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Methyl, 1 prime or 2 prime alkyl halide
For the substrate, ______ are preferred
3 prime
_____ substrates are too bulky AND WON’T WORK!
Inversion
The stereochemistry, the reaction proceeds with an ____ of stereochemistry at the reactive center: partial positive carbon
2nd
The kinetics - ___ order (bimolecular) aka the rate depends on [Nu] and [RX]
k[Nu][RX]
rate =
Transition state
A non-hindered needs to be used. Large substrates prevent the nucleophile from being able to attack. They will raise the energy of the ______\
Methyl and 1 prime alkyl halides
Undergo SN2 reactions with ease
2 prime alkyl halides
React more slowly
3 prime alkyl halides
DO NOT UNDERGO SN2 reactions. This order of reactivity can be explained by steric effects. Steric hinderance caused by bulky R groups makes Nucleophilic attack from the backside more difficult, slowing the reaction rate.
Vinyl and aryl halides
Do not undergo SN2 displacement
Nucleophile
Appears in the rate expression; the strength of the ______ will affect the rate of the reaction
Polar Aprotic solvent
Preferred for an SN2 reaction; has strong dipoles but no -OH or -NH groups
Protic solvents
Stabilize the nucleophile by lowering its energy, therefore slowing down the SN2 reaction; examples are ROH and NH2
Weaker base
The better leaving group is the ______ (except TsO- due to resonance)