M) x 10.0mL = molsFe(NO<sub>3</sub>)<sub>3</sub></p><p>Fe(NO<sub>3</sub>)<sub>3 </sub>mols/ 50.0mL total volume solution = [Fe<sup>+3</sup>]</p>
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What calculations are for part 1?

Equilibrium [FeSCN+2] = initial [SCN-], initial [Fe+3]

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Why is the calculated initial [Fe+3] constant for each table?

We added the same amount of Fe+3 to every solution each part of the experiment, so it’s the same concentration

Using 0.0020MFe+3, 10.0mL in each flask part 1 and then 5.0mL each tube part 2.

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What calculations are in part II?

initial [Fe+3]

initial [SCN-]

equillibrium[FeSCN+2]

then calculate [Fe+3] and [SCN-] at equillibrium with an ICE box

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How to find [FeSCN+2] with the graph for part 2?

Absorbance/slope

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Equation for ice box

[Fe+3] + [SCN-] → [FeSCN+2]

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How to find Fe+3] and [SCN-] with icebox

We know:

[FeSCN+2] at equilibrium and all the initial concentrations

then add/subtract to find the rest of the concentrations at equilibrium

Use K = FeSCN+2]     

[Fe+3] [SCN-]

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Calculating initial [Fe+3] in part 2

[Fe+3] = (M stock x mL added/ Total Volume

0.0020M Fe(NO3)3 × 5.0mL/ 10.0mL = 0.0010M

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Calculating initial [SCN-] in part 2

C1 = 0.002M KSCN

V1 = Volume of KSCN added(mL)

C2 = X [SCN-] we want to find

V2 = 10.0mL total volume

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What does the spectrophotometer detect?

FeSCN+2 complex

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Role of HNO3

To maintain an acidic environment for the reaction

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Why keep total volume the same in each trial?

So concentration differences are only due to reactants, not dilution

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Does K have units?

No