Algebra 2 Spring Final Review

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/10

flashcard set

Earn XP

Description and Tags

This set of vocabulary flashcards covers essential Algebra 2 concepts including function behaviors, asymptotes, complex equations, and growth/decay formulas derived from the final review transcript.

Last updated 4:15 AM on 5/21/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

11 Terms

1
New cards

Relative Minima and Maxima

The low and high points within a specific range of a function; for the function f(x)=x3+2x2+3f(x) = -x^3 + 2x^2 + 3, the approximate minimum is (0,3)(0, 3) and the maximum is (1.333,4.185)(1.333, 4.185).

2
New cards

Distinct Real Zeros

The points where a function's graph crosses the x-axis, also referred to as x-intercepts.

3
New cards

Inverse Function

A function that reverses the operation of the original function, denoted as g1(x)g^{-1}(x); for the function y=x23y = \frac{x-2}{3}, the inverse is discovered by swapping variables to get g1(x)=3x+2g^{-1}(x) = 3x + 2.

4
New cards

Horizontal Asymptote

A horizontal line that a graph approaches as xx goes to infinity; in f(x)=5x+4x3f(x) = \frac{5x+4}{x-3}, the asymptote is y=5y=5 because the degrees of the numerator and denominator are equal (n=dn=d), whereas in f(x)=1x+5f(x) = \frac{1}{x+5}, the asymptote is y=0y=0 because n<dn < d.

5
New cards

Vertical Asymptote

A vertical line where a function is undefined, typically found by setting the denominator to zero; for f(x)=x(x+3)(x4)f(x) = \frac{x}{(x+3)(x-4)}, the vertical asymptotes are x=3x=-3 and x=4x=4.

6
New cards

Extraneous Solutions

Solutions derived during algebraic manipulation that do not satisfy the original equation, often requiring validation through checking, such as in rational equations like 1x6+2x236=x+2x+6\frac{1}{x-6} + \frac{2}{x^2-36} = \frac{x+2}{x+6}.

7
New cards

Exponential Depreciation Formula

A mathematical model used to calculate decreasing value over time, represented by f(t)=a(1r)tf(t) = a(1 - r)^t; applied to a car purchased for $22,400\$22,400 at an 11%11\% rate, the value after 66 years is approximately $11,132.38\$11,132.38.

8
New cards

Continuous Compounding Formula

A growth model represented by A=PertA = Pe^{rt}, where AA is the final amount, PP is the principal, rr is the interest rate, and tt is time; for an account growing from $5,000\$5,000 to $6,880\$6,880 at 3.9%3.9\%, the time required is 8.28.2 years.

9
New cards

Exponential Growth Formula

A model used to calculate population or value increases over time, expressed as f(t)=a(1+r)tf(t) = a(1 + r)^t; used when a town of 17,00017,000 people grows at 3%3\% for 1010 years to reach 22,84622,846 people.

10
New cards

Leading Coefficient

The coefficient of the term with the highest degree in a polynomial, which determines the end behavior of the graph along with the degree being even or odd.

11
New cards

Function Composition

The application of one function to the results of another, such as finding f(g(0))f(g(0)) by substituting the value from g(x)g(x) into f(x)f(x); for f(x)=3x5f(x) = 3x-5 and g(x)=x29g(x) = x^2-9, the result is 32-32.