HON Geometry Topics 1-3 Study Guide Flashcards

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Flashcard study set covering topics 1 through 3 in HON Geometry including line/angle relationships, triangle theorems, parallel lines, and transformations.

Last updated 12:01 PM on 9/29/26
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32 Terms

1
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Equilateral Triangle

A triangle in which all three sides and all three interior angles are congruent (60∘60^\circ each).

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Isosceles Triangle

A triangle with two congruent sides; the interior angles opposite these sides are also congruent.

3
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Scalene Triangle

A triangle with no congruent sides or angles, where the largest angle opens up to the largest side.

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Supplementary Angles

Two angles whose measures add up to 180∘180^\circ.

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Complementary Angles

Two angles whose measures add up to 90∘90^\circ.

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Linear Pair

A pair of adjacent angles whose non-common sides form a straight line, making them supplementary (sum=180∘\text{sum} = 180^\circ).

7
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Vertical Angles

A pair of non-adjacent opposite angles formed by two intersecting lines; vertical angles are congruent.

8
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Exterior Angle Theorem

The measure of an exterior angle of a triangle equals the sum of the measures of its two remote interior angles.

9
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Corresponding Angles

Angles in matching positions relative to two lines and a transversal; they are congruent when the lines are parallel.

10
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Alternate Interior Angles

Angles on opposite sides of the transversal and inside two parallel lines; alternate interior angles are congruent.

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Alternate Exterior Angles

Angles on opposite sides of the transversal and outside two parallel lines; alternate exterior angles are congruent.

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Consecutive Interior Angles

Angles on the same side of the transversal and inside two parallel lines; consecutive interior angles are supplementary (sum=180∘\text{sum} = 180^\circ).

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Translation Rule

A transformation that slides every point of a figure by the same distance and direction, represented algebraically as (x,y)→(x+a,y+b)(x, y) \rightarrow (x + a, y + b).

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Reflection across the x-axis

A geometric transformation that flips a figure over the x-axis, mapping coordinate points according to (x,y)→(x,−y)(x, y) \rightarrow (x, -y).

15
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Reflection across the y-axis

A geometric transformation that flips a figure over the y-axis, mapping coordinate points according to (x,y)→(−x,y)(x, y) \rightarrow (-x, y).

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Reflection across line y = x

A geometric transformation that flips a figure across the line y=xy = x, mapping coordinate points according to (x,y)→(y,x)(x, y) \rightarrow (y, x).

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Reflection across line y = -x

A geometric transformation that flips a figure across the line y=−xy = -x, mapping coordinate points according to (x,y)→(−y,−x)(x, y) \rightarrow (-y, -x).

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Rotation 180∘180^\circ about the origin

A transformation turning a figure 180∘180^\circ around the origin, mapping coordinate points according to (x,y)→(−x,−y)(x, y) \rightarrow (-x, -y).

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Rotation 90∘90^\circ clockwise about the origin

A transformation turning a figure 90∘90^\circ clockwise around the origin, mapping coordinate points according to (x,y)→(y,−x)(x, y) \rightarrow (y, -x).

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Rotation 90∘90^\circ counterclockwise about the origin

A transformation turning a figure 90∘90^\circ counterclockwise around the origin, mapping coordinate points according to (x,y)→(−y,x)(x, y) \rightarrow (-y, x).

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<p>Problem 1 Solution (Value of $$x$$)</p>

Problem 1 Solution (Value of xx)

x=22x = 22. The two angles form a right angle (90∘90^\circ), so 3x+(x+2)=903x + (x + 2) = 90.

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<p>Problem 2 Solution (Value of $$x$$)</p>

Problem 2 Solution (Value of xx)

x=15x = 15. The angles form a linear pair (180∘180^\circ), so 87+(6x+3)=18087 + (6x + 3) = 180.

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<p>Problem 3 Solution (Value of $$x$$)</p>

Problem 3 Solution (Value of xx)

x=41x = 41. Vertical angles are congruent, so 2x+1=832x + 1 = 83.

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<p>Problem 6 Solution (Value of $$x$$)</p>

Problem 6 Solution (Value of xx)

x=−4x = -4. The sum of interior angles in a triangle is 180∘180^\circ, so 71+73+(x+40)=18071 + 73 + (x + 40) = 180.

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<p>Problem 7 Solution (Value of $$x$$)</p>

Problem 7 Solution (Value of xx)

x=−4x = -4. By the Exterior Angle Theorem, (x+129)=(180−105)+50=125(x + 129) = (180 - 105) + 50 = 125.

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<p>Problem 8 Solution (Value of $$x$$)</p>

Problem 8 Solution (Value of xx)

x=7x = 7. In an isosceles triangle, base angles are equal: m∠2=180−1002=40∘m\angle 2 = \frac{180 - 100}{2} = 40^\circ. Solving 4x+12=404x + 12 = 40 gives x=7x = 7.

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<p>Isosceles Base Angle Problem (Value of $$x$$)</p>

Isosceles Base Angle Problem (Value of xx)

x=11x = 11. Base angles are congruent (m∠2=43∘m\angle 2 = 43^\circ). Solving 3x+10=433x + 10 = 43 yields x=11x = 11.

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<p>Isosceles Triangle Side Problem (Value of $$x$$)</p>

Isosceles Triangle Side Problem (Value of xx)

x=8x = 8. Sides opposite congruent angles are equal, so 2x−5=112x - 5 = 11.

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<p>Isosceles Vertex Angle Problem (Value of $$x$$)</p>

Isosceles Vertex Angle Problem (Value of xx)

x=82x = 82. The base angles are both 49∘49^\circ, so x=180−2(49)=82x = 180 - 2(49) = 82.

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<p>Problem 13 Solution (Value of $$x$$)</p>

Problem 13 Solution (Value of xx)

x=8x = 8. Alternate interior angles are congruent, so 15x+10=13015x + 10 = 130.

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<p>Problem 14 Solution (Value of $$x$$)</p>

Problem 14 Solution (Value of xx)

x=3x = 3. Corresponding angles are congruent, so 13x−4=8+9x13x - 4 = 8 + 9x.

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Supplementary Angle Difference Problem

Two supplementary angles that differ by 98∘98^\circ measure 41∘41^\circ and 139∘139^\circ.