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Peanut butter is falling out of every orifice. I'm sorry. That was a bit personal.
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addition
adding two groups on either side of a double bond (opposite of elimination)
hydrohalogenation
a hydrogen and halogen are added across a double bond.
markovnikov product
Non-hydrogen group bonds to the MORE substituted alkene carbon.
anti-markovnikov product
Non-hydrogen group bonds to the LESS substituted alkene carbon.
markovnikov addition of H&X
H bonds to less substituted carbon to make the carbocation more stable.
X = halogen
Exception: HBr + ROOR = anti-markovnikov product.

H2O addition
H and OH are each added across a double bond, which makes an alcohol.
Reagents:
Dilute H3O+ or H2O + H2SO4 for alkene to alcohol.
Concentrated H3O+ or H2O + H2SO4 for alcohol to alkene.
Acid catalyzed hydration mechanism

acid catalyzed addition of alcohols
adds an ether, rearrangement is possible, markovnikov addition, can be syn or anti.

Oxymercuration-demercuration
markovnikov, rearrangement is not possible, can by syn or anti.
Reagents: Hg(OAc)2 + H2O + THF + NaBH4
hydroboration oxidation
results in syn addition of H and OH, anti-markovnikov, no rearrangement possible.
Reagents: BH3 + THF and H2O2 + NaOH

H2O addition reaction comparison

halonium ion

Dihalogenation
alkene to vicinal dihalide (2 halogens connected to adjacent carbons), results in anti addition. A holonium is the intermediate. It gives both enantiomers.
Reagents = X2 and CCl4. X = any halogen

Halohydrin formation
alkene to halohydrin (OH on one side, halogen on the other), gives both enantiomers with anti addition. OH bonds to the more substituted carbon, and a halonium is the intermediate.
Reagents: X2 and H2O

epoxide
reactive and unstable

epoxide formation
start with an alkene, and use RCO3H or mCPBA as the reagent, and the epoxide can form on either side of the alkene.

anti dehydroxylation
start with an alkene and use 1: RCO3H and 2: H3O+ or NaOH. It makes a vicinal diol (2 OH on neighboring carbons) with anti addition and an enantiomer.

anti dehydroxylation mechanism

syn dehydroxylation
start with alkene, then use OsO4 + H2O2 as reagents or KMnO4 + NaOH + cold as reagents, and 2x OH do syn addition with an enantiomer.

epoxidation and dihydroxylation summary

ozonolysis cleavage
alkene is cut down the middle to make two carbonyl containing compounds.
Reagents:
1: O3
2: H2O2 for oxidative (carboxylic acid or carbon dioxide)
2: DMS or Zn,HOAc for reductive (aldehyde or formaldehyde)
Fully substituted: makes two ketones
Non-fully substituted: makes an aldehyde if DMS or Zn,HOAc, or a carboxylic acid if H2O2.
Terminal alkene: terminal side makes a formaldehyde if DMS or Zn,HOAc, or carbon dioxide if H2O2.

catalytic hydrogenation
2 hydrogens are added to bring an alkene to an alkane
Reagents: 1: H2, 2: Pt or Pd/C
Results in syn addition

Elijah’s cleavage
