Unit 1 - Chapter 3 Physics and Motion Vocabulary

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Vocabulary flashcards with formulas for Unit 1 Chapter 3, covering motion, forces, Newton's Laws, work, power, mechanical advantage, and efficiency.

Last updated 2:01 PM on 10/5/26
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16 Terms

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Reference point

A starting point or location used to describe the location or position of an object.

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Position

An object's distance and direction from a reference point.

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Displacement

The difference between the initial position and the final position of an object.

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Velocity

The speed and direction of a moving object.

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Force

A push or a pull on an object.

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Gravity

An attractive force that exists between all objects that have mass.

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Mass

The amount of matter in an object, measured in kilograms (kg\text{kg}).

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Weight

The gravitational force exerted on an object.

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Newton’s 1st law of motion

States that if the net force on an object is zero, the motion of the object does not change.

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Inertia

The tendency of an object to resist a change in its motion.

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Newton’s 2nd law of motion

States that the acceleration of an object is equal to the net force acting on it divided by its mass (a=Fma = \frac{F}{m}).

<p>States that the acceleration of an object is equal to the net force acting on it divided by its mass ($$a = \frac{F}{m}$$).</p>
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Newton’s 3rd law of motion

States that when one object exerts a force on a second object, the second object exerts an equal force in the opposite direction on the first object.

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Work

The amount of energy transferred when a force causes an object to move, measured in joules (J\text{J}).

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Power

The rate at which work is done on an object.

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Mechanical Advantage

The ratio of output force (in newtons) to input force (in newtons), calculated as MA=FoutFinMA = \frac{F_{\text{out}}}{F_{\text{in}}} with no units.

<p>The ratio of output force (in newtons) to input force (in newtons), calculated as $$MA = \frac{F_{\text{out}}}{F_{\text{in}}}$$ with no units.</p>
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Efficiency

The ratio of output work (in joules) to input work (in joules) expressed as a percentage: efficiency=WoutWin×100%\text{efficiency} = \frac{W_{\text{out}}}{W_{\text{in}}} \times 100\%.

<p>The ratio of output work (in joules) to input work (in joules) expressed as a percentage: $$\text{efficiency} = \frac{W_{\text{out}}}{W_{\text{in}}} \times 100\%$$.</p>