MS - The effect of drug structure on fragmentation DBE and the nitrogen rule

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Last updated 5:37 PM on 4/25/26
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22 Terms

1
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What is mass spectrometry?

Process of ionization, separation and detection if ions according to their mass-to-charge (m/z) ratio

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What are the uses of mass spec?

  • Molecular weight – how big?

  • Fragmentation/isomers

  • Isotope analysis

  • Drug metabolite analysis

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What are the advantages and disadvantages of mass spec?

  • Advantages - smallest sample size 10-12 g, accurate mwt to 4 dec. pl, exact molecular formulae

  • Disadvantages - destructive technique, no sample recovery, requires expert operator, and high-cost equipment

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What is ionisation?

High energy electrons impact on neutral drug to remove e- from the drug to give molecular ion = molecular weight (M)

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What is fragmentation?

Charged molecular ion is a high energy radical cation that can break/fragment to give daughter ions that are separated according to mass-to-charge (m/z) ratio (M+.)

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What is detected in mass spec?

Only charged structures detected, not radicals or neutrals

  • High vacuum required because of the highly reactive structures formed

  • M- and M+ or M+. and M

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What is the base peak in mass spec?

The tallest, most intense peak in the spectrum, representing the most abundant ion.

  • It is assigned a relative abundance/intensity of 100%

<p><mark data-color="rgba(0, 0, 0, 0)" style="background-color: rgba(0, 0, 0, 0); color: inherit;">The tallest, most intense peak in the spectrum, representing the most abundant ion</mark><span>. </span></p><ul><li><p><span>It is assigned a relative abundance/intensity of 100%</span></p></li></ul><p></p>
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Is the M+. always the base peak and why?

No

  • Branching gives a weak M+. as it can fragment and break

<p>No</p><ul><li><p>Branching gives a weak M<sup>+.</sup> as it can fragment and break</p></li></ul><p></p>
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<p>Why does CH₃CH₂Cl have 2 peaks for M<sup>+. </sup>?</p>

Why does CH₃CH₂Cl have 2 peaks for M+. ?

Due to Cl having 35 and 37 isotopes

  • In a 3:1 ratio

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What are the 3 fragments CH₃CH₂Cl can break into?

  • Homolytic cleavage - radical formation, breaking C-C

    • CH₃CH₂Cl+. → CH2=Cl+ → m/z 49,51

  • Heterolytic cleavage - carbocation formation, breaking C-Cl

    • CH₃CH₂Cl+. → CH3CH2+ → m/z 29

  • Loss of neutral fragment - lose uncharged, stable molecule, HCl

    • CH₃CH₂Cl+. → CH2CH2+ → m/z 28

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Give examples of neutral molecules that can be lost

  • H₂ — loss of hydrogen

  • H₂O — dehydration (common in alcohols)

  • CO — carbonyl-containing compounds

  • CO₂ — carboxylic acids, esters

  • NH₃ — amines, amides

  • HCl, HBr, HI — haloalkanes (e.g., chloroethane)

  • CH₄ — alkanes

  • C₂H₄ (ethene) — common in alkyl chain rearrangements

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How many chlorines coresspond to number of molecular ions?

  • 1 Chlorine Atom: Produces two molecular ion peaks with a 3:1 intensity ratio. M and M+2

  • 2 Chlorine Atoms: Produce three molecular ion peaks with a 9:6:1 intensity ratio. M and M+2 and M+4

  • 3 Chlorine Atoms: Produce four molecular ion peaks with a 27:27:9:1 ratio. M and M+2 and M+4 and M+6

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<p>Why does nicotinamide have 2 fragmentation pathways?</p>

Why does nicotinamide have 2 fragmentation pathways?

  • Proportion of molecular ions fragment at the C-C bond

  • Other molecular ions fragment at the amide C-N bond

<ul><li><p><span>Proportion of molecular ions fragment at the C-C bond</span></p></li></ul><ul><li><p><span>Other molecular ions fragment at the amide C-N bond</span></p></li></ul><p></p>
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<p><span>Why does amphetamine give m/z = 91 not 77 in the MS?</span></p>

Why does amphetamine give m/z = 91 not 77 in the MS?

The fragmentation process leads to the formation of a highly stable benzyl carbocation (tropylium ion)

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<p>What is Mclafferty rearrangement?</p>

What is Mclafferty rearrangement?

When the molecular ion forms, the carbonyl oxygen abstracts the γ‑hydrogen. This occurs through a six‑membered cyclic transition state, leading to:

  1. Transfer of the γ‑H to the carbonyl oxygen

  2. Cleavage of the α–β bond

  3. Formation of:

    • A charged enol radical cation (detected in MS)

    • A neutral alkene (not detected)

Happens in ketones, aldehydes, esters, and carboxylic acids that have a γ‑hydrogen.

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What is combustion analysis?

Gives drug composition % C,H,N …also F,Cl,P…..

  • O measured by difference few mg sample needed

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What is the empirical and molecular formula?

  • Empirical formula - gives ratio of each element using % composition from combustion analysis

  • Molecular formula - calculate exact number of each atom present using empirical formula and molecular weight from MS

Check if % add up to 100 to see if O is present

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How do you know a drug is pure using mass spec?

For any new drug, % for all elements measured must be
within +/- 0.3 of the calculated value

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What is the double bond equivalent and equation?

Total number of double bonds + rings.

  • Large DBE value but small number of C suggest rings present in the drug

  • Divalent sulphur - oxidation state = 2 → makes 2 bonds

  • Tetravalent sulphur - makes 4 bonds

  • Hexavalent sulphur - 6 covalent bonds → add 4x number of sulphurs

<p>T<span>otal number of double bonds + rings. </span></p><ul><li><p><span>Large DBE value but small number of C suggest rings present in the drug</span></p></li><li><p><span>Divalent sulphur - oxidation state = 2 → makes 2 bonds</span></p></li><li><p><span>Tetravalent sulphur - makes 4 bonds</span></p></li><li><p><span>Hexavalent sulphur - 6 covalent bonds → add 4x number of sulphurs</span></p></li></ul><p></p>
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<p>Calculate the empirical formula, molecular formula and DBE of <span>nicotinamide</span></p>

Calculate the empirical formula, molecular formula and DBE of nicotinamide

  • Molecular formula, M+ = 122
    Empirical formula = C6H6N2O = 122
    Empirical formula x 1 = Molecular formula

  • DBE

½ (2NC - NH + NN + 2) = ½ ((2 x 6) – 6 + 2 + 2) = ½ (10) = 5

<ul><li><p>Molecular formula, M+ = 122<br>Empirical formula = C6H6N2O = 122<br>Empirical formula x 1 = Molecular formula</p></li></ul><ul><li><p>DBE</p></li></ul><p>½ (2N<sub>C</sub> - N<sub>H</sub> + N<sub>N</sub> + 2) = ½ ((2 x 6) – 6 + 2 + 2) = ½ (10) = 5</p>
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What is the nitrogen rule?

  • Even number of nitrogens, even molecular weight

  • Odd number of nitrogens, odd molecular weight (0 is even)

<ul><li><p><span>Even number of nitrogens, even molecular weight</span></p></li></ul><ul><li><p><span>Odd number of nitrogens, odd molecular weight (0 is even)</span></p></li></ul><p></p>
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