MATH 645

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/15

encourage image

There's no tags or description

Looks like no tags are added yet.

16 Terms

1
New cards

Axiom 1

u+v∈Vu+v\in V

2
New cards

Axiom 2

u+v=v+uu+v=v+u

3
New cards

Axiom 3

(u+v)+w=u+(v+w)\left(u+v\right)+w=u+\left(v+w\right)

4
New cards

Axiom 4

0∈V0\in V s.t 0+u=u0+u=u

5
New cards

Axiom 5

−u∈V-u\in V s.t u+(−u)=0u+\left(-u\right)=0

6
New cards

Axiom 6

c⋅u∈Vc\cdot u\in V

7
New cards

Axiom 7

c(u+v)=cu+cvc\left(u+v\right)=cu+cv

8
New cards

Axiom 8

(c+d)u=cu+du\left(c+d\right)u=cu+du

9
New cards

Axiom 9

c⋅(du)=d(cu)c\cdot\left(du\right)=d\left(cu\right)

10
New cards

Axiom 10

I∈Vs.tI\in Vs.t I⋅u=uI\cdot u=u

11
New cards

What are all the addition Axioms

  1. u+v∈Vu+v\in V

  2. u+v=v+uu+v=v+u

  3. (u+v)+w=u+(v+w)\left(u+v\right)+w=u+\left(v+w\right)

  4. 0∈V0\in V s.t 0+u=u0+u=u

  5. −u∈V-u\in V s.t u+(−u)=0u+\left(-u\right)=0


12
New cards

What are the scalar Axioms

  1. c⋅u∈Vc\cdot u\in V

  2. c(u+v)=cu+cvc\left(u+v\right)=cu+cv

  1. (c+d)u=cu+du\left(c+d\right)u=cu+du

  2. c⋅(du)=d(cu)c\cdot\left(du\right)=d\left(cu\right)

  3. I∈Vs.tI\in Vs.t I⋅U=UI\cdot U=U


13
New cards

How to find the Null Space

  1. Make problem into Ax = 0

  2. Row reduce

  3. Set all the pivots equal to the free variables (non pivots)

  4. Have an X column with all the variables

  5. Separate the free variables into separate columns (This is span)

  6. Each column is a null space vector


<ol><li><p>Make problem into Ax = 0</p></li><li><p>Row reduce</p></li><li><p>Set all the pivots equal to the free variables (non pivots)</p></li><li><p>Have an X column with all the variables</p></li><li><p>Separate the free variables into separate columns (This is span)</p></li><li><p>Each column is a null space vector</p></li></ol><p></p>
14
New cards

Inverse of a 2×2

1ad−bc[d−b−ca]\frac{1}{ad-bc}\begin{bmatrix}d & -b\\ -c & a\end{bmatrix}

15
New cards

Diagonalization Process

  1. Get Diagonal Matrix with eigenvals of A

  2. Find all linearly independent eigenvectors of A

    1. If the amount of vectors is less than n for an A = n x n matrix, the matrix is not diagonalizable

  3. Construct P using the eigenvectors,

  4. Construct D from the eigenvalues like an Identity matrix

    1. For repeated roots, just have the repeats show twice

  5. Have A=PDP−1A=PDP^{-1}

  6. Multiply the Matrices Left to Right


16
New cards

Diagonalization k Identity

When A=PDP−1A=PDP^{-1}, we getAk=PDkP−1A^{k}=PD^{k}P^{-1}