Maths Foundations Mid term

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1
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Lemma 1 : (∀ x in F) x * 0 = 0

- Use Distributive Law

- Additive inverse of (x*0) is -(x * 0)

2
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Lemma 2 : (∀ x in F) -x = -1 * x

First step: x + ( -1 * x ) = (x * 1) + ( x * -1 )

with (x * 1) being the multiplicative identity and the second part by commutativity.

- Use distributive law with x * (1 + -1)

- Prove RHS = 0, then add (-x) to both sides.

3
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Lemma 3 : (-1)2 = 1

  • Distributive Law with a = -1, b = -1, c = 1


4
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Lemma 4 : (∀ x in F) If x does not = 0, then x does not equal -x

  • Consider trichotomy, so case 1 (x<0) and case 2 (x>0)

  • + x

  • Use transitivity x + x < x < 0


5
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Lemma 5 : (∀ x in F) x2 >= 0

  • Trichotomy. 3 cases: x = 0, x > 0, x < 0

  • For case 1 and 2 : *x for both sides.

  • For case 3 : add -x, so that you can * -x as -x > 0



6
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Lemma 6 : Archimedian Property v1 (the set of natural numbers are unbounded)

  • Proof by Contradiction. Assume N is bounded above.

  • So it has an upper bound x, so x-1 is not an upper bound. So can pick n>x-1 to exist. so n+1>x false.


7
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Lemma 7 : Archimedean Property v2. 1/n → 0

  • Definition of convergence.

  • N>1/ε so 1/N<ε


8
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Lemma 8 : Every sequence contains a monotone subsequence.

  • 2 cases: infinitely many peaks & finitely many peaks

  • Case 1: infinitely many peaks so ank >= ank+1 so monotone decreasing

  • Case 2 : Let ak be the last peak, so an1 < an2 so strictly monotone increasing


9
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Proposition 1 : Every rational number has a finite decimal expansion or an infinite recurring decimal expansion.

  • Let p/q be in the rational….

  • 10n1p / q = a1 + r1/q

  • remainder = 0 then expansion terminates and is finite

  • remainder repeats: all subsequent digits repeat


10
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Proposition 2

Root 2 is not rational.

11
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Proposition 3 : A sequence (an) is bounded if and only if (∃C in R)(∀n in N) |an| <= C

  • => Definition of bounded with L and U, set C = max{ |L|, |U| }.

  • <= Set L = -C and U = C


12
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Proposition 4 : If an is a convergent sequence, then (an) is bounded.

  • Set ε = 1 and so a - ε < an < a + ε

  • Consider terms nefore N1 so (∀n<= N1 -1) m <= an <= M

  • (∃m,M in R)(∀n in N)(min { a-1 , m} <= an <= max {a+1, M} , and set the min = L and max = U


13
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Proposition 5 : an → a <=> every subsequence ank → a

  • => Convergence def. All indices are strictly increasing, so nk >= N so replace ank with an.

  • <= Suppose every subsequence converges to a, set k = nk, so replaces ank = ak


14
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Theorem 1 : Triangle inequality

  • Write |x| and |y| using expanded bounds and combine


15
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Theorem 2 : Algebraic Limit Theorem

Algebraic Limit Theorem (an → a & bn → b)

  • can → ca

  • an + bn → a+b

  • anbn → ab

  • an/bn → a/b


16
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Theorem 2 : Algebraic Limit Theorem part a (can → ca)

  • ε / |c|

  • (∀ ε / |c| >0 )… where |an - a| < ε / |c|

  • Multiply the c to the other side


17
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Theorem 2 : Algebraic Limit Theorem part b (an + bn → a+b)

  • ε / 2

  • Take Na and Nb and M = max (Na, Nb)

  • Use triangle inequality


18
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Theorem 2 : Algebraic Limit Theorem part c (anbn → ab)

  • Take Na and Nb and M = max (Na, Nb)

  • |anbn - ab| = |anbn - abn + abn -ab| < …

  • Use bn is bounded so |bn| <= C and set C into where that is

  • Make each term < ε / 2 so +1 on denominator


19
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Theorem 2 : Algebraic Limit Theorem part d (an/bn → a/b)


  • Prove (1/bn → 1/b) then apply part c

  • 0 < C < |b|

  • |bn - b| = |b - bn| < C

  • Try to express bn in terms of something else


20
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Theorem 3 : Sequence Squeeze Theorem ((∀n in N)(an <= xn <= bn) and an → L and bn → L then, xn → L

  • Express the expanded L - ε < … < L + ε

  • Take Na and Nb and M = max (Na, Nb)

  • Combine using transitivity


21
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Theorem 4: Order Limit Theorem

  1. ((∀n in N)(an >= 0) => a >= 0

  2. ((∀n in N)(an <= bn) => a<=b

  3. ((∀c in R)(((∀n in N) c<=bn) => c<= b)


22
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Theorem 4: Order Limit Theorem part a : ((∀n in N)(an >= 0) => a >= 0

  • Proof by contradiction : suppose a < 0

  • |an - a| < |a|. => an < 0


23
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Theorem 4: Order Limit Theorem part b : ((∀n in N)(an <= bn) => a<=b

  • Consider the sequence (bn - an) → (b - a)

  • Use part a so b - a >= 0


24
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Theorem 4: Order Limit Theorem part c : ((∀c in R)(((∀n in N) c<=bn) => c<= b)


  • Define bn = c (the constant sequence) and apply part b


25
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Theorem 5 : Monotone Convergence Theorem

Monotone + Bounded => Convergence

26
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Theorem 5 : Monotone Convergence Theorem : if monotone + bounded => Convergence

  • 2 Cases: increasing case and decreasing case

E.g. Monotone increasing case

  • By def of bounded, there exists sup = s

  • s - ε < aN <= an <= s < s + ε by transitivity it converges to the sup


27
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Theorem 6 : Bolzano - Weierstrass Theorem

Every bounded sequence contains a convergent subsequence.

(by Lemme 8 we know every sequence contains a monotone subsequence, so if its bounded, then by monotone convergence theorem, it converges)

28
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Def 1 : Partial Ordering

  • Reflexivity : a<=a

  • Antisymmetry : a<=b and b<=a, then a=b

  • Transitivity : a<=b and b<=c , then a<=c


29
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Def 2 : Total Ordering

If it is a partial ordering and any two elements are comparable ( a<=b or b<=a).

30
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Def 3 : Maximal element

No element x is greater than the maximal element m.

31
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Def 4 : Greatest element

(∀s in S) s<= g and g is in S

32
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Def 5 : Field

A set F with two operations + and *, that satisfy the 11 axioms.

33
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Def 6 : Ordered Field

A field with total ordering <=

01) If x <= y , then x+z <= y+z

02) If x <= y , then x*z <= y*z

34
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Def 7 : Upper Bound

(∀s in S) s<= B

35
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Def 8 : Supremum (least upper bound)

1) (∀s in S) s<= B

B is an upper bound

2) (∀y < B)(∃a in S) a>y

No element less than B is an upper bound

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Def 9 : Lower Bound

(∀s in S) s >= b

37
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Def 10 : Infimum (greatest lower bound)

1) (∀s in S) s>= b

b is a lower bound

2) (∀y > b)(∃a in S) a<y

No element greater than b is lower bound

38
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Def 11 : Least Upper Bound Property

  • If a subset is non empty and is bounded above, then there exists a supremum in the set.


39
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Def 12 : Greatest Lower Bound Property

  • If a subset is non empty and is bounded below, then there exists an infimum in the set.


40
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Def 13 : Real Numbers

An ordered field with the least upper bound property.

41
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Def 14 : Absolute value

  • |x| = x , if x>=0

  • |x|= -x , if x<0


42
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Def 15 : Sequence

A function a : N → R

43
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Def 16 : Convergence of an → L

(∀ε >0)(∃N in N)(∀n>=N) |an - L| < ε

44
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Def 17 : ε neighbourhood

For a in R & ε >0. Vε (a) = { x in R : |x - a| < ε}

(points whose distance from a is less than ε)

45
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Def 18 : Convergence (topological)

an → a if every ε neighbourhood of a contains all terms of the sequence from some point on. Contains finite terms.

(∀ε >0)(∃N in N)(∀n>=N) an is in Vε (a)

46
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Def 19 : Bounded

(an) is bounded if (∃L,U in R)(∀n in N) L <= an <= U

47
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Def 20 : Monotone…

  • Monotone increasing if (∀n in N) an <= an+1

  • Strictly monotone decreasing is (∀n in N) an > an+1


48
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Def 21 : Partial Sum and Series

The mth partial sum of (bn) is = b1 + b2 + b3 …

Series is the sequence of partial sums. ie. b1 , b1+b2 , b1+b2+b3, …

If the partial sum converges to B, then the series equals B.

49
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Def 22 : Subsequence

A subsequence of (an) is (ank). Where the index are strictly monotone increasing.

50
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Def 23 : Peak

am is a peak of a sequence (an) if (∀n > m) am >= an