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What is the pentose phosphate pathway (PPP)
Glucose enters glycolysis and is converted into glucose-6-phosphate (G6P)
G6P doesn’t HAVE to continue through glycolysis and can be redirected into the PPP which is also known as the hexose monophosphate shunt
The cell does this because sometimes it does not primarily need ATP, it may need NADPH and Ribose-5-phosphate
Instead of breaking down glucose to make ATP, the cell redirects G6P to produce NADPH and R5P
Why would the cell need NADPH and Ribose-5-phosphate
NADPH: provides reducing power for biosynthesis and antioxidant defenseÂ
Ribose-5-phosphate (R5P): Provides the sugar backbone for nucleotides which are needed for DNA and RNA synthesis
Two phases of PPP:Â
Oxidative Phase:
Produces NADPHÂ
Produces CO2
Converts G6P → Ribulose-5-P
Irreversible overallÂ
Supports antioxidant defense and biosynthesisÂ
Nonoxidative Phase:Â
Rearranges carbon skeletons
Does not directly produce NADPHÂ
Interconverts 3-, 4-, 5-, 6-, and 7- carbon sugars
Reversible reactionÂ
Supplies R5P or returns carbons to glycolysis
Oxidative Phase
Making NADPH, first phase
Glucose-6-phosphate (6C)Â
NADP+ → NADPHÂ
6-phosphogluconate (6C)Â
NADP+ → NADPHÂ
CO2 Released
Ribulose-5-phosphate (5C)
Produces 2 NADPH, 1 CO2, 1 ribulose 5-phosphate per G6PÂ
Why is NADPH so important
NADPH provides electrons for reductive biosynthesis and antioxidant agents
It is needed to help synthesize fatty acids and sterols
Glutathione
Cells need NADPH to protect themselves
Problem: During processes like mitochondrial respiration, cells can generate reactive oxygen species (ROS)
Ex) Superoxide radicals (O2.-) which is very reactive and can damage lipids in cell membranes, proteins, and DNA → potentially causing mutation
the cell will need to neutralize them
How does the cell neutralize reactive oxygen species
superoxide radical → Hydrogen peroxide (H2O2) → Water (2H2O)
Problem: glutathione gets oxidized while helping neutralize hydrogen peroxide, so the cells need a way to regenerate the reduced glutathione which is where NADPH comes in
Glutathione Cycle
Glutathione Peroxidase: uses reduced glutathione (GSH) to neutralize hydrogen peroxide
H2O2 + 2GSH → 2H2O + GSSG
Hydrogen peroxide becomes water and reduced GSH becomes oxidized (GSSG)
Glutathione Reductase: Regenerates reduced glutathione using NADPH
GSSG + NADPH + H+ → 2GSH + NADP+
NADPH is oxidized to NADP+
GSSG gets reduced to 2GSH
The cell can now reuse GSH to neutralize more hydrogen peroxide
How does the glutathione cycle connect to the PPP
Oxidative phase of PPP produces NADPH
NADPH helps regenerate GSH
Regenerated GSH can help neutralize more H2O2 and protect against oxidative damage
What if the cell cannot make enough NADPH
G6P dehydrogenase catalyzes the first NADPH producig reaction of the PPP, if G6PD activity were reduced:
less NADPH produced
Glutathione reductase has less NADPH available
less oxidized glutathione can be regenerated into GSH
cells become more vulnerable to oxidative damage
What is the purpose of nonoxidative phase
Imagine the cell has already made the NADPH it needs but now it has a lot of the 5C sugars from the PPP but it doesn't need to make many nucleotides. Rather than wasting energy and resources, it can rearrange their carbons into molecules that will reenter glycolysis
How does carbon shuffling work
Transketolase: Transfers a 2 carbon unit from one sugar to anotherÂ
Transaldolase: Transfers a 3 carbon unit from one sugar to anotherÂ
The total number of carbons is conserved!
Transketolase: 5C + 5C ⇌ 3C + 7C
Transaldolase: 7C + 3C ⇌ 4C + 6CÂ
Transketolase: 5C + 4C ⇌ 3 C + 6C
Overall: three 5C sugars can be rearranged into 2 6C sugars and one 3C sugarÂ
Where do the products of carbon shuffling go
The 6C sugar is fructose-6-phosphate, which can be converted into G6P
The 3C sugar is glyceraldehyde-3-phosphate, which can enter glycolysis or be converted through additional reactions to help regenerate hexose phosphates
Why does the cell recycle carbons back into G6P
Allows the cell to keep generating NADPH without accumulating unnecessary ribose-5-phosphate
Regulation of PPP by NADPH
Glucose-6-phosphate dehydrogenase catalyzes the first reaction of the oxidative PPP
NADPH negatively regulated G6PD
High NADPH → G6PD inhibited → oxidative PPP flux decreases
High NADPH/increased NADP → oxidative PPP flux increases
How can nonoxidative PPP products be recycles towards G6P
Transketolase and transaldolase rearrange 5C sugars into F6P and G3P
F6P can be converted into G6P via phosphoglucose isomerase
G3P can enter additional reactions to help regenerate hexose phosphates
This allows carbons to be reused when the cell needs more NADPH than ribose-5-phosphate
G6PD deficiency and hemolytic anemia
A mutation in G6PD can cause hemolytic anemia, where red blood cells burst and are destroyed.Â
This happens because G6PD is responsible for the first NADPH producing reaction of oxidative PPP. RBCs are dependent on the PPP because they don't have mitochondria, and rely on PPP-generated NADPH to maintain a reduced glutathione.Â
Less G6PD can cause less NADPH to regenerate GSH, making the cell less capable of neutralizing reactive oxygen species. ROS will damage red blood cell proteins and membranes causing hemolytic anemia.Â
Carbon Shuffling in non-oxidative PPP
Ribulose-5-phosphate can become two different sugars via two reactions:Â
Reaction A: Isomerization → Ribulose-5-P → Ribose-5-P
Ribulose 5-phosphate isomerase converts a ketose into an aldoseÂ
Reaction B: Epimerization → Ribulose-5-P → Xu5P via Ribulose 5-phosphate 3-epimerase
Stays as a ketose but the configuration around carbon three changesÂ
This is important since the cells need different types of sugars to perform carbon shufflingÂ
Transketolase: The first carbon-shuffling reactionÂ
Xylulose 5-phosphate + Ribose-5-phosphate ⇌ G3P + S7P (7C)Â
Xu5P is a ketose donor and gives away one 2-carbon fragments
Its remaining 3C become G3P
Ribose-5-phosphate is the aldose acceptor, receiving the 2C fragment, and becoming 7C S7P
Utilizes TPP cofactor
3. Transaldolase: second carbon-shuffling reactionÂ
S7P + G3P ⇌ Fructose-6-phosphate + Erythrose-4-phosphateÂ
S7P (ketose so loses) donated 3C, leaving E4PÂ
G3P (aldose so gains) accepts 3C forming F6P
Doesn’t require TPP. Instead, an active-site forms covalent intermediates to stabilize during the carbon transfer
Transketolase: Third carbon-shuffling reactionÂ
Xu5P + E4P ⇌ G3P + F6P
TPP Role
Transketolase requires the thiamine pyrophosphate (TPP)Â
It helps the enzyme transfer a two-carbon unit between sugars
How does the transketolase reaction work
R5P + Xu5P ⇌ S7P + G3PÂ
TPP performs a nucleophilic attack on the carbonyl group of the Xu5P, allowing the TPP to interact with the ketose sugar and participate in the transfer of the two carbon unitÂ
Xu5P loses two carbons which becomes G3P, this is released from the active siteÂ
2C stay attached to the TPPÂ
Ribose-5-phosphate enters the active site and gains the two carbons forming S7P
This reaction is reversible, and it can catalyze this reaction in both directions
Formation of S7P
The Ribose-5-phosphates aldehyde carbonyl group turns into an alcohol groupÂ
This is because the histidine acts as a proton donor, protonated this OH
ATCase enzyme in nucleotide synthesis
Make the ring: ATCase participates in the process of building the pyrimidine ringÂ
Add the sugar component: the sugar component comes from the ribose-5-phosphate produced through the PPPÂ
°PPP provides the sugar component needed for nucleotide synthesis, while ATCase is involved in making the pyrimidine ring
Impact of electrons leaking out of the ETC
When an electron reacts with an Oxygen, it forms a superoxide which is an ROS and can damage proteins, membrane lipids, and DNA
Allergic reactions and G6PD
Someone has reduced G6PD activityÂ
Their red blood cells produce less NADPH through the PPPÂ
They have a reduced ability to regenerate GSHÂ
Certain antibiotics can cause oxidative stressÂ
Their red blood cells become damaged and undergo hemolysisÂ
This is an adverse reaction to taking an antibiotic and assume they are allergic but it could be a result of oxidative damage due to G6PD deficiency
First reaction of oxidative PPP
Standard step: G6P → 6-phosphoglucono-δ-lactone, and creating NADH + H+ from NADP+
PPP and the Glutathione cycle relationship
related but not the same
Oxidative PPP generated NADPH
Glutathione reductase uses the NADPH to generate GSH
The glutathione peroxidase will use GSH to neutralize the H2O2
So the PPPs role is to supply the NADPH, and the glutathione cycle just uses that NADPH to maintain antioxidant defense.
Why is NADPH the best regulator
Why is NADPH the best regulator:Â
High NADPH → G6PD inhibitionÂ
NADPH/NADP+ balance reflects the cell’s need for reducing powerÂ
The PPP produces multiple products, including NADPH and ribose-5-phosphate, which serve different cellular needs.
Regulating the PPP solely through sugar-product accumulation would not accurately reflect NADPH demand.
Example: The cell may need high NADPH but little ribose-5-phosphate.