Physics ig

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Kinetic energy

1/2mv²

Kinetic energy of a particle

p^2 /2m

Horizontal velocity

Vx=V0 cos(theta)

At peak trajectory, a balls vertical component of velocity is

0

𝐅net

𝑚⁢(𝑑⁢v/𝑑⁢𝑡)

dWnet

Fnet•dr

𝑑⁢𝑊net(extended)

𝑚⁢(𝑑⁢𝐯/𝑑⁢𝑡)·𝑑⁢r

Horizontal surface

Normal force=mg

Frictional force

mew static kinetic*Fn

Fnet

ma

d

(½)*a of x*t^2

Horizontal velocity (Component)

v of x=a of x*t

Instantaneous Power

P=f of x*v of x

Horizontal pulling force

Fnet=F-Frictional force

Horizontal work force

Horizontal pulling force*distance

Frictional force work

Wf=-Ff*d

Wnet

Fnet * d

Horizontal component of force

F of x=F*cos(theta)

Horizontal acceleration

a=F of x/m

Work energy theorem

the net work done on an object is strictly equal to its change in kinetic energy

Newtons second law applies to

the motion of the center-of-mass of the object

Rotational Kinetic Energy

K=1/2(Sum of m*v²)*w²

Tangential speed

v of i=2pi*r of i

Ktr

1/2(sum of m of i * v of i²)

rot kinetic energy

K=1/2(I)*w²

Moment of inertia

(sum of m of i* r of i²)

Angular velocity

w=the limit as change in time approaches 0 of change in d over change in t