SATH MATH

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If f(x)=a2+2f\left(x\right)=a^2+2 , where a is a constante and f(1)=2.5f\left(1\right)=2.5 , what is the value ofa=0.5a=0.5 a-2?

a(1)2+2=2.5a\left(1\right)^2+2=2.5

a+2=2.5a+2=2.5

a=0.5a=0.5

a−2=0.5−2=−1.5a-2=0.5-2=-1.5

2
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When 4 times a is subtracted from 23 it gives -5. What is the resulting number when a times 9 is added to 8?

23−4a=−523-4a=-5

28−4a=028-4a=0 → 28=4a28=4a

a=7a=7 → 7⋅9+8=717\cdot9+8=71

3
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4x−7=z(x−3)+54x-7=z\left(x-3\right)+5

In the equation above a is a constant. If the equation has infinitely many solutions what is the value of z?

Infinitely many→ have same slope, both sides of the equations are the same

WRITING

Multiply z for the equation, then find the same value of the coefficient 4x. Verify if they give the same number

DESMOS

type the equations separately, add the slider for z and when they match you find z

4
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