MATE 220 EXAM 1

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Last updated 7:54 PM on 10/7/26
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75 Terms

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Unit cell

The smallest repeating structural unit of a crystal lattice.

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Lattice parameter aa

The edge length (side length) of a cubic unit cell.

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Number of atoms in a simple cubic (SC) unit cell

1 atom per unit cell1\text{ atom per unit cell}

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Number of atoms in a body-centered cubic (BCC) unit cell

2 atoms per unit cell2\text{ atoms per unit cell}

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Number of atoms in a face-centered cubic (FCC) unit cell

4 atoms per unit cell4\text{ atoms per unit cell}

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Number of atoms in a conventional hexagonal close-packed (HCP) unit cell

6 atoms per conventional unit cell6\text{ atoms per conventional unit cell}

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Atom contact direction in simple cubic (SC)

Along the cube edge.

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Atom contact direction in body-centered cubic (BCC)

Along the body diagonal.

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Atom contact direction in face-centered cubic (FCC)

Along the face diagonal.

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Relationship between aa and RR in simple cubic (SC)

a=2Ra = 2R

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Relationship between aa and RR in BCC

a=4R3a = \frac{4R}{\sqrt{3}}

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Relationship between aa and RR in FCC

a=22Ra = 2\sqrt{2}R

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Formula to find RR from aa for BCC

R=a34R = \frac{a\sqrt{3}}{4}

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Formula to find RR from aa for FCC

$$R = \frac{a}{2\sqrt{2}}$Metric

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Atomic packing factor (APF) of simple cubic (SC)

0.520.52

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Atomic packing factor (APF) of BCC

0.680.68

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Atomic packing factor (APF) of FCC

0.740.74

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Atomic packing factor (APF) of HCP

0.740.74

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APF abbreviation

Atomic Packing Factor

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Physical quantity measured by APF

The fraction of the unit-cell volume occupied by atoms.

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General APF formula

APF=volume occupied by atomstotal unit-cell volume\text{APF} = \frac{\text{volume occupied by atoms}}{\text{total unit-cell volume}}

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Volume of a cubic unit cell (VcV_c)

Vc=a3V_c = a^3

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Theoretical density equation (ρ\rho)

ρ=nAVcNA\rho = \frac{nA}{V_c N_A}

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Meaning of nn in the theoretical density equation

Number of atoms per unit cell.

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Meaning of AA in the theoretical density equation

Atomic weight (molar mass), usually expressed in g mol−1g\,mol^{-1}.

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Meaning of VcV_c in the theoretical density equation

Volume of the unit cell.

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Avogadro's number (NAN_A)

NA=6.022×1023 atoms mol−1N_A = 6.022 \times 10^{23}\,\text{atoms}\,mol^{-1}

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Calculation path from atomic radius RR to theoretical density (ρ\rho)

R→a→a3→ρR \rightarrow a \rightarrow a^3 \rightarrow \rho

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Calculation path from theoretical density (ρ\rho) to atomic radius RR

ρ→a3→a→R\rho \rightarrow a^3 \rightarrow a \rightarrow R

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Formula for a3a^3 rearranged from the theoretical density equation

a3=nAρNAa^3 = \frac{nA}{\rho N_A}

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Conversion factor from nm\text{nm} to cm\text{cm}

1 nm=10−7 cm1\,\text{nm} = 10^{-7}\,\text{cm}

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Conversion factor from cm\text{cm} to nm\text{nm}

1 cm=107 nm1\,\text{cm} = 10^7\,\text{nm}

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Cation

A positively charged ion formed when an atom loses electrons.

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Anion

A negatively charged ion formed when an atom gains electrons.

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Typical ionic charge of Group 1 elements

+1+1

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Typical ionic charge of Group 2 elements

+2+2

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Typical ionic charge of Group 13 elements

+3+3

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Typical ionic charge of Group 15 elements

−3-3

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Typical ionic charge of Group 16 elements

−2-2

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Typical ionic charge of Group 17 elements

−1-1

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Typical ionic charge of Group 18 elements

00

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Electron change during cation formation

Electrons are lost.

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Electron change during anion formation

Electrons are gained.

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Electron configuration of argon (Ar\text{Ar})

1s2 2s2 2p6 3s2 3p61s^2\,2s^2\,2p^6\,3s^2\,3p^6

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Electron configuration of K+K^+

1s2 2s2 2p6 3s2 3p6=[Ar]1s^2\,2s^2\,2p^6\,3s^2\,3p^6 = [\text{Ar}]

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Electron configuration of Cl−Cl^-

1s2 2s2 2p6 3s2 3p6=[Ar]1s^2\,2s^2\,2p^6\,3s^2\,3p^6 = [\text{Ar}]

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Reason K+K^+ and Cl−Cl^- share the same electron configuration

Both species have 18 electrons18\text{ electrons} and are isoelectronic with argon (Ar\text{Ar}).

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Ionic bonding

Electrostatic attraction between oppositely charged ions.

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Covalent bonding

Bonding in which atoms share pairs of electrons.

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Metallic bonding

Positive ion cores held together by delocalized valence electrons.

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Equilibrium spacing (r0r_0)

The interatomic distance where attractive and repulsive forces balance.

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Net force at equilibrium spacing (r0r_0)

00 (zero).

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Status of individual attractive and repulsive forces at r0r_0

They are non-zero; they are equal in magnitude and opposite in direction.

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Significance of a deeper interatomic potential-energy well

Stronger bonding and greater bond energy.

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Vacancy defect

A normally occupied lattice site that is missing an atom.

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Vacancy equation

Nv=Nexp⁡(−QvkT)N_v = N \exp\left(-\frac{Q_v}{kT}\right)

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Meaning of NvN_v in the vacancy equation

Number of vacancies per unit volume.

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Meaning of NN in the vacancy equation

Number of atomic sites per unit volume.

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Meaning of QvQ_v in the vacancy equation

Energy required to form one vacancy.

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Meaning of kk in the vacancy equation

Boltzmann's constant.

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Temperature scale required for the vacancy equation

Kelvin (K\text{K}).

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Formula to convert Celsius to Kelvin

T(K)=T(∘C)+273T(\text{K}) = T(^\circ\text{C}) + 273

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Value of Boltzmann's constant kk when QvQ_v is in eV/atom\text{eV}/\text{atom}

k=8.617×10−5 eV/(atom⋅K)k = 8.617 \times 10^{-5}\,\text{eV}/(\text{atom}\cdot\text{K})

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Formula for atomic sites per unit volume (NN)

N=ρNAAN = \frac{\rho N_A}{A}

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Effect of increasing temperature on vacancy concentration

Vacancy concentration increases exponentially.

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Substitutional impurity

An impurity atom that replaces a host atom at a regular lattice site.

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Interstitial impurity

A small impurity atom that occupies a space between host atoms.

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Weight percent (wt%\text{wt}\%) formula

wt%=(mass of componenttotal mass of alloy)×100%\text{wt}\% = \left(\frac{\text{mass of component}}{\text{total mass of alloy}}\right) \times 100\%

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Convenient assumed sample size for wt%\text{wt}\% problems

100 g of alloy100\,\text{g}\text{ of alloy}

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Masses in a 100 g100\,\text{g} sample of 15 wt% Ge15\,\text{wt}\%\,\text{Ge} and 85 wt% Si85\,\text{wt}\%\,\text{Si}

15 g Ge15\,\text{g}\,\text{Ge} and 85 g Si85\,\text{g}\,\text{Si}

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Formula to calculate volume from mass and density

V=mρV = \frac{m}{\rho}

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Formula to convert grams of an element to moles

$$\text{moles} = \frac{\text{mass}}{\text{atomic weight}}$Metric

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Formula to convert moles to number of atoms

atoms=moles×6.022×1023\text{atoms} = \text{moles} \times 6.022 \times 10^{23}

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Octahedral interstitial site

An interstitial site coordinated by 6 neighboring atoms6\text{ neighboring atoms}.

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Tetrahedral interstitial site

An interstitial site coordinated by 4 neighboring atoms4\text{ neighboring atoms}.