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A complete set of vocabulary flashcards covering summation formulas, geometric series, index manipulation, double sums, factorials, and finite product rules.
Sum of a Constant Sequence
For any constant a∈R and integers p≤n, the sum of constant terms equals ∑k=pna=(n−p+1)a.
Sum of the First n Integers
The closed-form formula for the sum of the first n positive integers: ∑k=1nk=2n(n+1).
Sum of the Squares of the First n Integers
The closed-form formula for the sum of the first n squares: ∑k=1nk2=6n(n+1)(2n+1).
Sum of the Cubes of the First n Integers
The closed-form formula for the sum of the first n cubes: ∑k=1nk3=4n2(n+1)2.
Geometric Sum from Index 0
For all n∈N, the geometric sum equals ∑k=0nqk=n+1 if q=1, and ∑k=0nqk=1−q1−qn+1 if q=1.
General Geometric Sum
For any q=1 and n≥p, the sum of geometric terms starting from index p is ∑k=pnqk=qp1−q1−qn−p+1.
Distributivity of Summation
For any constant λ∈R that does not depend on the index k, ∑k=1nλxk=λ∑k=1nxk.
Associativity and Commutativity of Summation
The rule that allows splitting the sum of two combined terms into separate sums: ∑k=1n(xk+yk)=∑k=1nxk+∑k=1nyk.
Index Shift by Translation (i=k+m)
For natural numbers p≤n and integer m, translating the summation index by i=k+m gives ∑k=pnxk+m=∑i=p+mn+mxi.
Index Shift by Reversal (i=m−k)
For natural numbers p≤n and integer m≥n, reflecting the summation index by i=m−k gives ∑k=pnxm−k=∑i=m−nm−pxi.
Additive Telescoping Sum
For any sequence of real numbers x0,…,xn+1, consecutive terms cancel to give ∑k=0n(xk+1−xk)=xn+1−x0.
Double Sum Interchange (Independent Indices)
When the ranges of indices are independent, the summation order can be swapped freely: ∑(i,j)∈[[1,n]]×[[1,m]]xi,j=∑i=1n∑j=1mxi,j=∑j=1m∑i=1nxi,j.
Double Sum Interchange (1≤i≤j≤n)
For dependent triangular indices with non-strict inequality: ∑1≤i≤j≤nxi,j=∑i=1n∑j=inxi,j=∑j=1n∑i=1jxi,j.
Double Sum Interchange (1≤i<j≤n)
For dependent triangular indices with strict inequality: ∑1≤i<j≤nxi,j=∑i=1n−1∑j=i+1nxi,j=∑j=2n∑i=1j−1xi,j.
Link Between Single and Double Sums
For real numbers x1,…,xn with n∈N∗, the expanded square of a sum is given by (∑k=1nxk)2=∑k=1nxk2+2∑1≤i<j≤nxixj.
Factorial (n!)
For any natural integer n, the integer defined by 0!=1 and for n∈N∗, n!=∏k=1nk=1×2×⋯×n, which satisfies n!=n×(n−1)!.
Product of a Constant Sequence
For all n∈N∗ and constant value λ, the product of constant terms is ∏k=1nλ=λn.
Multiplicativity of the Product Operator
For all n∈N∗, the product of term-by-term sequence products separates as ∏k=1n(xkyk)=(∏k=1nxk)(∏k=1nyk).
Product of a Quotient
When no yk is zero, the product of quotients factors as ∏k=1nykxk=∏k=1nyk∏k=1nxk.
Multiplicative Telescoping Product
When no xk is zero, for all n∈N, consecutive quotients cancel to yield ∏k=0nxkxk+1=x0xn+1.