thermodynamics

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38 Terms

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Specific heat capacity

Q=mcΔTQ=mc\Delta T

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atm to Pa

1atm=1.01×10^5 Pa

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Ideal gas law

pV=nRT, pV=NkT

(On formula sheet)

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What is an isochoric process

Volume is constant

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What is an isobaric process

Constant pressure

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What is an isothermal process

Constant temperature

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Work done on a system

∫V1V2pdV\int_{V_1}^{V_2}pdV

work is negative if the gas is compressed

work is positive is the gas expands

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Change in internal energy

dU=dQ-dW

Where dQ is the change in heat

is path independent, constant in an isolated system

(On formula sheet)

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work done in an isothermal process

dW=dQ so dU=0

W=nRTln⁡V2V1W=nRT\ln\frac{V_2}{V_1}

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Work done in an isochoric process

no work is done

dU=nCvdTdU=nC_{v}dT_{}

where C is molar heat capacity at a constant volume (C=Molar mass x c)

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Work done in isobaric process

dW=p(V2−V1)dW=p(V_2-V_1)

dU=ndT(Cp−R)dU=ndT(C_{p}-R)

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relationship between molar heat capacity at a constant pressure and at constant volume

Cp=CV+RC_{p}=C_{V}+R

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Adiabatic constant

γ=CpCV\gamma=\frac{C_{p}}{C_{V}}

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Adiabatic process

no heat flow into or out of system (dQ=0)

dU=-W

TVγ−1=constTV^{\gamma-1}=const

pVγ=constpV^{\gamma}=const (On formula sheet)

W=p1V1−p2V2γ−1W=\frac{p_1V_1-p_2V_2}{\gamma-1}

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Internal energy in a cycle

No net change in internal energy

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Heat in a heat engine

Q=W=∣QH∣−∣QC∣Q=W=\left\vert Q_{H}\right\vert-\left\vert Q_{C}\right\vert

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thermal efficiency of a heat engine

η=1−∣QCQH∣\eta=1-\left\vert\frac{Q_{C}}{Q_{H}}\right\vert

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the Carnot cycle

Contains two isothermal and two Adiabatic processes

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Efficiency for the carnot cycle

η=1−TCTH\eta=1-\frac{T_{C}}{T_{H}}


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Energy in a refrigerator

∣QH∣=∣QC∣+∣W∣\left\vert Q_{H}\right\vert=\left\vert Q_{C}\right\vert+\left\vert W\right\vert


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Coefficient of performance in refrigerators

Kr=∣QC∣∣QH−QC∣=TCTH−TCK_{r}=\frac{\left\vert Q_{C}\right\vert}{\left\vert Q_{H}-Q_{C}\right\vert}=\frac{T_{C}}{T_{H}-T_{C}}


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coefficient of performance in a heat pump

Kr=∣QH∣∣QH−QC∣=THTH−TCK_{r}=\frac{\left\vert Q_{H}\right\vert}{\left\vert Q_{H}-Q_{C}\right\vert}=\frac{T_{H}}{T_{H}-T_{C}}


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Zeroth law

When two bodies are each separately in thermodynamic equilibrium with a third body they will be in thermodynamic equilibrium which each other

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First law

For a closed system, the change in internal energy is the difference between the heat accumulated by the system and the work done by it

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Second law

It is impossible to construct a cyclic engine that only converts thermal energy from a reservoir at a given temperature into mechanical heat. A portion of the thermal energy must be transferred to a second reservoir at a lower temperature.

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what is entropy

Increasing entropy is an increase in disorder

Adiabatic and reversible processes have no change in entropy

Increased by:

Add heat

Increase volume

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Change in entropy

ΔS=SB−SA=∫AB ⁣1T dQ\Delta S=S_{B}-S_{A}=\int_{A}^{B}\!\frac{1}{T}\,dQ (JK−1)(JK^{-1})

CONVERT dQ TO dT USING SHC FORMULA

Positive value=decrease in order

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Entropy for microstates

S=kBln⁡wS=k_{B}\ln w

w is number of microstates


change in s: kB ln(w2-w1)

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Third law

The entropy of a perfect crystal at absolute zero is equal to zero


(Absolute zero is impossible to reach)

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Kinetic theory of gases

  • molecules move randomly

  • total number of molecules is large

  • volume occupied by molecules is small compared to that of the gas

  • no forces between molecules unless they collide

  • collisions are elastic and occur instantaneously


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kinetic pressure

p=13ρvrms2p=\frac13\rho v_{rms}^{_2}

(On formula sheet)

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root mean squared speed

vrms2=3Pρv_{rms}^2=\frac{3P}{\rho}

P is pressure

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Average kinetic energy

KE=32kTKE=\frac32kT

each degree of freedom the molecule has contributes 1/2kT

Eg translational x,y,z =3/2kT

translational and two rotational=5/2kT

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Average velocity

v‾=8kTπm\overline{v}=\sqrt{\frac{8kT}{\pi m}}

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rms velocity

vrms‾=3kTm\overline{v_{rms}}=\sqrt{\frac{3kT}{m}} (On formula sheet)

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most probable velocity

vmp=2kTmv_{mp}=\sqrt{\frac{2kT}{m}}

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How are the velocities related

vmp<v‾<vrmsv_{mp}<\overline{v}<v_{rms}

mp<avg<rms

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van der waals equation

ideal gas law corrected

(p+a(nV)2)(Vn−b)=RT(p+a(\frac{n}{V})^2)(\frac{V}{n}-b)=RT

a- corrects pressure/ intermolecular forces

b- corrects volume/ volume of molecules