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Fnet=mgsinθ-Ffr
Acceleration down a ramp
Ffr=μ(Fg-Fappsinθ)
Pulling up at an angle of an object on a horizontal surface
Ffr≤μFN
Friction equation
T1=T2(cosΦ/cosθ)
AND
T2=((cosΦ/cosθ)sinθ)+T2sinΦ=Fg
For finding tension of booth strings holding a hanging object
Ffr=μmgcosθ
Friction on an incline
T=m1a
m2g-T=m2a
T=m1a+m1g
Tension correlating to block on table
Block dropping down
Block rising up
Fnet=Fapp-Ffr (where Fapp is cosθ)
x direction for an object being pushed/pulled at an angle
F= (μmg)/(cosθ+μksinθ)
Constant speed of being pulled at an angle upward
a=(Fnet)/(a) OR Fnet=ma
newton’s 3rd law
FT=m(g+a)
FT=m(g-a)
a=(g(m1-m2))/(m1+m2)
vertical acceleration solving for tension going up
vertical acceleration solving for tension going down
solving for acceleration with 2 masses over a frictionless pulley
FN=mg-Fsinθ
Pulling upward at an angle
FN=mgcosθ
sitting on an inclined ramp at an angle
F11=mgsinθ
parallel component of gravity
FN=mg+sinθ
pushing downward at an angle
Ffr=μ(Fappsinθ+Fg)
pushing down at an angle on an object on a horizontal surface
FN=Fg
Fapp-Ffr=Fnet
Ffr=Fapp
horizontal with no vertical component
when Fappis greater than Ffr
constant speed where Fnet=0
F11=Ffr
F=ma⟶ma=mgsinθ⟶a=gsinθ
F=ma⟶Fnet=ma⟶Fnet=F11-Ffr
Acceleration when there’s constant velocity
acceleration if its smooth or frictionless
when there’s friction an acceleration
a=[(g(m2-(μm1cosθ)-(m1sinθ)))]/m2+m1
acceleration of 2 masses on an incline (1 hanging, 1 on incline)