Calculus AB Derivation/Integration Euler/Log + Inverse Identities

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/14

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 5:13 PM on 4/23/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

15 Terms

1
New cards

d/dx ln(f(x))\ln\left(f\left(x\right)\right)

f(x)f(x)\frac{f^{\prime}\left(x\right)}{f\left(x\right)}

2
New cards

The derivative of a general inverse function, where f(a)=b and f^-1(b) = g(b) = a

g(b)=1f(a)g^{\prime}\left(b\right)=\frac{1}{f^{\prime}\left(a\right)}

3
New cards

 ⁣g(x)eg(x)dx\int_{}^{}\!g^{\prime}\left(x\right)\,e^{g\left(x\right)}\cdot dx

eg(x)+Ce^{g\left(x\right)}+C

4
New cards

d/dx (logbx\log_{b}x)

1lnbg(x)g(x)\frac{1}{\ln b}\cdot\frac{g^{\prime}\left(x\right)}{g\left(x\right)}

5
New cards

d/dx (axa^{x})

axlnaa^{x}\cdot\ln a

6
New cards

axdx\int a^{x}dx

axlna+c\frac{a^{x}}{\ln a}+c

7
New cards

d/dx (sin1(u)\sin^{-1}\left(u\right))

u1u2\frac{u^{\prime}}{\sqrt{1-u^2}}

8
New cards

d/dx (cos1(u)\cos^{-1}\left(u\right) )

u1u2-\frac{u^{\prime}}{\sqrt{1-u^2}}

9
New cards

d/dx (tan1(u)\tan^{-1}\left(u\right) )

uu2+1\frac{u^{\prime}}{u^2+1}

10
New cards

d/dx (cot1(u)\cot^{-1}\left(u\right))

uu2+1-\frac{u^{\prime}}{u^2+1}

11
New cards

d/dx (sec1(u)\sec^{-1}\left(u\right))

uuu21\frac{u^{\prime}}{\left|u\right|\sqrt{u^2-1}}

12
New cards

d/dx (csc1(u)\csc^{-1}\left(u\right))

uuu21-\frac{u^{\prime}}{\left|u\right|\sqrt{u^2-1}}

13
New cards

1(a2u2)du\int\frac{1}{\sqrt{\left(a^2-u^2\right)}}du

arcsin(ua)+C\arcsin\left(\frac{u}{a}\right)+C

14
New cards

1u2+a2du\int\frac{1}{u^2+a^2}du

1aarctan(ua)+C\frac{1}{a}\arctan\left(\frac{u}{a}\right)+C

15
New cards

1uu2a2du\int\frac{1}{u\sqrt{u^2-a^2}}du

1aarcsec(ua)+C\frac{1}{a}\operatorname{arcsec}\left(\frac{\left|u\right|}{a}\right)+C