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IRE
Image Receptor Exposure
-kVp & mAs
When you have an underexposed IRE you should...
increase the exposure factors (kVp and mAs)
When you have an overexposed IRE you should...
decrease exposure factors
Controlling Factor of the IRE
mA and time (mAs)
mAs and IRE relationship
directly proportional (twins), whatever you do to one the same happens to the other
-if mAs doubles, the amount of radiation exiting the tube doubles
mAs only affects
quantity or amount of radiation making it the QUANTITATIVE FACTOR
-nothing to do with penetration
Time of exposure
actual duration of x-ray production, in seconds
Time of exposure and IRE relationship
directly proportional, quantity of radiation produced & time exployed
mAs
the amount of electron charge transferred from cathode to anode during the exposure (mA x time)
As mAs is increased
quantity of radiation is increased and IRE is increased
-and vice versa
What % change in mAs in necessary to see a visible change on the radiographic image?
30% (50% for clinic because it's easier to divide by 2)
Example of applying the 50% rule for change in mAs.
45 mAs, too underexposed, what is the new mAs?
45/2 =22.5
22.5 + 45 = ~70 mAs
Primary Influencing Factor
kVp (but is more powerful than mAs)
kVp
quality factor of the beam controlling the penetrating ability of the beam & speed of electrons
kVp affects
quality and quantity
kVp and penetration relationship
direct
increasing kVp, increases penetration
kVp and absorption relationship
inverse
increasing kVp, decreases absorption (going faster so it will penetrate rather than this)
Subject contrast
the difference in intensity between different areas of the image carried by the remnant beam, created by the xray absorption characteristics of different body tissues
-the ability to look at a radiograph and see different between neighboring structures
kVp and subject contrast relationship
inverse
increasing kVp, decreases subject contrast
-ex. abdomen (lots of greys) vs finger (black and white)
kVp and IRE relationship
direct but not directly proportional, increase in kVp increases IRE but by a lot
kVp must be used to ___________ the part, and mAs to _______________
penetrate (bony tissue); produce proper IRE (soft tissue delineation)
15 % rule
a 15% change in kVp is equivalent to double or half the mAs
can mAs compensate for inadequate kvp?
No because we won't be able to penetrate the bone with mAs
To maintain exposure to image receptor
-Increase mA and proportionally decrease time
-Increase time and proportionally decrease mA
-Increase kVp 15% and decrease mAs by half
-Decrease kVp 15% and increase mAs by two times (not done often because we want low mAs)
increase kVp by 15%
decrease mAs by half
Decrease kVp by 15%
increase mAs by 2 times (double mAs)
-not done often
For patient safety you always want...
high kVp and low mAs
To increase exposure to image receptor
increase mA, exposure time, or kVp (and vice versa to decrease)
Digital image receptors have...
wide dynamic range (many exposure factors can provide an image)
Image brightness is not dependent on...
mAs and kVp
What else influences IRE?
Patient Factors
Distance
Beam Limiting Devices (collimator)
Grids
Filters
Anode Heel Effect
Source-to-Image Receptor Distance (SID)
distance measured between the focal spot (target) of an x-ray tube to the image receptor (IR)
object-to-image receptor distance (OID)
The distance between the subject/ object and the image receptor (IR)
source-to-object distance (SOD)
distance from the source (focal spot/target) to object/subject
SID is a
secondary influencing factor for IRE
-as this is changed a noticeable difference in IRE is produced
As distance increases... (SID)
the total area influenced by the beam increases, decreasing IRE
SID and IRE Relationship
Inverse square law, as SID increases, IRE decreases as a result of the square of the distances (and vice versa)
inverse square law
numerically illustrates what happens to the intensity of radiation as distance changes
-used for exposure to pt., tech, air or the entrance skin exposure
Because intensity of radiation changes with SID changes we must use the...
mAs distance formula (direct) to maintain IRE regardless of SID changes
mAs distance formula
mAs new/mAs old = D new^2/D old^2
-direct square law, direct relationship
-used for changes to the control panel
Object-image distance (OID) vs IRE Relationship
inverse relationship
-increase in OID causes a decrease in IRE because the remnant beam will scatter before reaching the IR
A double/ half in SID (by 2) changes IRE by a factor of
4, this is the greatest influence on IRE
ex. Increasing the SID by 2 times, decreases IRE by a factor of 4
Beam Limitation Devices vs IRE relationship
inverse relationship
-increase collimation (reduce beam), you decrease exposure
Grids
limit the amount of scatter radiation reaching the IR
Grids vs IRE relationship
inverse relationship
-using a grid, removes scatter/photons, which will reduce the amount of IRE
Filters vs IRE relationships
inverse
-increase filters will absorb the low or soft energy photons, which will reduce the IRE slightly
When adding a grid (kVp)
you add to the original kVp
When taking away a grid (kVp)
you subtract from kVp
Grid Sizes (in order)
5:1
6:1
8:1
10:1 & 12:1
16:1
kVp addition or subtraction units for Grids (in order)
8
12
20
23
25
If the field size is increased from the the beam limitation device (decrease collimation)
the amount of tissue irradiated is increased, increasing the amount of secondary and scatter radiation, increasing IRE
- MORE MATTER, MORE SCATTER
do we ever square mAs or kVp?
No, we square distance
Uneven changes in SID and want to quantify the rate at which exposure is changing
use the mAs maintenance formula and plug in 10 for mAs old and solve for the mAs new