Physical Techniques

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Last updated 12:23 AM on 4/19/26
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14 Terms

1
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What three main properties do physical characterization techniques determine?

  1. Composition/formula (chemical analysis)

  2. Connectivity (structures/isomers)

  3. Electronic structure

2
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If a physical technique tells us the oxidation state, location of unpaired electrons, or colour of a material, what specific property is it measuring?

The distribution of electrons (electronic structure)

3
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Why are x-rays specifically used to produce diffraction patterns from crystals instead of other types of light?

Their wavelengths (~10-10m or 1 Å) are on the exact same order of magnitude as the spacing between atoms.

4
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What happens to x-rays when they interact with the electrons in a crystal?

They will be scattered elastically, with no change in their energy.

5
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In a powder diffraction pattern, what specific information do the positions of the peaks give you, versus the intensities of the peaks?

Peak Positions = Size and shape of the unit cell. Peak Intensities = Types of atoms present and their positions.

6
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Why does an element like Lead (Pb) produce a much stronger X-ray diffraction signal than Sodium (Na)?

X-rays are scattered by electrons. Scattering power is proportional to the square of the number of electrons present in the atom, so heavier elements dominate the signal.

7
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You are analyzing a solid containing both Lead (Pb) and Hydrogen (H). Why is Neutron Diffraction a better tool than X-ray Diffraction for this specific compound?

X-ray diffraction is completely dominated by the electron-heavy Pb, making H (1 electron) virtually undetectable. Neutrons are scattered by nuclei rather than electron clouds, allowing very light elements to be easily distinguished.

8
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What specific physical event happens when a material absorbs energy in the UV-Vis range (300-800 nm)?

Electrons are excited into higher energy levels (electronic spectroscopy).

9
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Why do transition-metal coordination compounds tend to have bright, distinct colors?

Visible light (~400-750 nm) provides the exact quanta of energy required to excite electrons between d-orbitals.

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