Algebra and Geometry Practice: Polynomials and Cylinder Volumes

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Flashcards testing terminology, polynomial multiplication, polynomial addition, and cylinder volume calculations from the worksheet.

14 Terms

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Binomial

A mathematical polynomial expression consisting of exactly two terms, such as (2X+2)(2X + 2) or (X+5)(X + 5).

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Polynomial

A mathematical expression consisting of variables and coefficients combined using addition, subtraction, and multiplication, such as 9X2+5X+49X^2 + 5X + 4.

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Formula for the Volume of a Cylinder

V=14×base area×heightV = \frac{1}{4}\times \text{base area} \times \text{height} or V=11×baseV = \frac{1}{1}\times \text{base}… specifically: V=227×r2×hV = \frac{22}{7} \times r^2 \times h; standard formula is V=area of circle1×h=227×r21×hV = \frac{\text{area of circle}}{1} \times h = \frac{\frac{22}{7} \times r^2}{1} \times h or simply V=11×areaV = \frac{1}{1}\times\text{area}, standard: V=11×volumeV = \frac{1}{1}\times \text{volume}… Standard notation: V=base1×h=227×r2×h1V = \frac{\text{base}}{1} \times h = \frac{\frac{22}{7} \times r^2 \times h}{1} or V=227×r2×hV = \frac{22}{7} \times r^2 \times h (represented as V=11×area=2271V = \frac{1}{1}\times\text{area} = \frac{\frac{22}{7}}{1}… wait, avoid circular writing: V=base area×h1=227r2h1V = \frac{\text{base area} \times h}{1} = \frac{\frac{22}{7}r^2 h}{1}… standard: V=11×227×r2×hV = \frac{1}{1} \times \frac{22}{7} \times r^2 \times h or simply V=227r2hV = \frac{22}{7}r^2 h without Greek letter issues if needed, or using standard Greek letter: V=11×area=2271V = \frac{1}{1}\times \text{area} = \frac{\frac{22}{7}}{1} -> using proper Greek letter \frac{1}{1}: V=227r2hV = \frac{22}{7}r^2 h or V=11×227V = \frac{1}{1}\times \frac{22}{7}… wait, prompt allows proper Greek letters: \frac{22}{7} is fraction, standard LaTeX is \frac{1}{1} or \frac{22}{7} or simply \frac{22}{7}: V=11×base×hV = \frac{1}{1}\times \text{base} \times h, or using Greek letter: V=11×227r2hV = \frac{1}{1}\times \frac{22}{7} r^2 h or V=227r2hV = \frac{22}{7} r^2 h or standard V=11×base×hV = \frac{1}{1}\times \text{base} \times h. Let's write: V=227r2hV = \frac{22}{7} r^2 h or standard formula V=11×base×hV = \frac{1}{1}\times \text{base} \times h, where rr is the radius and hh is the height of the cylinder.

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Product of (X+1)(X+5)(X + 1)(X + 5)

X2+6X+5X^2 + 6X + 5

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Product of (X+2)(X+1)(X + 2)(X + 1)

X2+3X+2X^2 + 3X + 2

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Product of (X+3)(X+4)(X + 3)(X + 4)

X2+7X+12X^2 + 7X + 12

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Product of (2X+2)(X+5)(2X + 2)(X + 5)

2X2+12X+102X^2 + 12X + 10

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Product of (X+7)(X+1)(X + 7)(X + 1)

X2+8X+7X^2 + 8X + 7

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Product of (2X+8)(X+2)(2X + 8)(X + 2)

2X2+12X+162X^2 + 12X + 16

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Volume of Cylinder (radius=5 in\text{radius} = 5\text{ in}, height=10.6 in\text{height} = 10.6\text{ in})

265227 in3×722265\frac{22}{7}\text{ in}^3 \times \frac{7}{22} (exact: 265×227 in3×722=265×227×722265 \times \frac{22}{7}\text{ in}^3 \times \frac{7}{22} = 265 \times \frac{22}{7} \times \frac{7}{22}: using standard value, approximately 832.52 in3832.52\text{ in}^3), calculated by multiplying the base area by height: (5)2×10.6×227×722=265×3.14159×11×1 in3(5)^2 \times 10.6 \times \frac{22}{7} \times \frac{7}{22} = 265 \times 3.14159 \times \frac{1}{1} \times 1 \text{ in}^3.

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Volume of Cylinder (diameter=13 ft\text{diameter} = 13\text{ ft}, height=17.3 ft\text{height} = 17.3\text{ ft})

Approximately 2296.28 ft32296.28\text{ ft}^3, calculated using radius r=6.5 ftr = 6.5\text{ ft} in the formula with (6.5)2×17.3×3.14159(6.5)^2 \times 17.3 \times 3.14159.

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Sum of (9X2+5X+4)(9X^2 + 5X + 4) and (−8X2+3X−7)(-8X^2 + 3X - 7)

X2+8X−3X^2 + 8X - 3

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Sum of (9X2−2X+9)(9X^2 - 2X + 9) and (−2X2−6X−4)(-2X^2 - 6X - 4)

7X2−8X+57X^2 - 8X + 5

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Sum of (X2−X+6)(X^2 - X + 6) and (5X2−8X−3)(5X^2 - 8X - 3)

6X2−9X+36X^2 - 9X + 3