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torque due to a force
if a force is applied perpendicular to the object wished to be rotated from rest, the torque τ is a vector quantity whose magnitude is given by: τ = Fp r
r is the distance from the axis of rotation
torque is proportional to r and the perpendicular force applied to rotate the object
the units of torque are in Newton-meters, not Joules
if a force is applied at any angle θ relative to the object wished to be rotated from rest, the torque τ is a
vector quantity whose magnitude is given by: τ = F r sin θ
Fsinθ is the perpendicular component of the applied force which does the job of rotating
Fcosθ is the parallel component of the applied force which pushes against the hinge
torque is thus defined as the
perpendicular component of force (Fsinθ) times the actual distance from the axis of rotation (r)
if θ is smaller, the perpendicular force Fsinθ will also be smaller, until θ = 0, thus torque will also be 0
torque will always be perpendicular in direction to the plane defined by radius and force, since the vector quantity τ = the vector r x the vector F
torque also equals the
force applied (F) x the lever arm (l) which measures effective distance
the greater the lever arm, the greater the torque
τ = F l = Fsinθ r, since l = rsinθ
increasing θ increases the lever arm, and when θ = 90°, the lever arm is at its maximum and equal to r
direction of torque
if τ > 0, there is counterclockwise rotation from rest since the angles are increasing
if τ < 0, there is clockwise rotation from rest since the angles are decreasing
net torque
when multiple torques act about the same axis of an object, the net torque is the vector sum of individual torques: τnet = τ1 + τ2 + τ3 + … + τn
in the case of a rotation about a fixed axis, the torque is always parallel to the axis of rotation, so it can only be a vector pointing forward or backward along the axis
rotational inertia
an object tends to preserve its state of no rotation or rotation at a constant angular velocity unless compelled to change that state by a net external torque
consequence of Newton’s 1st law (law of inertia)
net torque results in angular acceleration, since the force applied results in a tangential acceleration
Ft gives at, τ gives α
the moment of inertia for a rigid object about an axis quantifies the
tendency to rotate with constant angular velocity about that axis
determined by the distribution of mass about an axis of rotation
it is the rotational analog of inertial mass
for regular shapes, the moment of inertia I is given by
I = bmR²
b is a dimensionless coefficient between 0 and 1
m is the total mass of the object
R is the characteristic dimension of the object
for any shape, the moment of inertia I is
I = Σ mi ri²
a solid distribution of mass has a lower moment of inertia than a hollow distribution of mass
solid cylinder: I = ½ mR²
hollow cylinder: I = mR²
solid sphere: I = 2/5 mR²
hollow sphere: I = 2/3 mR²
rod rotating in the center: I = 1/12 mL²
rod rotating at the end: I = 1/3 mL²
the net torque τ needed to change the angular velocity of a rigid object is proportional to the
moment of inertia I about the axis of rotation and the desired angular acceleration α
τnet = Iα
F = m at, and since at = rα, F = m rα, and F ri = (m rα) ri, thus τi = m r²α
I = Σ mi ri², thus Σ τi = (Σ mi ri²) α, thus τnet = Iα
if the bar is rigid, the
same force will be applied across the bar
torque will be different because the distance from the axis of rotation (r) is not the same at different points
increasing the length of the bar gives
more lever arm to the force, thus increasing the torque, and this will also increase the moment of inertia since the moment of inertia I is proportional to L²
increasing the length of the plank will make it accelerate less
the kinetic energy of an object performing a rigid rotation about a fixed axis is
K = Krot = ½ I w²
if the axis is fixed, any point on the axis will have a zero kinetic energy, since it will not be moving at all, since the angular velocity w = 0
the kinetic energy of a rigid object is due to the
translation of its center and rotation about an axis
ex. a rolling object, which performs both a translation and a rigid rotation about a moving axis has a kinetic energy K = Ktra + Krot = ½ mv² + ½ Iw²
v is the speed of the center of mass of the object
if angular velocity is changed, then rotational kinetic energy is
also changed, and work is related to the change
work-energy theorem for rotations
the work done by the net external torque acting on an object is equal to the change in its rotational kinetic energy, thus Wτ = ∆Krot = ½ Iwf² - ½ Iw0²
if an object is rotated at varying angular speed, the torque will do work
if the angular speed increases, Wτ > 0 and the torque will do positive work
if the angular speed decreases, Wτ < 0 and the torque will do negative work
if torque remains constant, the work done by torque is
Wτ = τ ∆θ
the work done by torque is equal to the magnitude of the torque times the change in angular position or angular displacement from rotation