Alkene Reactions

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Last updated 2:45 PM on 10/14/26
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32 Terms

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Addition reaction

The pi bond breaks and two new sigma bonds form on the two alkene carbons

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Oxidation in organic chemistry

Gaining C-O bonds or losing C-H bonds

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Reduction in organic chemistry

Gaining C-H bonds or losing C-O bonds

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Role of the alkene pi bond in additions

It is electron rich so it acts as the nucleophile

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Markovnikov's rule

H (or the first group added) goes on the less substituted carbon so the more stable carbocation forms

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Anti-Markovnikov

H goes on the more substituted carbon and the other group on the less substituted carbon

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Regioselectivity

When one direction of adding to the double bond is preferred

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Stereoselectivity

When one stereoisomer forms more than the others

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Syn addition

Both new groups add to the same side (both wedges or both dashes)

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Anti addition

The two new groups add to opposite sides (one wedge and one dash)

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Racemic mixture

Equal amounts of both enantiomers. Forms whenever a new stereocenter is made from a flat alkene or carbocation

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HX (HCl or HBr or HI) plus alkene

Alkyl halide. Markovnikov. Racemic if a stereocenter forms. Can rearrange

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Mechanism of HX addition

Pi bond attacks the H of HX to make a carbocation (slow step) then X⁻ attacks the carbocation

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Rate determining step of HX addition

Forming the carbocation

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H₂O with H₂SO₄ plus alkene

Alcohol. Markovnikov. Racemic if a stereocenter forms. Can rearrange. Acid is a catalyst

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Mechanism of acid catalyzed hydration

Pi bond grabs H from H₃O⁺ to make a carbocation then water attacks then water removes the extra H from the O to give the alcohol and regenerate H₃O⁺

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Br₂ or Cl₂ plus alkene

Vicinal dihalide (two X on neighboring carbons). Anti addition. No rearrangement

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Mechanism of halogenation

Pi bond attacks X₂ to form a bridged halonium ion then X⁻ attacks from the back side giving anti addition

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Bridged halonium ion

A three membered ring with the halogen bonded to both carbons. It blocks one face so the nucleophile attacks from the opposite side

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Br₂ or Cl₂ in water plus alkene

Halohydrin. OH goes on the more substituted carbon and X on the less substituted carbon. Anti addition

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Why OH goes on the more substituted carbon in halohydrin formation

That carbon of the bridged halonium is the most carbocation-like so water attacks it

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1) BH₃ or R₂BH then 2) H₂O₂ and NaOH

Hydroboration-oxidation. Alcohol with OH on the less substituted carbon (anti-Markovnikov). Syn addition. No rearrangement

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Do you need the hydroboration mechanism

No. Just know it is anti-Markovnikov and syn with no rearrangement

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1) OsO₄ then 2) NaHSO₃ and H₂O

1‚2-diol (vicinal diol or glycol). Syn addition through a cyclic osmate

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Why OsO₄ gives syn addition

OsO₄ binds both oxygens to the same face of the alkene in a cyclic osmate

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1) O₃ then 2) Me₂S (DMS)

Ozonolysis. Cuts the C=C and makes two C=O groups. Not regioselective or stereoselective

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Ozonolysis products

An alkene carbon with an H becomes an aldehyde and one with two carbon groups becomes a ketone. A ring alkene gives one chain with two C=O

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H₂ with Pd (or Pt or Ni)

Alkane. Syn addition of two H. Reduces every C=C in the molecule

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Which reactions are syn

Hydroboration and OsO₄ and H₂ with Pd

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Which reactions are anti

Br₂ or Cl₂ and Br₂ or Cl₂ in water

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Which reactions are Markovnikov

HX and H₂O with H₂SO₄ and halohydrin formation

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Reaction coordinate diagram for HX addition

Two humps with the first one higher (carbocation formation is the slow step) and the carbocation in the valley between