Calculus: Center of Mass and Centroids

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Vocabulary practice flashcards covering master formulas, point masses, 1-D wires, 2-D plates, centroids, 3-D solids, and common exam traps for Section 3.8: Center of Mass.

23 Terms

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Master Center-of-Mass Formula

The foundational principle behind all center-of-mass problems: coordinate=momentmass=∫(position of slice) dm∫dm\text{coordinate} = \frac{\text{moment}}{\text{mass}} = \frac{\int (\text{position of slice})\,dm}{\int dm}. The general procedure is to find dmdm, determine the position of the slice, integrate position×dm\text{position} \times dm, and divide by ∫dm\int dm.

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For example, masses of 2 kg2\,\text{kg} at (0,0)(0,0), 3 kg3\,\text{kg} at (4,0)(4,0), and 5 kg5\,\text{kg} at (1,3)(1,3) give total mass M=10M = 10, with coordinates xˉ=1.7\bar{x} = 1.7 and yˉ=1.5\bar{y} = 1.5.

Center of Mass for Discrete Point Masses: Calculated via a weighted average without integrals: xˉ=∑mixi∑mi\bar{x} = \frac{\sum m_i x_i}{\sum m_i} and yˉ=∑miyi∑mi\bar{y} = \frac{\sum m_i y_i}{\sum m_i}.

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For example, 8 kg8\,\text{kg} at (0,0)(0,0) and 4 kg4\,\text{kg} at (t,t)(t,t) yield xˉ=4t12=t3\bar{x} = \frac{4t}{12} = \frac{t}{3} and yˉ=t3\bar{y} = \frac{t}{3}.

Time-Dependent Point Masses: Point mass systems where coordinates are functions of time, such as p⃗i(t)\vec{p}_i(t). The standard discrete weighted average formula is applied, producing center-of-mass coordinates that are functions of tt.

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For a thin wire positioned along the x-axis from aa to bb with length-density δℓ(x)\delta_\ell(x) ,

total mass is M=∫abδℓ(x) dxM = \int_a^b \delta_\ell(x)\,dx, the moment is Mxˉ=∫abxδℓ(x) dxM\bar{x} = \int_a^b x\delta_\ell(x)\,dx, and the center of mass is xˉ=MxˉM\bar{x} = \frac{M\bar{x}}{M}.

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Constant-Density Wire

A one-dimensional wire along the x-axis from aa to bb with uniform density. Its center of mass is located directly at the geometric midpoint xˉ=a+b2\bar{x} = \frac{a+b}{2} without requiring any integration.

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Integration-by-Parts Moment Integrals

Wire center-of-mass problems where the density function δ(x)\delta(x) involves expressions such as exe^x, ln⁡(x)\ln(x), xln⁡(x)x\ln(x), or cos⁡(x)\cos(x). In these cases, computing the moment integral Mxˉ=∫xδ(x) dxM\bar{x} = \int x\delta(x)\,dx yields integrands like xexxe^x or x2ln⁡(x)x^2 \ln(x) that require integration by parts.

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Mass of a Two-Dimensional Plate (MM)

The total mass of a flat lamina bounded between top curve f(x)f(x) and bottom curve g(x)g(x) from aa to bb with density δ(x)\delta(x), obtained using vertical strips dm=δ(x)(f(x)−g(x)) dxdm = \delta(x)(f(x) - g(x))\,dx to give M=∫abδ(x)(f(x)−g(x)) dxM = \int_a^b \delta(x)(f(x) - g(x))\,dx.

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Plate Moment about the y-Axis (MxˉM\bar{x})

The moment of a planar plate bounded by top curve f(x)f(x) and bottom curve g(x)g(x) with density δ(x)\delta(x) about the y-axis, defined by Mxˉ=∫abxδ(x)(f(x)−g(x)) dxM\bar{x} = \int_a^b x\delta(x)(f(x) - g(x))\,dx.

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Plate Moment about the x-Axis (MyˉM\bar{y})

The moment of a planar plate bounded by top curve f(x)f(x) and bottom curve g(x)g(x) with density δ(x)\delta(x) about the x-axis, defined by Myˉ=∫abδ(x)f(x)2−g(x)22 dxM\bar{y} = \int_a^b \delta(x) \frac{f(x)^2 - g(x)^2}{2}\,dx. This arises because each vertical strip balances at its midpoint f+g2\frac{f+g}{2}, and f+g2(f−g)=f2−g22\frac{f+g}{2}(f - g) = \frac{f^2 - g^2}{2}.

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Crossing Curves Limits Method

The procedure used when finding the region between two curves without given interval limits: set f(x)=g(x)f(x) = g(x) to solve for the boundary points, then test a value strictly between those points to determine which curve is on top (ff) and which is on the bottom (gg).

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Plate Defined by Vertices

A planar region defined by vertex coordinates (such as a triangle with vertices at (0,0)(0,0), (1,1)(1,1), and (1,−1)(1,-1)). Solving requires writing out the linear equation of each bounding edge to identify top curve f(x)f(x) and bottom curve g(x)g(x) over the relevant interval.

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Plate with Constant Horizontal Boundaries

A rectangular plate or region bounded by lines such as y=1y = 1 and y=5y = 5, represented by constant functions f(x)=5f(x) = 5 and g(x)=1g(x) = 1. For a rectangle [1,6]×[1,5][1,6] \times [1,5] where density δ=ex\delta = e^x does not depend on yy, yˉ=3\bar{y} = 3 by inspection.

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Centroid of a Two-Dimensional Region

The geometric center of a planar region where density is constant and cancels out. Given area A=∫ab(f−g) dxA = \int_a^b (f - g)\,dx, the coordinates are xˉ=1A∫abx(f−g) dx\bar{x} = \frac{1}{A} \int_a^b x(f - g)\,dx and yˉ=12A∫ab(f2−g2) dx\bar{y} = \frac{1}{2A} \int_a^b (f^2 - g^2)\,dx.

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Centroid Symmetry Principle

A rule stating that if both the shape of a region and its density are symmetric across a line, the center of mass must lie along that line of symmetry, allowing one to skip evaluating that coordinate's integral (e.g., symmetry across the y-axis guarantees xˉ=0\bar{x} = 0).

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Centroid of a Half-Disk

For the upper half-disk y=r2−x2y = \sqrt{r^2 - x^2}, symmetry yields xˉ=0\bar{x} = 0, area is A=πr22A = \frac{\pi r^2}{2}, and the vertical centroid is yˉ=12A∫−rr(r2−x2) dx=4r3π\bar{y} = \frac{1}{2A} \int_{-r}^r (r^2 - x^2)\,dx = \frac{4r}{3\pi}. Squaring ff eliminates the square root.

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Centroid of a Right Triangle

Located 13\frac{1}{3} of the way inward from the right-angled corner along each leg. For example, for the region beneath y=kxy = kx on the interval [0,b][0,b], the centroid is given by (2b3,kb3)\left(\frac{2b}{3}, \frac{kb}{3}\right).

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Center of Mass of a 3-D Solid with Cross-Sectional Area

For a three-dimensional solid with horizontal slab cross-sectional area A(z)A(z) and uniform density, the slab mass element is dm=δA(z) dzdm = \delta A(z)\,dz and the vertical centroid is zˉ=∫zA(z) dz∫A(z) dz\bar{z} = \frac{\int zA(z)\,dz}{\int A(z)\,dz}.

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Centroid Height of a Cone

A standard geometric result stating that the centroid of any cone, regardless of base shape, is located 14\frac{1}{4} of the total height up from the base (or 34\frac{3}{4} of the height down from the apex).

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Density Cancellation Fallacy

The mistaken idea that a variable density function δ(x)\delta(x) can be cancelled from the ratio ∫xδ dx∫δ dx\frac{\int x\delta\,dx}{\int \delta\,dx}. Density can only factor out and cancel when δ\delta is constant across the entire region.

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Mid-Mass Point vs. Center of Mass

The mid-mass point divides the total mass into two equal halves (50%50\% on each side), whereas the center of mass additionally weights mass by its distance from the origin. For δ=e−x\delta = e^{-x} on [0,4][0,4], the mid-mass point is approximately 0.6750.675, whereas xˉ≈0.925\bar{x} \approx 0.925.

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Validity of a Density Function

The requirement that a real-world density function must satisfy δ≥0\delta \ge 0 everywhere on the specified interval, because negative mass density is physically meaningless. For example, δ(x)=x2−3\delta(x) = x^2 - 3 is valid on [2,5][2,5] but invalid on [1,4][1,4] where x<3x < \sqrt{3}.

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“Set Up Only, Do Not Evaluate” Protocol

A problem-solving instruction requiring the student to write the definite integrals for MM, MxˉM\bar{x}, and MyˉM\bar{y} with explicit integration limits, boundary curves ff and gg, and density δ\delta, state xˉ=MxˉM\bar{x} = \frac{M\bar{x}}{M} and yˉ=MyˉM\bar{y} = \frac{M\bar{y}}{M}, and stop without computing antiderivatives.

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Center-of-Mass Sanity Check

A verification step confirming that the computed center of mass shifts toward the heavier or wider portions of the object and, for a single region with f≥gf \ge g, lies strictly within the bounding box of the geometric shape.