qm: probability trees and conditional expectations

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/9

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 10:23 AM on 4/30/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

10 Terms

1
New cards

E(X)E(X)

E(X)=i=1nP(Xi)XiE(X)=\sum_{i=1}^{n}P\left(X_{i}\right)X_{i}

2
New cards

σ2(X)\sigma^2\left(X\right)

σ2(X)=E[(XE(X))2]\sigma^2\left(X\right)=E\left\lbrack\left(X-E\left(X\right)\right)^2\right\rbrack

==i=1nP(Xi)(XiE(X))2==\sum_{i=1}^{n}P\left(X_{i}\right)\left(X_{i}-E\left(X\right)\right)^2

3
New cards

conditional expected values

E(XS)=i=1nP(XiS)XiE(X\vert S)=\sum_{i=1}^{n}P\left(X_{i}\vert S\right)X_{i}

4
New cards

total probability rule for the expected value

E(X)=E(XS)P(S)+E(XSc)P(Sc)E(X)=E\left(X\vert S)P\left(S)+E(X\vert S^{c}\right)P\left(S^{c}\right)\right.

5
New cards

total probability rule

P(A)=nP(ABn)P\left(A\right)=\sum_{n}^{}P\left(A\cap B_{n}\right)

6
New cards

bayes formula

P(eventinfo)=P(infoevent)P(info)P(event)P\left(event\vert info\right)=\frac{P\left(info\vert event\right)}{P\left(info\right)}P\left(event\right)

7
New cards
8
New cards
9
New cards
10
New cards