Mathematics: Equations, Perimeter, Area, and Circle Properties

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Comprehensive practice flashcards covering circle vocabulary, circumference, area of circles, semicircles and compound shapes, perimeter problems, curriculum content indices, and rearranging multi-step algebraic formulae.

100 Terms

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According to the Equations unit contents, on which page is "Solving One Step Equations" reviewed?

Page 2

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Which topic in the Equations unit is designated as an "extra challenge" on Page 4?

Square Mystery

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On which page does the Equations unit cover "Forming & Solving Equations (Angles)"?

Page 9

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Which page of the Equations unit introduces the visual method of "Bar Models"?

Page 22

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What two types of double-sided equations are distinguished in the unit contents on Pages 21 and 23?

Double Sided Equations (Positive Coefficients) on Page 21 and Double Sided Equations (Negative Coefficients) on Page 23

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In Exercise 8g, Question 1a, how is the perimeter equation set up for a rectangle with adjacent sides 3x−13x - 1 and 2x2x and a perimeter of 3232?

2(3x−1)+2(2x)=322(3x - 1) + 2(2x) = 32

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In Exercise 8g, Question 1c, a triangle has side lengths 8−m8 - m, 9−m9 - m, and 10−m10 - m, and a perimeter of 1212. What is the value of mm?

m=5m = 5, because (8−m)+(9−m)+(10−m)=27−3m=12(8 - m) + (9 - m) + (10 - m) = 27 - 3m = 12, giving 3m=153m = 15

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In Exercise 8g, Question 2, a gate has a width of 2.4 m2.4\,\text{m} and a height of 1 m1\,\text{m}. What is the length of its diagonal rod?

2.6 m2.6\,\text{m}, calculated using Pythagoras' theorem: (2.4)2+12=5.76+1=6.76=2.6 m\sqrt{(2.4)^2 + 1^2} = \sqrt{5.76 + 1} = \sqrt{6.76} = 2.6\,\text{m}

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In Exercise 8g, Question 3a, a right-angled triangle with a height of 5 cm5\,\text{cm} and a base of 2x cm2x\,\text{cm} has an area of 30 cm230\,\text{cm}^2. What is the value of xx?

x=6x = 6, because 12×2x×5=5x=30\frac{1}{2} \times 2x \times 5 = 5x = 30

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In Exercise 8g, Question 3b, what is the perimeter of a right-angled triangle with perpendicular legs measuring 5 cm5\,\text{cm} and 12 cm12\,\text{cm}?

30 cm30\,\text{cm}, calculated as 5+12+52+122=5+12+13=30 cm5 + 12 + \sqrt{5^2 + 12^2} = 5 + 12 + 13 = 30\,\text{cm}

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In Exercise 8g, Question 4, what does the term "regular" mean when referring to regular hexagons?

All sides are equal

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In Exercise 8g, Question 5, two squares each with an area of 36 cm236\,\text{cm}^2 are placed side-by-side to form a rectangle. What is the perimeter of the rectangle?

36 cm36\,\text{cm}, because each square has side length 36=6 cm\sqrt{36} = 6\,\text{cm}, giving rectangle dimensions of 12 cm×6 cm12\,\text{cm} \times 6\,\text{cm} and a perimeter of 2(12+6)=36 cm2(12 + 6) = 36\,\text{cm}

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In Exercise 8g, Question 6, the area of a parallelogram with base 88 and height hh is four times the area of a triangle with base 66 and height 33. What is the value of hh?

h=4.5h = 4.5, because the triangle area is 12×6×3=9\frac{1}{2} \times 6 \times 3 = 9, four times this is 3636, and 8h=368h = 36 gives h=4.5h = 4.5

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In Page 39, Question 7, eight identical small rectangles are stacked to form a larger rectangle with a total height of 16 cm16\,\text{cm}. If four narrow sides form this height, what is the shorter side of each rectangle?

4 cm4\,\text{cm}, calculated as 16÷4=4 cm16 \div 4 = 4\,\text{cm}

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In Page 39, Question 8, what are the dimensions of the hockey pitch that Laura needs to paint?

A rectangle measuring 91.4 m91.4\,\text{m} by 55 m55\,\text{m} with two semicircular areas of radius 29.2 m29.2\,\text{m}

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In Page 39, Question 9, what is the length of the hypotenuse of an isosceles right-angled triangle with an area of 100 cm2100\,\text{cm}^2?

20 cm20\,\text{cm}, because 12a2=100  ⟹  a2=200\frac{1}{2}a^2 = 100 \implies a^2 = 200, so the hypotenuse is a2+a2=400=20 cm\sqrt{a^2 + a^2} = \sqrt{400} = 20\,\text{cm}

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In Page 39, Question 10, two identical overlapping squares have an overlapping area of 14 cm214\,\text{cm}^2 and a non-overlapping area of 70 cm270\,\text{cm}^2. What is the width of each square?

7 cm7\,\text{cm}, because the area of each square is 70+2(14)2=49 cm2\frac{70 + 2(14)}{2} = 49\,\text{cm}^2, giving a side length of 49=7 cm\sqrt{49} = 7\,\text{cm}

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In Page 39, Question 11a, each vertex of a square with area 36 cm236\,\text{cm}^2 lies on the circumference of a circle. What is the diameter of the circle correct to 3 significant figures?

8.49 cm8.49\,\text{cm}, which is the diagonal of the square: 62+62=72≈8.49 cm\sqrt{6^2 + 6^2} = \sqrt{72} \approx 8.49\,\text{cm}

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In Page 39, Question 11b, what is the area of a circle circumscribing a square of area 36 cm236\,\text{cm}^2, correct to 3 significant figures?

56.5 cm256.5\,\text{cm}^2, calculated as π×(722)2=18π≈56.5 cm2\pi \times \left(\frac{\sqrt{72}}{2}\right)^2 = 18\pi \approx 56.5\,\text{cm}^2

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In Page 39, Question 12, what general formula is used to calculate the area of a trapezium?

Area=a+b2×h\text{Area} = \frac{a + b}{2} \times h, where aa and bb are the lengths of the parallel sides and hh is the perpendicular height

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In Page 39, Question 12a, which algebraic expression represents one of the parallel bases of the trapezium?

7x−67x - 6

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According to the Contents page for the Perimeter, Area, and 3D Shapes unit, on which page does "Area of Circles, Semi-Circles & Quarter Circles" begin?

Page 9

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On which page does the unit cover "Names & Properties of 3d Shapes"?

Page 22

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What topic is covered immediately before "Units of Volume and Capacity" (Page 30)?

Surface Area (Page 28)

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On which page is "Volume of Cubes & Cuboids" introduced?

Page 32

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Which topic is designated as an extra challenge on Page 34 of the 3D Shapes unit?

Mixed & Combined Surface Area & Volume of Cuboids

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On which page does "Volume of Prisms & Cylinders" appear?

Page 36

28
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What is the definition of circumference?

The curve all the way round the circle

29
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What is the definition of a radius of a circle, and what is its plural?

A straight line from the centre to the circumference; plural: radii

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What is the definition of a diameter of a circle?

A straight line all the way across a circle, passing through the centre

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What is the definition of a chord?

A straight line from one point on the circumference to another

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What is the definition of an arc of a circle?

A curved part of the circumference

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What is the definition of a tangent to a circle?

A straight line outside the circle that meets the circumference at a point, but does not cross it

34
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What is the definition of a sector of a circle?

A 2D shape formed from an arc of a circle and two radii

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What is the definition of a segment of a circle?

A 2D shape formed from an arc of a circle and a chord

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Which two straight lines form the straight boundaries of a circle's sector?

Two radii

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Which straight line of a circle is always double the length of the radius?

The diameter

38
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Among a chord, radius, tangent, arc, and diameter, which one is not a straight line?

Arc

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What is the formula for the circumference of a circle in terms of its diameter?

Circumference=π×diameter\text{Circumference} = \pi \times \text{diameter} (C=πdC = \pi d)

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What is the formula for the circumference of a circle in terms of its radius?

Circumference=2×π×radius\text{Circumference} = 2 \times \pi \times \text{radius} (C=2πrC = 2\pi r)

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What constant value is approximated by π\pi (pi) in the "learn by heart" section?

π\pi is a constant equal to 3.14…3.14\dots

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In Exercise 4p, Question 1a, what is the circumference of a circle with a radius of 5 cm5\,\text{cm}, correct to 1 decimal place?

31.4 cm31.4\,\text{cm}, calculated as 2×π×5≈31.4 cm2 \times \pi \times 5 \approx 31.4\,\text{cm}

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In Exercise 4p, Question 1c, what is the circumference of a circle with a diameter of 8 m8\,\text{m}, correct to 1 decimal place?

25.1 m25.1\,\text{m}, calculated as π×8≈25.1 m\pi \times 8 \approx 25.1\,\text{m}

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In Page 28, Question 2, Jared does not have a calculator. Which calculation can he use to estimate the circumference of a circle with radius 5.9 cm5.9\,\text{cm}?

Calculation B: 2×3×62 \times 3 \times 6

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In Page 28, Question 3, what is the circumference of a circle with a diameter of 8 cm8\,\text{cm}, correct to 1 decimal place?

25.1 cm25.1\,\text{cm}, calculated as π×8≈25.1 cm\pi \times 8 \approx 25.1\,\text{cm}

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In Page 28, Question 4, what is the circumference of a circle with a radius of 2.4 cm2.4\,\text{cm}, correct to 1 decimal place?

15.1 cm15.1\,\text{cm}, calculated as 2×π×2.4≈15.1 cm2 \times \pi \times 2.4 \approx 15.1\,\text{cm}

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In Page 28, Question 5, a circle is inscribed in a square with a perimeter of 20 cm20\,\text{cm}. What is the circumference of the circle correct to 1 decimal place?

15.7 cm15.7\,\text{cm}, because the square has side length 20÷4=5 cm20 \div 4 = 5\,\text{cm}, giving a diameter of 5 cm5\,\text{cm} and C=π×5≈15.7 cmC = \pi \times 5 \approx 15.7\,\text{cm}

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In Page 28, Question 6, a circle touches two sides of a rectangle that has an area of 24 cm224\,\text{cm}^2 and a height of 6 cm6\,\text{cm}. What is the circumference of the circle to 1 decimal place?

12.6 cm12.6\,\text{cm}, because the rectangle's width is 24÷6=4 cm24 \div 6 = 4\,\text{cm}, making the circle's diameter 4 cm4\,\text{cm}, and C=π×4≈12.6 cmC = \pi \times 4 \approx 12.6\,\text{cm}

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In Page 28, Question 7, which is larger: the circumference of a circle with diameter 10 cm10\,\text{cm}, or the total circumference of two circles each with diameter 5 cm5\,\text{cm}?

Neither; they are equal, because π×10=10π\pi \times 10 = 10\pi and (π×5)+(π×5)=10π(\pi \times 5) + (\pi \times 5) = 10\pi

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In Mixed Shapes (Page 28), what is the perimeter of Shape A, an equilateral triangle with side length 7 cm7\,\text{cm}?

21 cm21\,\text{cm}, calculated as 3×7=21 cm3 \times 7 = 21\,\text{cm}

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In Mixed Shapes (Page 28), what is the perimeter of Shape B, a rectangle measuring 5 cm5\,\text{cm} by 2 cm2\,\text{cm}?

14 cm14\,\text{cm}, calculated as 2(5+2)=14 cm2(5 + 2) = 14\,\text{cm}

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In Mixed Shapes (Page 28), what is the perimeter of Shape C, a regular octagon with side length 2 cm2\,\text{cm}?

16 cm16\,\text{cm}, calculated as 8×2=16 cm8 \times 2 = 16\,\text{cm}

53
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In Mixed Shapes (Page 28), what is the perimeter of Shape D, a kite with side lengths 4 cm4\,\text{cm} and 6 cm6\,\text{cm}?

20 cm20\,\text{cm}, calculated as 2(4+6)=20 cm2(4 + 6) = 20\,\text{cm}

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What is the formula for the area of a circle?

Area=π×radius2\text{Area} = \pi \times \text{radius}^2 (A=πr2A = \pi r^2)

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According to the instruction box on Page 29, how do you find the radius when given the diameter?

To find the radius, half the diameter (Radius=diameter÷2\text{Radius} = \text{diameter} \div 2)

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In the worked example on Page 29, what is the area of a circle with radius 5 cm5\,\text{cm}, rounded to 3 significant figures?

78.5 cm278.5\,\text{cm}^2, calculated as π×52=78.5398⋯≈78.5 cm2\pi \times 5^2 = 78.5398\dots \approx 78.5\,\text{cm}^2

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In the worked example on Page 29, what is the area of a circle with diameter 13 m13\,\text{m}, rounded to 3 significant figures?

133 m2133\,\text{m}^2, calculated with radius 13÷2=6.5 m13 \div 2 = 6.5\,\text{m} as π×6.52=132.7322⋯≈133 m2\pi \times 6.5^2 = 132.7322\dots \approx 133\,\text{m}^2

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In Exercise 4q, Question 1a, what is the area of a circle with a radius of 3 cm3\,\text{cm}, correct to 1 decimal place?

28.3 cm228.3\,\text{cm}^2, calculated as π×32=9π≈28.3 cm2\pi \times 3^2 = 9\pi \approx 28.3\,\text{cm}^2

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In Exercise 4q, Question 1b, what is the area of a circle with a diameter of 12 cm12\,\text{cm}, correct to 1 decimal place?

113.1 cm2113.1\,\text{cm}^2, calculated with radius 6 cm6\,\text{cm} as π×62=36π≈113.1 cm2\pi \times 6^2 = 36\pi \approx 113.1\,\text{cm}^2

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In Exercise 4q, Question 2, a circle is inscribed within a square with a perimeter of 88 cm88\,\text{cm}. What is the area of the circle correct to 1 decimal place?

380.1 cm2380.1\,\text{cm}^2, because the square has side length 88÷4=22 cm88 \div 4 = 22\,\text{cm}, giving a radius of 11 cm11\,\text{cm} and Area=π×112≈380.1 cm2\text{Area} = \pi \times 11^2 \approx 380.1\,\text{cm}^2

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In Exercise 4q, Question 3a, what is the area of the smaller circle in a pair of concentric circles with radii 3 cm3\,\text{cm} and 5 cm5\,\text{cm}, to 1 decimal place?

28.3 cm228.3\,\text{cm}^2, calculated as π×32≈28.3 cm2\pi \times 3^2 \approx 28.3\,\text{cm}^2

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In Exercise 4q, Question 3c, what is the shaded ring area between two concentric circles with radii 3 cm3\,\text{cm} and 5 cm5\,\text{cm}, correct to 1 decimal place?

50.3 cm250.3\,\text{cm}^2, calculated as π×52−π×32=25π−9π=16π≈50.3 cm2\pi \times 5^2 - \pi \times 3^2 = 25\pi - 9\pi = 16\pi \approx 50.3\,\text{cm}^2

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In the Page 31 worked example, how is the area of a semicircle with a straight boundary of 7 cm7\,\text{cm} calculated?

Radius = 7÷2=3.5 cm7 \div 2 = 3.5\,\text{cm}; Area of full circle = π×3.52=38.484… cm2\pi \times 3.5^2 = 38.484\dots\,\text{cm}^2; Area of semicircle = 38.484÷2≈19.2 cm238.484 \div 2 \approx 19.2\,\text{cm}^2

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In the Page 31 worked example, how is the area of a quarter circle with radius 6 cm6\,\text{cm} calculated?

Area of full circle = π×62=113.097… cm2\pi \times 6^2 = 113.097\dots\,\text{cm}^2; Area of quarter circle = 113.097÷4≈28.3 cm2113.097 \div 4 \approx 28.3\,\text{cm}^2

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In Exercise 4r, Question 1a, what is the area of a semicircle with diameter 10 cm10\,\text{cm}, correct to 1 decimal place?

39.3 cm239.3\,\text{cm}^2, calculated with radius 5 cm5\,\text{cm} as π×522=12.5π≈39.3 cm2\frac{\pi \times 5^2}{2} = 12.5\pi \approx 39.3\,\text{cm}^2

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In Exercise 4r, Question 1b, what is the area of a semicircle with diameter 6 cm6\,\text{cm}, correct to 1 decimal place?

14.1 cm214.1\,\text{cm}^2, calculated with radius 3 cm3\,\text{cm} as π×322=4.5π≈14.1 cm2\frac{\pi \times 3^2}{2} = 4.5\pi \approx 14.1\,\text{cm}^2

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In Exercise 4r, Question 1c, what is the area of a quarter circle with radius 5 cm5\,\text{cm}, correct to 1 decimal place?

19.6 cm219.6\,\text{cm}^2, calculated as π×524=6.25π≈19.6 cm2\frac{\pi \times 5^2}{4} = 6.25\pi \approx 19.6\,\text{cm}^2

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In Exercise 4r, Question 1d, what is the area of a quarter circle with radius 8 cm8\,\text{cm}, correct to 1 decimal place?

50.3 cm250.3\,\text{cm}^2, calculated as π×824=16π≈50.3 cm2\frac{\pi \times 8^2}{4} = 16\pi \approx 50.3\,\text{cm}^2

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In Exercise 4r, Question 1e, what is the area of a semicircle with diameter 15 cm15\,\text{cm}, correct to 1 decimal place?

88.4 cm288.4\,\text{cm}^2, calculated with radius 7.5 cm7.5\,\text{cm} as π×7.522=28.125π≈88.4 cm2\frac{\pi \times 7.5^2}{2} = 28.125\pi \approx 88.4\,\text{cm}^2

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In Exercise 4r, Question 2a, what is the area of a shaded quarter of a circle that has a diameter of 14 cm14\,\text{cm}, correct to 1 decimal place?

38.5 cm238.5\,\text{cm}^2, calculated with radius 7 cm7\,\text{cm} as π×724=12.25π≈38.5 cm2\frac{\pi \times 7^2}{4} = 12.25\pi \approx 38.5\,\text{cm}^2

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In Exercise 4r, Question 3, a circular sector is formed within a square that has a perimeter of 36 cm36\,\text{cm}. What is the area of this quarter-circle sector to 1 decimal place?

63.6 cm263.6\,\text{cm}^2, because the square has side length 36÷4=9 cm36 \div 4 = 9\,\text{cm}, giving an area of π×924=20.25π≈63.6 cm2\frac{\pi \times 9^2}{4} = 20.25\pi \approx 63.6\,\text{cm}^2

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In the Page 33 example, how is the shaded area calculated for a 7 cm×3 cm7\,\text{cm} \times 3\,\text{cm} rectangle joined to a quarter circle of radius 3 cm3\,\text{cm}?

Rectangle area = 7×3=21 cm27 \times 3 = 21\,\text{cm}^2; Quarter circle area = π×324≈7.06858 cm2\frac{\pi \times 3^2}{4} \approx 7.06858\,\text{cm}^2; Total shaded area = 21+7.06858≈28.1 cm221 + 7.06858 \approx 28.1\,\text{cm}^2

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In the Page 33 subtraction example, how is the shaded area calculated when a semicircle of diameter 10 cm10\,\text{cm} is cut from a 10 cm×5 cm10\,\text{cm} \times 5\,\text{cm} rectangle?

Rectangle area = 10×5=50 cm210 \times 5 = 50\,\text{cm}^2; Semicircle area = π×522≈39.2699 cm2\frac{\pi \times 5^2}{2} \approx 39.2699\,\text{cm}^2; Shaded area = 50−39.2699≈10.7 cm250 - 39.2699 \approx 10.7\,\text{cm}^2

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In Exercise 4s, Question 1a, what is the total area of a composite shape made of a 6 cm×6 cm6\,\text{cm} \times 6\,\text{cm} square attached to a semicircle of diameter 6 cm6\,\text{cm}, to 1 decimal place?

50.1 cm250.1\,\text{cm}^2, calculated as 36+π×322=36+14.137⋯≈50.1 cm236 + \frac{\pi \times 3^2}{2} = 36 + 14.137\dots \approx 50.1\,\text{cm}^2

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In Exercise 4s, Question 1b, what is the area of a composite shape comprising a right triangle with base 9 cm9\,\text{cm} and height 6 cm6\,\text{cm} joined to a quarter circle of radius 6 cm6\,\text{cm}?

55.3 cm255.3\,\text{cm}^2, calculated as (12×9×6)+π×624=27+9π≈55.3 cm2\left(\frac{1}{2} \times 9 \times 6\right) + \frac{\pi \times 6^2}{4} = 27 + 9\pi \approx 55.3\,\text{cm}^2

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In Exercise 4s, Question 1c, what is the total combined area of two identical quarter circles of radius 7 cm7\,\text{cm}, correct to 1 decimal place?

77.0 cm277.0\,\text{cm}^2, which equals the area of a semicircle with radius 7 cm7\,\text{cm}: π×722=24.5π≈77.0 cm2\frac{\pi \times 7^2}{2} = 24.5\pi \approx 77.0\,\text{cm}^2

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In Exercise 4s, Question 1d, which basic geometric figures make up the compound shape with an overall height of 12 cm12\,\text{cm}?

A rectangle and a semicircle

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In Exercise 4s, Question 1f, what is the total area of a composite shape formed by an 8 cm×8 cm8\,\text{cm} \times 8\,\text{cm} square and a three-quarter circle with radius 8 cm8\,\text{cm}, correct to 1 decimal place?

214.8 cm2214.8\,\text{cm}^2, calculated as 82+(34×π×82)=64+48π≈214.8 cm28^2 + \left(\frac{3}{4} \times \pi \times 8^2\right) = 64 + 48\pi \approx 214.8\,\text{cm}^2

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In Exercise 4s, Question 2, a circle is inscribed in a square of side length 22 cm22\,\text{cm}. What is the shaded area outside the circle but inside the square, correct to 1 decimal place?

103.9 cm2103.9\,\text{cm}^2, calculated as 222−(π×112)=484−121π≈103.9 cm222^2 - (\pi \times 11^2) = 484 - 121\pi \approx 103.9\,\text{cm}^2

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In Page 34, Question 3a, a quarter circle of radius 4 cm4\,\text{cm} is removed from a 4 cm×4 cm4\,\text{cm} \times 4\,\text{cm} square. What is the remaining shaded area to 1 decimal place?

3.4 cm23.4\,\text{cm}^2, calculated as 42−π×424=16−4π≈3.4 cm24^2 - \frac{\pi \times 4^2}{4} = 16 - 4\pi \approx 3.4\,\text{cm}^2

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In Page 34, Question 3b, a semicircle of diameter 6 cm6\,\text{cm} is removed from a rectangle measuring 3 cm×6 cm3\,\text{cm} \times 6\,\text{cm}. What is the remaining shaded area to 1 decimal place?

3.9 cm23.9\,\text{cm}^2, calculated as (3×6)−π×322=18−4.5π≈3.9 cm2(3 \times 6) - \frac{\pi \times 3^2}{2} = 18 - 4.5\pi \approx 3.9\,\text{cm}^2

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In Page 34, Question 3c, four corner quarter circles of radius 5 cm5\,\text{cm} are removed from a 10 cm×10 cm10\,\text{cm} \times 10\,\text{cm} square. What is the remaining shaded area to 1 decimal place?

21.5 cm221.5\,\text{cm}^2, calculated as 102−(π×52)=100−25π≈21.5 cm210^2 - (\pi \times 5^2) = 100 - 25\pi \approx 21.5\,\text{cm}^2

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In Page 34, Question 3e, a right-angled triangle with legs measuring 8 cm8\,\text{cm} is cut from a quarter circle of radius 8 cm8\,\text{cm}. What is the shaded area to 1 decimal place?

18.3 cm218.3\,\text{cm}^2, calculated as π×824−(12×8×8)=16π−32≈18.3 cm2\frac{\pi \times 8^2}{4} - \left(\frac{1}{2} \times 8 \times 8\right) = 16\pi - 32 \approx 18.3\,\text{cm}^2

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In Page 34, Question 4a, a rectangle of length 12 cm12\,\text{cm} encloses two identical tangent circles. What is the shaded area surrounding the circles to 1 decimal place?

15.5 cm215.5\,\text{cm}^2, because each circle has diameter 6 cm6\,\text{cm} (radius 3 cm3\,\text{cm}) and rectangle height is 6 cm6\,\text{cm}, giving (12×6)−2(π×32)=72−18π≈15.5 cm2(12 \times 6) - 2(\pi \times 3^2) = 72 - 18\pi \approx 15.5\,\text{cm}^2

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In Page 34, Question 4b, a rectangle of height 10 cm10\,\text{cm} contains three identical tangent circles. What is the shaded area surrounding the circles to 1 decimal place?

64.4 cm264.4\,\text{cm}^2, because each circle has diameter 10 cm10\,\text{cm} (radius 5 cm5\,\text{cm}) and rectangle length is 30 cm30\,\text{cm}, giving (30×10)−3(π×52)=300−75π≈64.4 cm2(30 \times 10) - 3(\pi \times 5^2) = 300 - 75\pi \approx 64.4\,\text{cm}^2

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In Page 34, Question 5a, what is the area of the smaller circle in a pair of concentric circles with an inner radius of 3 m3\,\text{m} and a ring width of 2 m2\,\text{m}, to 1 decimal place?

28.3 m228.3\,\text{m}^2, calculated as π×32≈28.3 m2\pi \times 3^2 \approx 28.3\,\text{m}^2

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In Page 34, Question 5b and 5c, what are the area of the larger circle and the shaded ring area for concentric circles with inner radius 3 m3\,\text{m} and outer radius 5 m5\,\text{m}, to 1 decimal place?

Large circle area = π×52=25π≈78.5 m2\pi \times 5^2 = 25\pi \approx 78.5\,\text{m}^2; Shaded area = 25π−9π=16π≈50.3 m225\pi - 9\pi = 16\pi \approx 50.3\,\text{m}^2

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In Page 34, Question 6, a square with side length 8 cm8\,\text{cm} has all four vertices on a circle. What are the diagonal of the square and the shaded area outside the square?

Diagonal = 82+82=128≈11.3 cm\sqrt{8^2 + 8^2} = \sqrt{128} \approx 11.3\,\text{cm}; Shaded area = π×(1282)2−82=32π−64≈36.5 cm2\pi \times \left(\frac{\sqrt{128}}{2}\right)^2 - 8^2 = 32\pi - 64 \approx 36.5\,\text{cm}^2

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In Source 12, formula (a), make xx the subject: y=axb+cy = \frac{ax}{b} + c

x=b(y−c)ax = \frac{b(y - c)}{a}

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In Source 12, formula (b), make xx the subject: y=ax3by = \frac{ax^3}{b}

x=bya3x = \sqrt[3]{\frac{by}{a}}

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In Source 12, formula (c), make xx the subject: ax+by=cax + by = c

x=c−byax = \frac{c - by}{a}

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In Source 12, formula (d), make xx the subject: y=bx10y = \sqrt{\frac{bx}{10}}

x=10y2bx = \frac{10y^2}{b}

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In Source 12, formula (e), make xx the subject: y+a=x2b−3ay + a = \frac{x}{2b} - 3a

x=2b(y+4a)x = 2b(y + 4a)

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In Source 12, formula (f), make xx the subject: x2+y2=9x^2 + y^2 = 9

x=±9−y2x = \pm\sqrt{9 - y^2} (or x=9−y2x = \sqrt{9 - y^2})

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In Source 12, formula (g), make xx the subject: y=ab+cxy = ab + \sqrt{cx}

x=(y−ab)2cx = \frac{(y - ab)^2}{c}

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In Source 12, formula (h), make xx the subject: y=2x+aby = \frac{2x + a}{b}

x=by−a2x = \frac{by - a}{2}

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In Source 12, formula (i), make xx the subject: y=5x−a3y = \sqrt[3]{5x - a}

x=y3+a5x = \frac{y^3 + a}{5}

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In Source 12, formula (j), make xx the subject: y=a(x−2)by = \frac{a(x - 2)}{b}

x=bya+2x = \frac{by}{a} + 2

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In Source 12, formula (k), make xx the subject: y+6=ax2−4yy + 6 = \frac{ax}{2} - 4y

x=2(5y+6)ax = \frac{2(5y + 6)}{a}

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In Source 12, formula (l), make xx the subject: y3=x2a−b2y^3 = \frac{x^2}{a} - b^2

x=±a(y3+b2)x = \pm\sqrt{a(y^3 + b^2)} (or x=a(y3+b2)x = \sqrt{a(y^3 + b^2)})