Given as <x(t), y(t)>, keep separate, 1st derivative is velocity 2nd derivative is acceleration
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Taylor Polynomials
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MacLaurin Polynomials
Taylor polynomial centered at x=0 (a=0 in equation)
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Lagrange Error Bound
M is the max value of the (n+1)st derivative
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FTC 1
top minus bottom, remember indefinite integrals have a +C term
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Integration- if the derivative of the bottom is on the top
General solution: “ln of the absolute value of x + C”
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Other techniques of integration (there are 8)
is the derivative of the bottom on the top, is the derivative of the inside next to it, can you split it into fractions (single term in denominator), can you expand it, can you use synthetic/long division, can you use the rules of logs to simplify, can you use trig substitution, u-substitution
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Integration by parts
“uv minus the integral of vdu (think voodoo)”, remember LIATE for assigning u values
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LIATE
Logs
Inverse Trig
Algebraic
Trig functions
Exponential
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Integration of powers of sin and cos
Remember: sin^x + cos^x = 1
\- If the power of one is odd and positive, save one of those terms and convert the rest to the other term
\ Remember: sin^2(x) = \[1-cos(2x)\]/2,
cos^2(x) = \[1+cos(2x)\]/2
\-Use these identities if both terms exponents are even and positive
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Integration of powers of tan and sec
Remember info in pic!
A lot of trial and error
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Method of partial fractions
factor denominator, split fraction into two parts, cross multiply, solve for A and B, then plug back into the fractions and integrate
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Exponential Growth and Decay (differential equations)
“the rate of change of Y is proportional to Y”, dy/dt=ky, y=Ce^(kt) where C is the starting value
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“Other” Exponential Growth and Decay (differential equations)
“the rate of change of Y is proportional to BLANK”, dy/dt = (get from word problem) y = use separation of variables
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Newton’s Law of Cooling (differential equations)
“the rate of cooling of an object is proportional to the difference between the object’s temp and room temp”, dT/dt = k(T0 - Ts) where Ts is a constant representing room temp and T0 is initial temp, T = (T0-Ts)e^kt + Ts
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Logistics Growth (differential equations)
“rate of change of y is proportional to y and the difference between the upper limit, L, and y”, dy/dt=ky(L-y), y=L/\[1+Ce^(-kLt)\]