Unit 2: Moles, Solutions, and Gas Laws

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Vocabulary flashcards covering molar calculations, solution concentrations, dilutions, and gas behavior laws based on Unit 2 course material.

33 Terms

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Mole (nn)

  • Unit of measurement for amount in chemistry, referring to amount of particles such as atoms, ions, or molecules


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Avogadro's Constant (NAN_A)

  • The conversion factor between the number of particles and moles, equal to 6.02×1023 mol−16.02 \times 10^{23}\,\text{mol}^{-1}.


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Molar Mass (MrM_r) of an Element

  • The mass of one mole of an element's atoms, as shown on the periodic table.


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Molar Mass of a Compound

  • mass of one mole of a compound's particles

  • calculated by sum of the molar masses of all atoms


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Percent Composition by Mass

  • The percentage of a compound's mass contributed by a specific element,

  • Calculated as: Percent Comp. by Mass=TOTAL Element MassMolar Mass of Compound×100\text{Percent Comp. by Mass} = \frac{\text{TOTAL Element Mass}}{\text{Molar Mass of Compound}} \times 100


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Hydrate

  • Ionic compound containing unbonded water molecules trapped in the empty spaces of its crystal lattice → evaporate upon heating


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Solution

  • A homogeneous mixture that is uniformly blended together on the molecular or atomic scale.


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Solute

  • The substance that is dissolved in a solution

  • Usually present in the smaller amount


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Solvent

  • Substance that dissolves solute in a solution


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Aqueous Solution

  • A solution in which water is the solvent

  • Designated in chemical equations by the symbol (aq)(aq).


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Concentrated Solution

  • A solution containing a large proportion of solute

  • Characterized by a high ratio of solute to solvent


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Dilute Solution

  • A solution containing a small proportion of solute

  • Characterized by a low ratio of solute to solvent


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Molar Concentration (CC)

  • The amount of solute in moles per volume of solution in cubic decimeters (C=nVC = \frac{n}{V})

  • Units for concentration are: mol dm−3\text{mol}\,\text{dm}^{-3}


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Mass Concentration (ρ\rho)

  • The mass of solute in grams per given volume of solution in cubic decimeters (ρ=mV\rho = \frac{m}{V}), commonly measured in g dm−3\text{g}\,\text{dm}^{-3} or g cm−3\text{g}\,\text{cm}^{-3}


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Preparation of a Standard Solution

  • The analytical process of dissolving a precisely weighed mass of solute in solvent within a beaker, transferring it, and diluting to the calibration mark in a volumetric flask


<ul><li><p>The analytical process of dissolving a precisely weighed mass of solute in solvent within a beaker, transferring it, and diluting to the calibration mark in a volumetric flask</p></li></ul><p></p>
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Dilution

  • The process of decreasing the concentration of a solution by adding more solvent, uses formula C1V1=C2V2C_1 V_1 = C_2 V_2


<ul><li><p>The process of decreasing the concentration of a solution by adding more solvent, uses formula $$C_1 V_1 = C_2 V_2$$</p></li></ul><p></p>
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Standard Temperature and Pressure (STP)

  • A standard reference condition for comparing gases defined as a pressure of 100 kPa100\,\text{kPa} and a temperature of 273 K273\,\text{K} (0 ∘C0\,^\circ\text{C})


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Kinetic Molecular Theory (KMT)

  1. A model that describes gas behavior at the particle level

  2. Particles have negligible volume

  3. Exert no intermolecular forces

  4. Undergo perfectly elastic collisions


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Gas Pressure

  • The force per unit area created when moving gas particles collide with the walls of their container.


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Relationship Between Volume and Pressure

  • A gas law stating that volume and pressure are inversely proportional when temperature and gas amount remain constant (p1V1=p2V2p_1 V_1 = p_2 V_2; linear for PP vs. 1V\frac{1}{V})


<ul><li><p>A gas law stating that volume and pressure are inversely proportional when temperature and gas amount remain constant ($$p_1 V_1 = p_2 V_2$$; linear for $$P$$ vs. $$\frac{1}{V}$$)</p></li></ul><p></p>
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Relationship Between Gas Volume and Temperature

  • A gas law stating that gas volume is directly proportional to absolute temperature when pressure and amount of gas remain constant (V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2})


<ul><li><p>A gas law stating that gas volume is directly proportional to absolute temperature when pressure and amount of gas remain constant ($$\frac{V_1}{T_1} = \frac{V_2}{T_2}$$)</p></li></ul><p></p>
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Relationship Between Pressure and Temperature

  • A gas law stating that gas pressure is directly proportional to absolute temperature when volume and amount of gas remain constant (P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2})


<ul><li><p>A gas law stating that gas pressure is directly proportional to absolute temperature when volume and amount of gas remain constant ($$\frac{P_1}{T_1} = \frac{P_2}{T_2}$$)</p></li></ul><p></p>
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Combined Gas Law

  • An equation relating initial and final conditions of pressure, volume, and temperature for a fixed amount of gas: P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}, where temperature must be in Kelvin


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Avogadro's Law

  • A principle stating that equal volumes of gases at the same temperature and pressure contain equal numbers of moles


<ul><li><p>A principle stating that equal volumes of gases at the same temperature and pressure contain equal numbers of moles</p></li></ul><p></p>
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Molar Volume at STP

  • The volume occupied by one mole of an ideal gas at standard temperature and pressure (100 kPa100\,\text{kPa} and 273 K273\,\text{K}), which equals 22.7 dm3 mol−122.7\,\text{dm}^3\,\text{mol}^{-1}.


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Ideal Gas Law

  • The equation of state of an ideal gas given by PV=nRTPV = nRT, where PP is pressure (kPa\text{kPa}), VV is volume (dm3\text{dm}^3), nn is amount in moles, R=8.31 J K−1 mol−1R = 8.31\,\text{J}\,\text{K}^{-1}\,\text{mol}^{-1}, and TT is temperature (K\text{K}).


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Real Gas

  • A gas that deviates from ideal behavior and the Kinetic Molecular Theory

  • Especially, under conditions of very low temperature or very high pressure where particle volume and intermolecular forces become significant.


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Empirical Formula

  • Simplest ratio of atoms in a compound


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Empirical Formula by % Comp

  1. % → grams

  2. Convert element masses into moles

  3. Divide by the smallest no. of moles

  4. Answers w/ decimals should be multiplied to get a whole no.


<ol><li><p>% → grams </p></li><li><p>Convert element masses into moles</p></li><li><p>Divide by the smallest no. of moles </p></li><li><p>Answers w/ decimals should be multiplied to get a whole no. </p></li></ol><p></p>
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Empirical Formula by Analysis

  • Found by analyzing the masses of reactant and products in a reaction

  • Used to determine the masses of the elements in the compound

  • From this point forward, process for empirical formula finding is the same


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Empirical Formula by Combustion

  1. Use % comp to find mass of carbon in the mass of CO2 produced

  2. Use % comp to find mass of hydrogen in H2O produced

  3. 3rd element if applicable, find its mass by subtraction → requires initial mass of compound

  4. Convert masses to moles

  5. Divide all results by the smallest no. of moles to get subscripts


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Molecular Formula

  • No. of atoms in a covalent molecule


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Finding Molecular Formula

  1. Know empirical formula + mass of compound

  2. Calculate empirical formula → molar mass of emp. formula

  3. Divide molecular mass by empirical formula

  4. Multiply the result by the subscripts