L06 - Digital Signals

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25 Terms

1
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What is the difference between an analogue signal x(t) and a digital signal x[n]?

x(t) is continuous in time and amplitude; x[n] is a sequence of samples with discrete amplitude levels.

2
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What is the difference between sampling and quantisation?

Sampling makes time discrete; quantisation makes amplitude discrete.

3
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Sampling a continuous signal gives x[n] = ____.

x(nTs): the signal's value at time n × Ts.

4
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Telephone speech is sampled at 8 kHz. What is the sampling period?

125 µs, because Ts = 1/fs.

5
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What does the Nyquist-Shannon sampling theorem require for perfect reconstruction?

Sample faster than twice the highest frequency present: fs > 2fmax.

6
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A system samples at 16 kHz. What is the highest frequency it can represent without aliasing?

8 kHz, the Nyquist frequency (fs/2).

7
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A microphone signal contains energy up to 7 kHz. What is the minimum sampling rate?

Above 14 kHz, so 16 kHz wide-band systems are suitable.

8
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Why is 8 kHz a reasonable sampling rate for telephone speech?

Most speech intelligibility lies below about 4 kHz, so 8 kHz captures it while saving bandwidth.

9
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What is aliasing?

A frequency above fs/2 appears as a false, lower frequency after sampling.

10
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What rule gives the apparent frequency of an aliased tone?

The distance from the true frequency to the nearest multiple of fs.

11
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Sampled at 10 Hz, why can a 7 Hz tone and a 13 Hz tone not be told apart?

Both fold to 3 Hz, so they produce identical samples.

12
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Why do the samples on the right trace a slow wave that is not in the original signal? [IMAGE: Slide 11, hide both plot titles and the bottom caption]

fs = 6 Hz is below 2 × 5 Hz, so the 5 Hz tone aliases to 1 Hz.

13
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How is aliasing prevented in practice?

An anti-aliasing filter removes frequencies above fs/2 before sampling.

14
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<p>What frequency marks the first peak of this folding graph, and what happens above it? [IMAGE: Slide 24, hide the "Nyquist frequency fs/2" label]</p>

What frequency marks the first peak of this folding graph, and what happens above it? [IMAGE: Slide 24, hide the "Nyquist frequency fs/2" label]

The Nyquist frequency (fs/2 = 5 Hz); higher frequencies fold back to lower apparent frequencies.

15
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A quantiser using B bits has ____ amplitude levels.

2^B.

16
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Bit depth is doubled from 8 to 16 bits. What happens to the number of amplitude levels?

It is squared, from 256 to 65,536, because each extra bit doubles the levels.

17
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What is quantisation error, and what causes it?

The difference between the true and stored amplitude, caused by rounding to the nearest level.

18
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Signal-to-quantisation-noise ratio for B bits is approximately SQNR ≈ ____ dB.

6.02B + 1.76.

19
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Roughly how much does each extra bit of resolution improve SQNR, and at what cost?

About 6 dB per bit, at the cost of more storage and bandwidth per sample.

20
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What does the Fourier series say about a periodic signal?

Any well-behaved periodic signal is a weighted sum of sinusoids at its fundamental and harmonics.

21
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A voiced speech segment repeats every 8 ms. What are f0 and the next two harmonics?

f0 = 125 Hz; harmonics at 250 Hz and 375 Hz.

22
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Which harmonics make up an odd symmetric square wave, and how do their amplitudes behave?

Only odd harmonics, with amplitude 4/(kπ), so they fall as 1/k.

23
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<p>What happens to this waveform as more odd harmonics are added? [IMAGE: Slide 17, hide the four panel titles]</p>

What happens to this waveform as more odd harmonics are added? [IMAGE: Slide 17, hide the four panel titles]

It approaches a square wave, with each added harmonic giving a smaller correction.

24
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What is the difference between the Fourier series and the Fourier transform?

Series: periodic signal gives discrete harmonics. Transform: aperiodic signal gives a continuous spectrum.

25
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How does ideal sinc interpolation rebuild x(t) from its samples?

Each sample contributes one sinc pulse; summing them recovers x(t) exactly if fs > 2fmax.