The equation for spring deflection is derived from?
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Pd\*Pc=π
Spur Gear: Relation of Pd and Pc
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a+d
Whole depth formula of spur
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2a
Working depth of spur gear
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cleara
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1\.157/Pd
Dedendum of 14.5 and 22.5 degrees (Pd)
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1\.25/Pd
Dedendum of 20 and 25 degrees (no decimal) in Pd
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b = (2.5 - 4)\*Pc
Face Width of Spur gear formula
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S = T + B
T = tooth thickness
B = Backlash
Space Width formula
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m = 1/ Pd
Relation of module and diametrial pitch
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Tout/Tin = Product of driven teeth/Product of driver teeth
Gear Train Formula: Ratio of Input to Output Torque and Speed Ratio
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\
Center Distance of Spur Gear Formula (External Contact)
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a = rα
a = linear acceleration (m/s^2)
r = radius
α = angular acceleration (rad/s^2)
Angular acceleration and linear acceleration formula
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Ft is from P = Ft\*V
Spur Gear: Tangential, Separating, and Normal Load formula
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cos α = Pcn/Pc
\ Pcn = normal circular pitch
Pc = transverse circular pitch
α = helix angle
Relation between Pc and Pcn on Helical Gear
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tan α = Pc/Pa
Relation between Pc and Pa in Helical Gear
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Vmax = P/2
Simple Supported Beam with Central Load: Vmax?
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Mmax = PL/4
Simple Supported Beam with Central Load: Mmax?
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ymax = PL^3/48EI
Simple Supported Beam with Central Load: ymax?
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Vmax = wL/2
Simply Supported Beam with Uniformly Distributed Load: Vmax
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Mmax = wL^2/8
Simply Supported Beam with Uniformly Distributed Load: Mmax
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ymax = wL^4/(384/5)\*EI
Simply Supported Beam with Uniformly Distributed Load: ymax
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Vmax = P
Fixed Ends with Concentrated Load (Cantilever): Vmax?
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Mmax = PL
Fixed Ends with Concentrated Load (Cantilever): Mmax?
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ymax = PL^3/3EI
Fixed End with Concentrated Load (Cantilever): ymax?
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Vmax = P/2
Fixed Both Ends with Concentrated Load (Cantilever): Vmax?
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Mmax = PL/8
Fixed Both Ends with Concentrated Load (Cantilever): Mmax?
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ymax = PL^3/192EI
Moment Diagram is superimposition of Cantilever with Pure Bending and Simply Supported With Central Load
Fixed Both Ends with Concentrated Load (Cantilever): ymax?
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A’ = Area parallel to the force
V = shearing force
t = thickness = b (width)
Transverse Shear Stress along a plane perpendicular to the force applied FORMULA (Diba ang shear stress parallel raman nga area, naa puy perpendicular)
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At neutral axis
Where is the transverse shear stress (perpendicular to applied load not parallel) maximum?
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3V/2A
Max Transverse Shear Stress of RECTANGULAR CROSS SECTION
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4V/3A
Max Transverse Shear Stress of CIRCULAR CROSS SECTION derived from VQ/It
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2V/A
Max Transverse Shear Stress of Hollow, Thin wall round cross section
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V/Aweb
Max Transverse Shear Stress of Structural I beam
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P = IE\* pi^2/Le^2
Euler’s Critical Load for BUCKLING in Struts
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= effective length / radius of gyration = Le/k
Slender Ratio of Column formula (λ)
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Yield Strength
What strength is considered for DUCTILE materials
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Ultimate Strength
What strength is considered for BRITTLE materials
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Le = 2L
Effective length (Le) if one end fixed and one end free
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Le = L
Effective length (Le) if Both ends pinned
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Le = 0.707 L
Effective length (Le) if One end fixed and one end pinned
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Le = 0.5 L
Effective length (Le) if both ends fixed
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λ > 120
Slenderness ratio for LONG columns (λ)
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λ < 10
Slenderness ratio for SHORT columns (λ)
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One fixed and one free (Le = 2L)
If Column is cantilever, what type of strut is that?
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CRITICAL SPEED FORMULA
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τ = σy / sqrt(3)
\ If you play with your toy, squirt.
According to MAXIMUM SHEAR STRESS THEORY, what is the MAX SHEAR YIELD STRESS?
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tan(θ) \* 100% = V^2/rg
\ Remember: %grade in elevation is just the slope x 100%
Superelevation in percent of banked curve formula
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0\.5\*(PL/AE)
Deformation/Elongation DUE TO OWN WEIGHT formula
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σcmax = σnormal + σbend
\ NOTE: Left side kay compressive (downward) while right side kay tensile (upward)
What is the maximum compressive stress in eccentrically loaded shafts/beams (compressive force)
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σtmax = σbend - σnormal
\ NOTE: Ang compressive normal stress kay negative while positive ang bending stress mao i-subtract
What is the maximum tensile stress in eccentrically loaded shafts/beams (compressive force)
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v = poisson ratio
σ = tensile stress
ε = tensile strain
\ //x-(y+z)
strain formula for MULTI-AXIAL STRESS
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Max Shear Stress if given tensile and shear stress FORMULA
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Principal stresses
These are maximum and minimum NORMAL stresses that occur when the stress element is rotated such that shear stress is zero
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Vertical force
\ \*Moment results in PURE BENDING while a vertical force creates BENDING and TRANSVERSE SHEARING.
Which of the two would cause transverse shearing on a beam (Vertical Force or Moment)
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Flanges
What part of an I-beam carries the BENDING MOMENT
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Web
What part of an I-beam carries the SHEARING FORCE
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τ = T/(2\*Am\*t)
\ USE ONLY IF THICKNESS IS GIVEN WITH AREA
τ = shear stress
T = torque
Am = mean cross section area
t = thickness of tube
Stress and Torque for THIN-WALLED TUBES Formula
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KE = 0.5\*Iω^2
where:
I = moment of inertia of hollow cylinder
I = 1/2 m(R^2 + r^2)
In Flywheel, if given inner and outer radius, what is the KE formula?
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U = 1/2 Fδ = 1/2 Tθ
\ Similar to U = 1/2 k\*x in springs
Formula for the ENERGY ABSORBED by shaft due to stopping
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Fmax = Fpre + Pmax\*e
\ Fpre = preloaded force
Pmax = max external force applied
e = joint coefficient
MAX BOLT LOAD Formula given joint coefficient
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F = Central Load / 2
L = Total length / 2 = Effective Length / 2
\ S = 6FL/b**n**t^2
\ y = SL^2/Et \* 2**n**/(2ng+3nf)
\ **n** = ng + nf
ng = # of graduated leaves
nf = # of full leaves
In semi elliptical leaf springs, what is F, L, S and y?
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E = 12 x 10^6 psi
WIRE ROPE: Modulus of Elasticity (E)
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dw = 0.067(dr) (in)
\ dr = rope diameter
WIRE ROPE: Wire diameter (dw)
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Am = 0.38(dr)^2 or = 0.4 (dr)^2 (sq. in)
WIRE ROPE: Metallic Area (Am)
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ω 1.58(dr)^2 (lb/ft)
WIRE ROPE: Weight per unit Length (ω)
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σd = (Wload + Wr)/Am
\ Wload = weight of load
Wr = weight of rope
WIRE ROPE: Direct Stress (σd)
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σb = E \* (dw/ds)
\ E = modulus of elasticity of rope
dw = wire diameter NOT rope diameter
ds = Sheave diameter
WIRE ROPE: Bending Stress (σb)
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Ft = (Wload + Wr) \* (1 ± a/g)
Ft = (σd + σb)\*(Am)
\ Use (+) for RAISING
Use (-) for LOWERING
WIRE ROPE: Total Tensile Load (Ft) 2 FORMULAS
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Fb = σb\*Am = E \* (dw/ds) \* Am
WIRE ROPE: Bending Load (Fb)
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FS = (Fu - Fb)/Ft
\ Fu = Ultimate strength
Fb = Bending Load
Ft= total tensile strength
\ Another way to interpret is Rated Load - Losses/ Actual Load. I-minus ang bending load kay losses na.
WIRE ROPE: Factor of Safety (FS)
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Fu = 76,000 (dr)^2 (lbs)
WIRE ROPE: Ultimate Strength (Fu)
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Pitch = (Digits before last digit)/8
\ Ex. #40: P = 4 \* 1/8 = 0.5 in
Ex. #100: P = 10 \* 1/8 = 1.25 in
Pitch of Roller Chain from Chain Number?
Ex. Roller no. 40
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Tshaft = Twheel \* (SMALLER RATIO)
\ Ex. 40:11 ; Smaller ratio = 11/40
T wheel = Load\*(1/2) \*(Dw/2)
\ //See #13 of RF-MT-3D
If given ratio of differential, what is the torque on the shaft to get shear stress on shaft