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Reduction
Increase in the # of H
H2, Pd-C
Only reduce alkenes, not carbonyls

H2 (xs), Pd-C
Completely reduces alkenes and carbonyls

NaBH4, MeOH
A mild reducing agent that reduces aldehydes to primary alcohols and ketones into secondary alcohols, followed by hydrolysis.

Will NaBH4, MeOH or 1) LiAlH4 2) H2O reduce OH?
No, NaBH4 and LiAlH4 will not reduce alcohols to other products.

1) LiAlH4 2)H2O or NaBH4, MeOH

What happens to leaving groups when NaBH4, MeOH or 1) LiAlH4 2) H2O is used?
The LG leaves and the reduction continues as normal.

How does NaBH4, MeOH and 1) LiAlH4 2) H2O react in the presence of NH?
NH stays and the carbonyl is kicked off

DIBAL-H and big boy
Soft reducing agents that stop at the aldehyde
DIBAL-H is selective for
Esters, acid chlorides, nitriles

Big Boy is selective for
Cl
PCC, DCM
Mild oxidizer, turns primary alcohols into aldehydes and secondary alcohols into ketones
Cr 6+/ CrO3/ Cr2O7 in H+
Strong oxidizer, turn primary alcohols into carboxylic acids and secondary alcohols into ketones

Ag2, NH4OH
Mild oxidizer, selective for aldehydes. Turns aldehydes into carboxylic acids

KMnO4
Strong oxidizer, turn primary and secondary alcohols into carboxylic acids, converts side chain db of ring into alcohols



KMnO4

What happens in an organolithium or Grignard reaction if there is a LG on the reactant?
The organometallic attacks twice

Cuprate functions
Soft oxidizer; 1,4 addition; acid halide to ketone, open least substituted C on epoxides


Organolithiums and Grignards
Hard oxidizing; 1.2 addition;


TBAF
Kicks off protecting group

TBDMS-Cl, imidazole
forms stable protecting group

Forms methyl group
1) (Me)2CuLi 2)H2O
adds a methyl group


Cuprates don’t react with
Aldehydes, ketones, carboxylic acids, esters
LiAlH4 2) H2O
Strong oxidizer
Counter clockwise is what configuration
S (H makes it switch to R)
imine and enamine rns occur in what solvent?
acetic acid

ch3co2-h pka
4.8

water pka
15.7

ch3ch2o-h pka
16
hc triple bond ch
25
H-H
35
CH2=CH2
44
CH3-H
50