1/78
Looks like no tags are added yet.
Null hypothesis
assumes data will fit into given ratio
no difference between observed and expected
any difference is by chance
Can never be proven, only supported
fail to reject = support
Chi square
goodness of fit
influence of chance on data
whether data is consistent with model
Too different to not be by chance? = null rejected
Due to random fluctuations = fail to reject null
P-value
significant differences between datasets
frequently 0.05 → 5% you would observe same variation or greater
greater than 0.05 = fail to reject
less than 0.05 = reject null
Chi square equation
= sum of (o-e)2/e
Linkage
genes (alleles) on the same chromosome are likely to be inhereited together
linked genes
two genes on a single pair of homologs; exchange occurs between two nonsister chromatids
Linkage group
set of linked genes
on chromo 4 = linkage group
Genetic map
shows the order of linked genes and distances between genes on a chromosome
constructed based on recombination frequency between genes of interests observed during test crosses
The further apart two genes are
the more likely recombination will occur
happens every meiosis cycle
lots of space for crossing over
OR
two genes have less space between them and are unlikely to be separeted by crossing over
Frequency of recombination measured by
Determine the distance between genetic markers or physical markers and construct a map
test cross with F1 heterozygotes with homo recessive
two genes? two point cross
classify F2 as recombinant or parental
Physical marker
phenotype associated with a gene locus
Genetic marker
DNA sequence, such as SNP or repeat
Recombinant progeny
progeny that is different than parental
parental is vice versa
Distance of genes on a map formula
(number of recombinants / total progeny) (100)
Double crossover (DCO)
Double crossover occurs when two chiasmata form and there is a double exchange between two nonsister chromatids
The expected frequency of DCO gametes is much lower than
that of either single crossover gamete class
Three point test cross likelihoods
progeny in the lowest abundance are DCO recombinants
Progeny in the highest abunadance are parental
progeny intermediate in their abundance are single crossover recombinants
Distance between genes steps
order of genes
reorganize to gene order
MU for first two genes
MU for second two units
Genotypic sex determination
due to specific DNA sequences
Genic balance
ratio of sex chromosomes to autosomes controls the amount of sex determining gene products
Chromosome determination
whether specific gene product(s) encoded in a sex chromosome are present or absent; presence or absence of a sex chromosome
Mating-type determination
expression of gene variants called idiomorphs control mating type (in some haploid microbes)
Environmental sex determination
signals from environment
ex: day length, temperature, social cues
Y chromosome determination in humans
XX causes gonads to develop into ovaries and produce eggs
WT biological female
XY causes gonads to develop into testes and produce sperm
WT biological male
Y chromosome pieces
PAR = Psuedoautosomal region
SRY = Sex determining region Y
MSY = Male specific region of the Y
Genes present on X and Y chromosomes
many linked genes do not influence sex development
Most sex linked genes are X linked because Y doesn’t contain many genes
X linked recessive inheritance
More frequently observed in males
Males are hemizygous for genes on X chromosome
No second allele to compensate for recessive allele
Females express the trait when they are homozygous for the allele
Female heterozygotes are carriers
Barr bodies are inactive X chromosomes
During blastocyst stage, an X is deactivated in XX mammals
Barr body is made of heterochromatin
A form of imprinting
monoalleleic expression → gene dosage compensation
equal amounts of X linked expression betwen males and females
Number of Barr bodies in somatic cells
all X chromosomes except one are deactivated
Barr body formed through lyonization
Involves XIST gene on X chromosome
Weakly expressed from both X chromosomes
During early development, one XIST gene copy is silenced
This X chromosome becomes the active X chromosome
Other X chromosome continues to express XIST and becomes the Barr body
XIST encodes a long non-coding RNA (lncRNA)
Coats chromosome and recruits epigenetic machinery (DNA methyltransferases and HDAC) to pack up the chromosome
Mosaicism

Multiple alleles
Most genes have >2 alleles in a population
A single diploid can have up to 2 alleles for a given gene
New alleles arise through mutation
hierarchy of dominance ex: the three eye colors of flies,
red-most
eosin-mid
white-least
Calculating the number of possible genotypes in a population
n = number of alleles
possible genotypes are (n)(n+1) / 2
Codominance
Heterozygotes simultaneously show the phenotypes that would be seen in the homozygotes
In a heterozygote, the two phenotypes resulting from both alleles can be observed
no blend
Molecular explanation of codominance
Equal amounts of gene product from both alleles
Both alleles are expressed and have equal activities
Gene products don’t interfere with each other
Incomplete dominance
One allele is not completely dominant to the other
blend is present
Molecular explanation of incomplete dominance
Varies from trait to trait
Can be dependent on gene dosage
Homozygosity for functional allele causes two doses of the gene product
Heterozygosity causes one dose
Homozygosity for the null allele no dose
Pleiotropy
single gene, multiple phenotypes
PKU
Molecular explanations
Promiscuous protein has more than one function
Cell-specific effects of protein variants
Essential gene
gene product required for life of cell/organism
No compensating gene or gene with redundant function to take its place
When mutated in a way that changes the function of the gene product, a lethal allele results
Lethal allele
presence results in death of organism
A.k.a. deleterious allele
Different than a null allele, although a lethal allele can also be a null allele
Polygenic traits
Multiple genes contribute to a trait
Most traits result from the combinatorial action of multiple alleles of multiple genes
Example: lots of genes encode growth factors and growth factor receptors to influence human height
Example: autism
Coat color in mice
Eye color
Epistasis
two genes involved
form of gene interaction in which one gene interferes with the expression of another gene
epistatic gene supresses the phenotype from the hypostatic gee
Extranuclear Inheritance
Transmission of information to offspring occurs through something in the cytoplasm
phenotype not caused by own nuclear genome
non-medelian
Varieties in extranuclear inheritance
Organelle heredity - mt and cp
maternal effect - RNA and proteins in cytoplasm of egg
infectious heredity - DNA from microbes and viruses
Organelle heredity
Ancient eukaryotic cell engulfed prokaryotic cell (endosymbiotic theory)
Ability to make more energy was selected
Engulfed cell eventually became the mitochondria or chloroplast
Mitochondria split by fission
Cells have lots of mitochondria (not just one)
Progeny cells inherit mitochondria and therefore mtDNA from the parent cell during cell division
Number of mitochondria vary from cell to cell
Cells with high energy demands (muscle, neurons) have more mitochondria per cell
Organelle heredity in mammals, yeast, and plants
mtDNA inherited from female parent via the egg
sperm mitochondrai is degraded
Fungus
inhereited from both parents bc both cells fuse
Plants
cp varies
Heteroplasmy
mitochondria or chloroplasts from different sources and/or of varying genotypes
mixture of mito/cp from both parents
mixture of mito/cp genotypes within a cel or within a multicellular organism due to mutation
Molecular organization of mitochondria (mtDNA)
DNA in mito is unlike DNA in nucleus of euk cells that house these organelles
circular
no histone or introns
few gene products encoded
most RNAs and proteins found in mito are encoded in nucleus
mtDNA mutations
Damage due to
ROS
No protection from histones
DNA repair is limited
in nuclear genome
Used to trace ancestry (maternal haplogroup)
Mutations can cause human disease
Maternal effect
offspring phenotype is under control of nuclear gene products present in egg
nuclear genes of female gamete transcribed; gene products accumulate in egg cytoplasm
products are given to newly formed cells, influencing patterns and traits establshd in ealy development
Polarization
which side of embryo will be posterior or anterior
Testcross
cross genotype with homozygous recessive (tester)
3 point testcross steps
order of genes
distance between first two
distance between other two
Limits to genetic maps
DCO do not happen as often as predicted because of interference
One chiasma inhibits formation of another chiasma
Crossing over doesn’t occur at random.
Chromosomes have recombination hot and cold spots
Sometimes a DCO event can look like the parental phenotype, skewing the data
The farther apart two genes are, the greater the probability that undetected double crossovers will occur
Unrealistic to use the same methods as model organisms
ethics, takes a long time, low sample size
Can do: Analyze DNA markers (SNPs, microsatellites) using positional cloning, DNA arrays, and genome sequencing
Aneuploid conditions
45, XO (Turner syndrome) are female
47, XXY (Klinefelter syndrome) are male
Sex reversal conditions
46, XY females with deletion of the Y chromosome
46, XX males had a small piece of Y attached to X
Same chromosome region involved in both cases
Hypothesis: The chromosome region translocated in both XY females and XX males is
essential for an individual to develop testes
SRY discovered using transgenic mice
Experiment: Equivalent region from mouse was introduced into XX mouse embryos.
Controls: Untreated XY and XX littermates
Result: Male sexual development in XX mice.
Conclusion: SRY is required for male testes development.
The effect of SRY in mammalian sex
SRY is expressed about 6-8 weeks after fertilization
Activates SOX9 gene expression
controls the expression of genes involved in testes development
Represses WNT4 gene expression
signaling protein that activates ovary development via B-catenin pathway
Which statement best describes wild-type human sex determination?
Females are heterogametic.
Individuals with a Y chromosome are male.
Individuals with two X chromosomes are female.
Individuals with at least twice as many X chromosomes as Y chromosomes are female.
Individuals with one X chromosome are male.
Individuals with a Y chromosome are male.
A karyotype is done on an individual who has ovaries and no testes, and it is discovered that they are XY. However, the Y chromosome appears to have a deletion. What region is most likely deleted?
PAR
SRY
centromere
MSY
heterochromatin of MSY
SRY
X linked recessive inheritance proportions
What proportion of the sons of an affected XX mother would show the trait?
What proportion of the sons of a carrier XX mother would show the trait?
What proportion of XX daughters would show the trait from an affected XX mother and unaffected XY father?
100%
50%
0%
A young XY boy is diagnosed with hemophilia A, a recessive, X-linked condition. If neither parent has hemophilia A, what are their probable genotypes?
XAXa, XAY
XAXA, XaY
XaXa, XAYA
Mother could be either XAXA or XAXa, but father is XaY
cannot predict from the information given
XAXa, XAY
X-linked dominant inheritance
If the XX mother is heterozygous and XY father is unaffected, what proportion of their XY sons will be affected? XX daughters?
If the XX mother is unaffected but the XY father is affected, what proportion of their XX daughters will be affected? XY sons?
50% and 50%
All daughters, no sons
What does mosaic mean in genetics? How is it related to XX mammals?
Cells within mutlicellular organisms have different genotypes
2 ways
new mutation during development in a cell
Bar bodies in XX females
Colorblindness is an X-linked, recessive trait. The XY father of a family is colorblind while the XX mother has wild-type color vision and has no family history of colorblindness. Their XX daughter displays mild color perception deficits. What might explain her phenotype?
She is homozygous for the mutant allele
She is a mosaic
She is intersexed
She has a de novo mutation in the photoreceptors
She is hemizygous for the mutant allele
She is a mosaic
Which of the following describes Lyonization as a process?
Barr bodies are inactivated X chromosomes.
The paternal X chromosome of a female is inactivated in an early embryonic stage.
The maternal X chromosome of a female is inactivated in an early embryonic stage.
One of the two female X chromosomes is randomly inactivated in an early embryonic stage.
As a child grows, each cell of a female randomly inactivates one X chromosome shortly after mitosis.
One of the two female X chromosomes is randomly inactivated in an early embryonic stage.
A male observed his stained epithelial cells and saw a Barr body. If a karyotype was performed on his cells, what would you expect to see? Choose all that apply.
46, XY
46, XX
47, XXY
47, XYY
47, XXY
Drosophila melanogaster, like humans, have X and Y chromosomes so that XX is female and XY is male. However, unlike humans, it is the ratio of the number of X chromosomes to sets of autosomes that determines the sex of the fly. A fly has one X chromosome, two sets of autosomes (a diploid set), and no Y. What is its predicted sex?
male
female
intersex
male
You observe the cells and karyotypes of a novel species of mammal found on an island. No females have a Barr body; however, they all have two X chromosomes. Males have one X and one Y chromosome. Considering dosage compensation, which of the following would you predict?
Males transcribe their X at twice the rate of a female X.
Males transcribe their X at half the rate of a female X.
Females transcribe their X at twice the rate of a male X.
Transcription rates would not be affected.
Males transcribe their X at twice the rate of a female X.
Xist lncRNA plays a crucial role in X inactivation. The Xist RNA coats the X chromosome that produced it, and whichever X has more Xist, it becomes the inactive X. If a mutation inactivated Xist on only one chromosome, what would you predict to occur?
The mutant chromosome would always be inactivated.
The mutant chromosome would always be active.
Both chromosomes would be inactivated.
Both chromosomes would be active.
The wild-type Xist would compensate for the mutant, and X inactivation would proceed normally.
The mutant chromosome would always be active.
Slide 48