Mono and polysaccharides

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Last updated 5:59 PM on 4/26/26
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97 Terms

1
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How to find D and L stereochemistry of chiral compounds

R= D (put group on the right side of fischer projection)

S = L (put group on left side of fischer projection)

<p>R= D (put group on the right side of fischer projection)</p><p>S = L (put group on left side of fischer projection)</p>
2
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what stereochemistry do all naturally occuring sugars have?

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3
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Give the general equation for hemiacetal formation (starting from alcohol and aldehyde)

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4
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give the mechanism for acid catalysed hydrolysis of hemiacetal

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5
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give mechanism for the base catalysed hydrolysis of hemiacetal

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6
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what is the consequence of the aldehyde being able to rotate freely?

  • you end up with alpha beta mixtures

  • these have different physical and chemical properties

7
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<p>why do we only get attack from the red or blue OH on this chain? </p>

why do we only get attack from the red or blue OH on this chain?

  • as if the other OH were involved then the ring would be too small

  • thermodynamically favoured ring size is 5-6 membered.

8
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what do we get if we attack from the red OH

  • form a 5 mem furanose ring

  • alpha and beta

<ul><li><p>form a 5 mem furanose ring</p></li><li><p>alpha and beta</p></li></ul><p></p>
9
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what do we get if we attack from the blue OH?

  • 6 membered ring pyranose

<ul><li><p>6 membered ring pyranose</p></li></ul><p></p>
10
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<p>explain this graph</p>

explain this graph

<p></p><p></p>
11
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draw all axial and then all equatorial substituents around a cyclohexane ring

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12
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draw alpha D glucose and then beta D glucose

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13
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which are more preferred axial or equatorial?

equatorial

  • because 1,3 diaxial interactions are disfavoured

  • also to avoid gauche butane interactions

14
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<p>what are 1,2 eq substituents to eachother?</p>

what are 1,2 eq substituents to eachother?

  • trans

15
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<p>what are 1,2 eq/ax substituents to eachother?</p>

what are 1,2 eq/ax substituents to eachother?

  • cis

16
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draw the alpha D glucose and flip it to show all substituents

flipped chair = L configuration

<p>flipped chair = L configuration</p>
17
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<p>we see a preference for the beta equatorial position but only just. why?</p>

we see a preference for the beta equatorial position but only just. why?

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18
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what is the anomeric effect?

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19
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why does the anomeric effect occur? draw the 2 stabilising interactions

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20
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describe the small stabilisation that we see for an equatorial substituent on the ring

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21
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why are protecting groups useful?

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22
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<p>Annotate a- D glucose with the different functional groups </p>

Annotate a- D glucose with the different functional groups

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23
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what is an orthogonal set?

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24
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describe reagents/reaction for the protection of alcohol with OAc?

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25
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why do we NEED to use pyridine?

  • because OH nucleophile on its own is not nucleophilic enough

  • pyridine is used to generate a good electrophile

  • could also use ET3N

  • pyridine also works as a solvent

26
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draw the mechanism for alcohol to OAc

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27
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what is a con to acetate groups

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28
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why can acetate not move to the 3 position?

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29
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draw the mechanism for the reverse reaction of OAc to OH

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30
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Draw the mechanism for the addition of a benzoate group, what functional group does benzoate contain?

  • ester

<ul><li><p>ester </p></li></ul><p></p>
31
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draw a benzyl group and what functional group does it contain?

-ether

<p>-ether</p>
32
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<p>why can we not use BnBr alone? why is DMF used?</p>

why can we not use BnBr alone? why is DMF used?

  • must use NaH as BnBr on it own is not nucleophilic enough

  • DMF is a polar solvent used to solubilise the substrate

33
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<p>draw the mechanism for benzyl groups </p>

draw the mechanism for benzyl groups

  • forms an alkoxide which is now nucleophilic enough to attack BnBr

34
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why do we need different protecting groups?

  • so that we can selectively deprotect one in the presence of the other

35
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how can we deprotect only the anomeric carbon?

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36
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what is the purpose of using bulky ethers and give an example?

  • this is selective protection for primary alcohols ( very bulky and if u use 1 equiv then it will react with most reactive hydroxyl group)

  • example is OsiR3 or OTIPS

37
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how can we protect all the groups with bulky ethers?

by using an excess of OSiR3

38
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<p>draw the mechanism of bulky ether </p>

draw the mechanism of bulky ether

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39
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describe the purpose of using a TROC group?

— trichloroethylchloroformate is used to protect amines

40
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which are more reactive: amines or hemiacetals?

amines are more nucleophilic

41
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<p>describe the mechanism of amine protection with TROC</p>

describe the mechanism of amine protection with TROC

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42
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describe the mechanism of removing TROC from amine (reverse)

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43
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<p>draw the mechanism for deprotection via azide reduction</p>

draw the mechanism for deprotection via azide reduction

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44
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<p>is it vital to use pyridine for this reaction? why is this reaction not commonly used?</p>

is it vital to use pyridine for this reaction? why is this reaction not commonly used?

  • no because the amine is nucleophilic enough to directly attack the Ac2O group.

  • it deactivates the molecule

45
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How can we protect 1,2 diols

solvent = excess of carbonyl

acid catalysis = H+/ZnCl2 or TsOH

<p>solvent = excess of carbonyl </p><p>acid catalysis = H+/ZnCl2 or TsOH</p>
46
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how can we protect 1,3 diols?

  • same reactants as 1,2

<ul><li><p>same reactants as 1,2 </p></li></ul><p></p>
47
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what do we use for the reverse reaction for diol deprotection

  • aqueous dilute acid

48
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how to control whether we reacts a 1,2 diol vs a 1,3 diol?

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49
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how do cis diols and trans diols affect selectivity for diol protection?

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50
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<p>describe the protection of D-galactopyranose with acetonides</p>

describe the protection of D-galactopyranose with acetonides

  • prefers 1,2 diol

  • prefers eq/ax relationship

<ul><li><p>prefers 1,2 diol</p></li><li><p>prefers eq/ax relationship</p></li></ul><p></p>
51
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why does the OH at the anomeric prefer the axial position over the equatorial?

  • because we want to form the most thermodynamically stable product

  • we are using a ketone so it prefers ax/eq relationship

52
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<p>describe the protection of D-glucopyranose with acetonides and explain why it formed the 5 mem ring?</p>

describe the protection of D-glucopyranose with acetonides and explain why it formed the 5 mem ring?

  • forms the 5 membered furanose ring

  • because there arent many ax/eq relationship therefore to make more we can treat c4 OH and C5 OH as a 1,3 diol

<ul><li><p>forms the 5 membered furanose ring</p></li><li><p>because there arent many ax/eq relationship therefore to make more we can treat c4 OH and C5 OH as a 1,3 diol</p></li></ul><p></p>
53
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why does it form the 5 membered ring and not the 6 membered ring ?

  • hemiacetals are always in equilibrium with other species so finding axial/equatorial relationships pushes equilibrium towards forming furanose over pyranose

<ul><li><p>hemiacetals are always in equilibrium with other species so finding axial/equatorial relationships pushes equilibrium towards forming furanose over pyranose</p></li></ul><p></p>
54
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what are the reagents for the reverse reaction (deprotection of acetonides)?

  • H3O+

55
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how can we selectively deprotect certain acetals?

  • you always hydrolyse the most accessible acetyl

  • the one on the anomeric is less accessible compared to others at the primary position

  • so for this use H3O+ (acetic acid and water at RT)

  • this is mild acid hydrolysis

56
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how to deprotect all acetals?

  • you can use acetic acid and water but must leave for reflux and long time

  • you can use H2SO4 and HCL (much stronger acids)

57
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<p>how to protect 1,3 diols to form benzylidene acetals?</p>

how to protect 1,3 diols to form benzylidene acetals?

  • use bulky aldehyde and lewis acid

<ul><li><p>use bulky aldehyde and lewis acid </p></li></ul><p></p>
58
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<p>why does this reaction selectively protect 4,6 </p>

why does this reaction selectively protect 4,6

  • aldehydes prefer to form the transdecalin ring so that the phenyl group can be in the equatorial position

<ul><li><p>aldehydes prefer to form the transdecalin ring so that the phenyl group can be in the equatorial position</p></li></ul><p></p>
59
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<p>why do form the 6 membered ring and not the 5 membered ring for this reaction </p>

why do form the 6 membered ring and not the 5 membered ring for this reaction

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60
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what is the general scheme for glycosylation reaction?

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61
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what is the role of a counter ion?

  • it helps stabilise the oxocarbenium ion

62
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what are the problems associated with glycosylation reactions?

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63
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what properties should a good leaving group have?

  • easily introduced

  • stable when required

  • selectively activated

64
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give examples of different leaving groups for glycoslyation

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65
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give the mechanism for glycosylation

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66
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why is it easier to make 1,2 trans glycosides compared to 1,2 cis ?

  • 1,2 trans has groups further apart so easier for the nucleophile to come in and no sterics in the way

67
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what is neighbouring group participation ?

  • groups which help to activate the leaving group

<ul><li><p>groups which help to activate the leaving group</p></li></ul><p></p>
68
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<p>explain how we can form beta-glycosides using ester neighbouring group participation?</p>

explain how we can form beta-glycosides using ester neighbouring group participation?

  • alcohol nucleophile is poor so ester can attack intramolecularly instead at the anomeric carbon.

  • this form the 1,2 trans ring as it is favoured (eq/ax) - stabilised carbocation

  • this allows the nucleophile to attack and as axial position is occupied, equatorial formation is very favoured

  • the only exception is if the ester group is axial first

<ul><li><p>alcohol nucleophile is poor so ester can attack intramolecularly instead at the anomeric carbon. </p></li><li><p>this form the 1,2 trans ring as it is favoured (eq/ax) - stabilised carbocation</p></li><li><p>this allows the nucleophile to attack and as axial position is occupied, equatorial formation is very favoured</p></li><li><p>the only exception is if the ester group is axial first</p></li></ul><p></p>
69
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<p>explain how we can form alpha glycosides using chiral auxillary control?</p>

explain how we can form alpha glycosides using chiral auxillary control?

  • SPh is very nucleophilic so is able to attack the anomeric carbon and forms the transdecalin chair

  • this blocks the equatorial face with a bulky group allowing for alpha product

  • Ph must be starting from S configuration

<ul><li><p>SPh is very nucleophilic so is able to attack the anomeric carbon and forms the transdecalin chair </p></li><li><p>this blocks the equatorial face with a bulky group allowing for alpha product</p></li><li><p>Ph must be starting from S configuration</p></li></ul><p></p>
70
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how does this favour beta glycosides?

if Ph group is (R) then cisdecalin would form

<p>if Ph group is (R) then cisdecalin would form</p>
71
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what is in-situ anomerisation?

  • another way of making alpha glycosides (1,2 cis)

72
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what are the requirements for in-situ anomerisation

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73
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<p>describe how in-situ anomerisation works</p>

describe how in-situ anomerisation works

  • allows for the formation of equilibria between alpha and beta monomers

  • beta anomer is more reactive as due to the anomeric effect the equatorial bromide must flip to form the boat conformation for stability.

  • the boat conformation isnt stable compared to the chair which allows it to react faster with the nucleophile (R-OH) forming more of the alpha glycoside

74
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when can we use solvent effects for alpha and beta selectivity?

  • when we are limited by the number of protecting groups we can use

75
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How can we use solvent effects to favour formation of alpha glycosides? draw the mechanism

-ethers

but we get a mixture not pure selectivity

<p>-ethers </p><p>but we get a mixture not pure selectivity </p>
76
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How can we use solvent effects to favour beta formation? draw the mechanism

acetonitrile

<p>acetonitrile</p>
77
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which leaving group is better and why? OAc or Br?

  • Br as it is more electrowithdrawing

78
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how to form an activated glycoside using glycosyl halides on OAc? draw the mechanism

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79
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why does glycosyl halide form the axial glycoside?

  • In the presence of alot of acid you get the thermodynamic product due to the anomeric effect

  • if u quench the reaction after 5 minutes then you get a mixture of alpha and beta due to neighbouring group participation

80
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how to form an activated glycoside using glycosyl halides on OBn? draw the mechanism

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81
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why do we have to put the Br group on last?

  • once Br group is attached than you cant modify the rest of the OAc groups as Br is too reactive of a leaving group therefore we must put on other protecting groups first.

82
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How can we activate the Br leaving group?

  • using silver salts

<ul><li><p>using silver salts </p></li></ul><p></p>
83
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draw mechanism for activating Br

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84
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How to activate glycosides with trichloroacetimidates?

  • uses base (depending on this we can form alpha or beta)

  • then uses lewis acid

<ul><li><p>uses base (depending on this we can form alpha or beta)</p></li><li><p>then uses lewis acid</p></li></ul><p></p>
85
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draw the mechanism of lewis acid BF3.OET2 to form the beta glycoside

  • forms via sn1 reaction, although some strong nucleophiles can react via sn2 reaction

  • forms via oxocarbenium ion (on the slide)

<ul><li><p>forms via sn1 reaction, although some strong nucleophiles can react via sn2 reaction</p></li><li><p>forms via oxocarbenium ion (on the slide)</p></li></ul><p></p>
86
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<p>what are pros of using thioglycosides</p>

what are pros of using thioglycosides

  • able to generate mixed acetals which are stable to acid and base so we can do protecting group manipulations

87
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draw the activation mechanism for thioglycosides

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88
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draw the promoter source I+ from NIS/TfOH

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89
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<p>describe the mechanism for the formation of glycosyl sulfoxides with mcpba and the mechanism of activation with Tf2O</p>

describe the mechanism for the formation of glycosyl sulfoxides with mcpba and the mechanism of activation with Tf2O

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90
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why is formation of glycosyl sulfoxides formed at -78 degrees?

  • requires low temps as sulfoxides are very reactive

91
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how can we use pentenyl glycosides for activated glycoside

  • use activation to form I+

  • I+ reacts with double bonds only (nothing else in the molecule will react)

92
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draw the mechanism of pentenyl glycosides

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93
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what does armed and disarmed glycosides describe?

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94
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what are disarmed glycosides?

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95
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what are armed glycosides?

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96
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why is the lower reactions faster?

  • has EDG

  • EWG pulls electron density away so slower

<ul><li><p>has EDG </p></li><li><p>EWG pulls electron density away so slower</p></li></ul><p></p>
97
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between BnO and BzO which forms faster reaction?

BnO (benzyl ether) as its EDG