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If an alkene reacts with KMnO4 / H2O/ OH-
forms a vicinal diol (2 OH groups on carbons next to each other), does not cut the double bond
If an alkene reacts with KMnO4 / H3O+
it leads to oxidative cleavage of the double bond, yielding ketones or carboxylic acids
If an alkene reacts with KMnO4 / H3O+ and the first carbon is attached to no hydrogen:
it will yield a ketone
If an alkene reacts with KMnO4 / H3O+ and the first carbon is attached to 1 hydrogen:
it will yield a carboxylic acid
If an alkene reacts with Br2,
it will break the double bondand add bromine atoms across the double bond, resulting in a vicinal dibromide.
If an alkene reacts with HBr
it will add hydrogen and bromine across the double bond in a Markovnikov manner, resulting in an alkyl bromide.
If an alkene reacts with H2O/H2SO4
it will add water across the double bond in a Markovnikov manner, resulting in an alcohol.
If an alkyne reacts with 2H2/Pd
it will undergo hydrogenation resulting in an alkane.
If an alkyne reacts with with H2/Lindlar
it will result in a cis-alkene through partial hydrogenation.
If an alkyne reacts with H2O/HgSO4/H2SO4
it will form a ketone, specifically through acid-catalyzed hydration in a Markovnikov manner.