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derivative of a function
f’(x)= lim h→0 [f(x+h) - f(x)]/h
gives you the slope of the tangent line at a specific point when you plug the x value into the derivative
derivative at a point
f’(a)= lim h→0 [f(x) - f(a)]/x-a
graphing f’ from f:
when f is decreasing
when f is increasing,
f has a horizontal tangent
f’ is negative
f’ is positive
changing from increasing to decreasing or vice versa, when f’ is 0
when is y=f(x) differentiable on a closed interval [a,b]
if it has a derivative at every interior point of the interval, and if the limits lim h→0+ [f(a+h) - f(a)]/h and lim h→0- [f(b+h) - f(b)]/h exist at end points
derivatives at endpoints are one-sided limits
when will f’(a) fail to exist?
where the slopes of the secant lines: [f(x) - f(a)]/x - a fail to approach a limit as x approaches a
corner (ex: f(x)= |x|)
cusp (ex: f(x)= x²/³)
vertical tangent (ex: f(x) = 3rd root of x
discontinuity (ex: unit step function)
locally linear
a function that is differentiable at a closely resembles its own tangent line very close to a
differentiable curves will “straighten out” when we zoom in on them at a point of differentiability
symmetric difference quotient
[f(a + h) - f(a - h)]/2h
computes the slopes between two nearby points on opposite sides of a
numerical derivative of f at a
[f(a + 0.001) - f(a - 0.001)]/0.002
NDER(f(x), a)
number
numerical derivative of f
[f(x + 0.001) - f(x - 0.001)]/0.002
NDER(f(x), x)
function
what’s the relationship between differentiability and continuity
if f has a derivative at x=a, then f is continuous at x=a
the converse of this is not true
intermediate value theorem for derivatives
if a and b are two points in an interval on which f is differentiable, then f’ takes on every value between f’(a) and f’(b)
derivative of a constant function
df/dx= d/fx (c) = 0
power rule
d/dx(x^n)= nx^n-1
constant multiple rule
d/dx (cu)= c du/dx
sum and difference rules
d/dx (u + or - v)= du/dx + or - dv/dx)
when is there a horizontal tangent on f(x)
when f’(x)=0
product rule
d/dx (uv)= u dv/dx + v du/dx
quotient rule
d/dx(uv)=[v du/dx - u dv/dx]/v²
higher order derivatives notation
y^n = [dy^(n-1)]/dx = d^n y/dx^n
d/dx cos(x)=
-sin (x)
d/dx sin (x)=
cos (x)
ln 1=
0
ln 0=
U.D
e^0=
1
e^ln a =
a
ln e^a =
a
d/dx a^x=
a^x ln a
d/dx e^x=
e^x
d/dx log a (x)=
(1/x) (1/ln a)
d/dx ln(x)=
1/x