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State the distance formula in R3 (Theorem 1) and its special case from the origin.
If P=(a1,b1,c1) and Q=(a2,b2,c2), the distance between P and Q is
∣P−Q∣=(a2−a1)2+(b2−b1)2+(c2−c1)2
Special case: Q=O=(0,0,0) and P=(a,b,c) gives
∣OP∣=a2+b2+c2
Give the equations of planes parallel to the coordinate planes.
xy-plane: {(x,y,0):x,y∈R}, equation z=0.
Plane parallel to the xy-plane: {(x,y,c):x,y∈R}, equation z=c.
Similarly:
x=a is a plane parallel to the yz-plane.
y=b is a plane parallel to the xz-plane.
Give the set description and equation of a sphere.
A sphere centered at Q=(a,b,c) with radius R:
{(x,y,z):(x−a)2+(y−b)2+(z−c)2=R2}
Equation: (x−a)2+(y−b)2+(z−c)2=R2.
Give the equation of a right cylinder in R3, and compare it with a circle in R2.
A right cylinder in R3 has radius R and central axis the vertical line through (a,b,0).
R is the distance between the point (x,y,z) and that vertical line (the closest point on the line is (a,b,z)).
Set: {(x,y,z):(x−a)2+(y−b)2=R2}.
Equation (for 3D space): (x−a)2+(y−b)2=R2.
Compare: a circle in R2 with radius R and center (a,b) is {(x,y):(x−a)2+(y−b)2=R2}. It is the same equation but for 2D space, with only two coordinates.
How do vectors in 3-space work (components, length, addition, scalar multiplication)?
Geometrically it is almost the same as 2D, but pictures are harder to draw.
Algebraically there are just 3 coordinates/components.
For P=(a1,b1,c1) and Q=(a2,b2,c2):
Vector: PQ=⟨a2−a1,b2−b1,c2−c1⟩ (these are the components).
Length: ∥PQ∥=(a2−a1)2+(b2−b1)2+(c2−c1)2.
For v=⟨v1,v2,v3⟩, w=⟨w1,w2,w3⟩ and λ∈R:
Addition: v+w=⟨v1+w1,v2+w2,v3+w3⟩.
Scalar multiplication: λv=⟨λv1,λv2,λv3⟩.
Define parallel vectors in 3-space and the standard basis i,j,k. How do you write any vector in terms of it?
Parallel: non-zero v,w are parallel if there exists λ∈R with v=λw.
Standard basis in R3: i=⟨1,0,0⟩, j=⟨0,1,0⟩, k=⟨0,0,1⟩.
Any vector in R3 is a linear combination of i,j,k:
⟨a,b,c⟩=⟨a,0,0⟩+⟨0,b,0⟩+⟨0,0,c⟩=ai+bj+ck
How do you describe a general curve in 3D space with a parametric equation?
For a point P on the curve, write r=OP.
Parametric equation: r=r(t)=⟨x(t),y(t),z(t)⟩, or equivalently the system
x=x(t),y=y(t),z=z(t)
The notes’ picture marks points on the curve at t=0 and t=1 (position vectors r(0) and r(1) from O).
Give the equation of a line through a point P=(x0,y0,z0) with direction v=⟨a,b,c⟩. Show how it is derived.
Derivation: for a point Q=(x,y,z) on the line, the vector from the base point to Q is parallel to v. So there is t∈R with (vector from base point to Q) =tv. (The notes write this vector as PP0, which is presumably the vector between the base point and Q.) Thus
⟨x−x0,y−y0,z−z0⟩=t⟨a,b,c⟩
Vector form: ⟨x,y,z⟩=⟨x0,y0,z0⟩+t⟨a,b,c⟩.
Writing r=OQ: r(t)=OP+tv.
Parametric (scalar) form:
x=x0+at,y=y0+bt,z=z0+ct
Give the equation of the line through two points P=(a1,b1,c1) and Q=(a2,b2,c2).
Take the direction v=PQ=⟨a2−a1,b2−b1,c2−c1⟩.
Equation of the line: r(t)=OP+tPQ.
Component form: r(t)=⟨a1,b1,c1⟩+t⟨a2−a1,b2−b1,c2−c1⟩.
Parametric form:
x=a1+(a2−a1)t,y=b1+(b2−b1)t,z=c1+(c2−c1)t