Chem U1 IAL pp mistakes [2020-2023]

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State what happens to nuclear charge, shielding and effective nuclear charge:
- down the group
- across the period

  • down the groupboth nuclear charge and shielding increases so effective nuclear charge is almost same(very slight increase)

  • Across the period nuclear charge increases while shielding remains same so effective nuclear charge increases


NOTE:
Nuclear charge = the actual positive charge of the nucleus, determined by the number of protons

effective nuclear charge = nuclear charge - shielding

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<p></p>
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= 5.4 * 10 ^ 23

= 3.9 * 10 ^ 23

= 6.02 x 10^23

= 4.5 * 10 ^ 23

so you can see C has most no. of ions

<p>= 5.4 * 10 ^ 23</p><p>= 3.9 * 10 ^ 23</p><p>= 6.02 x 10^23</p><p>= 4.5 * 10 ^ 23<br><br>so you can see C has most no. of ions</p>
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C
carbon because it has 4 valence electron and giant covalent structure

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Explain the difference in the first ionisation energies of chlorine and bromine.

(3 marks)

  • chlorine has higher first I.E than Br

  • because down the grp shielding and nuclear charge increases,soclorine's outermost electron experiences less shielding effect

  • Chlorine's outermost electron is also in a lower energy level and so closer to the nucleus [3p] than bromine [4p]
    ( thus more energy is needed for ionisation)


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<p></p>



<p></p>
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<p>Label R, S and T</p>

Label R, S and T

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Explain whether Al or Mg has a greater first I.E
(3marks)

  • magnesium has greater first I.E than Al

  • because Al outermost electron is in a higher level 3p and so it experiences more shielding so it has less first I.E

  • Mg outermost electron is in 3s, so less shielding and more first I.E


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15
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<p>(ii) give the reagents needed for reaction 2</p>

(ii) give the reagents needed for reaction 2

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<p>plot a graph of this data</p>

plot a graph of this data

NOTE:
always try to distribute the numbers as much as you can,
like lowest value is 3.87 and highest 4.07

So instead of starting from 0 or 3, start from 3.85 or 3.80 and end at 4.10 or 4.5

<p>NOTE:<br>always try to distribute the numbers as much as you can, <br>like lowest value is 3.87 and highest 4.07<br><br>So instead of starting from 0 or 3, start from 3.85 or 3.80 and end at 4.10 or 4.5</p>
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the 4th I.E of sodium is around 3.995 KJ mol-1 in log10,
what is the I.E in KJ mol-1?

logbaseanswer = power format basically


<p>log<sub>base</sub>answer = power   format basically<br><br></p>
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Chromium most commonly exhibits +3 and +6

thus it is Cr2O3

<p><span>Chromium most commonly exhibits </span><strong><mark data-color="yellow" style="background-color: yellow; color: inherit;">+3</mark></strong><mark data-color="yellow" style="background-color: yellow; color: inherit;"> and </mark><strong><mark data-color="yellow" style="background-color: yellow; color: inherit;">+6</mark></strong><br><br><strong><mark data-color="yellow" style="background-color: yellow; color: inherit;">thus it is Cr2O3</mark></strong></p>
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NOTE, the conditions for pV = nRT

p(Pressure) = in Pa not Kpa

Volume (V) must be in m3

T(temperature) must be in K
where 1K = 1 C + 273
(or 1C = 1K -273)

<p>NOTE, the conditions for pV = nRT<br><br>p(Pressure) = in Pa not Kpa<br><br>Volume (V) must be in<mark data-color="yellow" style="background-color: yellow; color: inherit;"> m<sup>3</sup></mark><br><br>T(temperature) must be in K<br>where 1K = 1 C + 273<br>(or 1C = 1K -273)</p>
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  • reduce pollution

  • renewable

  • reduce waste going to landfill


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both double bonds in isoprene have two atoms of hydrogen on one end / need to have different groups on both ends to form geometric isomers

Allow two identical groups / atoms are attached to one carbon of the double bond

<p>both double bonds in isoprene have two atoms of hydrogen on one end / need to have different groups on both ends to form geometric isomers <br><br>Allow two identical groups / atoms are attached to one carbon of the double bond</p>
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Explain why first I.E of sulfur is less than phosphurus (2marks)


  • electron being removed from sulfur is paired electron in p orbital but for phospurus it is unpaired electron in p orbital

  • repulsion between paired electrons means less energy is needed to remove them



There must be a mention of p (orbital)

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The peak with the highest m/z value is the molecular ion (M ) peak

so i.e it is 256/1 = 256

my idea was right for (ii) but the notation for formula of stable ion is S2+ not what i wrote

<p><strong><u><mark data-color="yellow" style="background-color: yellow; color: inherit;">The peak with the highest m/z value is the molecular ion</mark></u></strong> (M ) peak<br><br>so i.e it is 256/1 = 256 <br><br>my idea was right for (ii) but the notation for formula of stable ion is S2+ not what i wrote</p>
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  • both solutions will turn colorless

  • bromine water goes from orange to colorless while acidified kMno4 goes from purple to colorless (when alkene is added)


<ul><li><p><strong><u>both solutions will turn colorless</u></strong> </p></li><li><p>bromine water goes from <strong><u>orange to colorless </u></strong>while acidified kMno4 goes from<strong><u> purple to colorless (when alkene is added)</u></strong></p></li></ul><p></p>
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<p>Draw the mechanism for the formation of 1-bromo-2-chloropropane in this reaction. Include curly arrows, and relevant lone pairs. (3marks)<br><br>complete the following mechanism in pic</p>

Draw the mechanism for the formation of 1-bromo-2-chloropropane in this reaction. Include curly arrows, and relevant lone pairs. (3marks)

complete the following mechanism in pic

ooof everything right just forgot to give the highlighted arrow

for the second Q forgot to give H+……..

<p>ooof everything right just forgot to give the highlighted arrow<br><br>for the second Q forgot to give H+……..</p>
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Suggest 3 properties that make squalane a liquid alkane useful in cosmetics.

1) inert / unreactive

2) colorless & odorless

3) non-toxic

[alkanes are inert, non toxic colorless and odorless]

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got everything except the hydrogenation concept:

6 hydrogenation occured meaning 6 double bonds broke, so 6 C=C present

(when alkene undergoes hydrogenation double bond breaks and it becomes alkane)

<p>got everything except the hydrogenation concept:<br><br> 6 hydrogenation occured meaning 6 double bonds broke, so 6 C=C present</p><p>(when alkene undergoes hydrogenation double bond breaks and it becomes alkane)</p>
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 restricted rotation about/around C=C

 (only) central C=C has two different groups attached to each carbon of the C=C

<p> restricted rotation about/around C=C <br><br> (only) central C=C has two different groups attached to each carbon of the C=C</p>
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<p>Give a reason for adding cycloalkane to petrol </p>

Give a reason for adding cycloalkane to petrol

prevents knocking

<p><strong><mark data-color="yellow" style="background-color: yellow; color: inherit;">prevents</mark></strong> knocking</p>
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<p>Give the reagent and condition needed for Reaction 2.</p>

Give the reagent and condition needed for Reaction 2.

Alkene + H20 → Alcohol

reagent = H20

condition = phosphoric acid



[reagentreacts with starting material while condition is the setup like an acid or temperature]

<p><mark data-color="yellow" style="background-color: yellow; color: inherit;">Alkene  + H20 → Alcohol<br><br>reagent = H20<br><br>condition = phosphoric acid</mark><br><br><br>[reagentreacts with starting material while condition is the setup like an acid or temperature]</p>
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"pentene" is an incomplete chemical name cause double bond can be in any place
so you have to specify like i.e pent-2-ene

<p>"pentene" is an incomplete chemical name cause double bond can be in any place<br>so you have to specify like i.e pent-2-ene</p>
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600 cm3 = ? m3

600 cm3 = 600×10-6 m3

<p>600 cm<sup>3 </sup> = 600×10<sup>-6</sup> m<sup>3</sup></p>
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<p>balance the equation</p>

balance the equation

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Ammonium iron(II) sulfate, (NH4)2Fe(SO4)2·6H2O, is a double salt that is used as a source of iron(II) ions.

<p>Ammonium&nbsp;iron(II)&nbsp;sulfate, <strong>(NH4)2Fe(SO4)2·6H2O</strong>, is a <strong>double salt</strong> that is used as a source of iron(II) ions.</p>
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as you go down group 1, MP decreases so:
Lithium (Li) has a higher melting point than rubidium (Rb)

<p>as you go down group 1, MP decreases so:<br><span><strong>Lithium (Li)</strong></span> has a higher melting point than <strong>rubidium (Rb)</strong></p>
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A is correct

D is incorrect because it is E-1-chlorobut-2-ene

<p>A is correct<br><br>D is incorrect because it is E-1-chlorobut-2-ene</p>
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<p>State the bond angle of Cl-Be-Cl of BeCl2 (g) and solid state polymeric berylium chloride</p>

State the bond angle of Cl-Be-Cl of BeCl2 (g) and solid state polymeric berylium chloride

BeCl2 (g) has 2 bp and 0 lp so bond angle is 180 degrees

BeCl2 solid from the diagram we can see has 4 bp and 0lp, so it should be tetrahedral and therefore bond angle of 109.5 degrees

<p>BeCl2 (g) has 2 bp and 0 lp so bond angle is 180 degrees<br><br>BeCl2 solid from the diagram we can see has 4 bp and 0lp, so it should be tetrahedral and therefore bond angle of 109.5 degrees</p>
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  • silicon dioxide has giant covalent structure and strong covalent bonds

  • these bonds need a lot of energy to break and thus they have high MP

  • SiO2 has no delocalised electrons so is an electrical insulator


    (Si can form 4 bonds and it has 4 BP with Oxygen so no delocalised electrons)


<ul><li><p>silicon dioxide has <strong><u><mark data-color="yellow" style="background-color: yellow; color: inherit;">giant covalent structure</mark></u></strong> and <strong>strong <u><mark data-color="yellow" style="background-color: yellow; color: inherit;">covalent</mark></u> bonds</strong><br></p></li><li><p>these bonds need a <strong><u>lot of energy to break</u></strong> and thus they have high MP<br></p></li><li><p><strong><u>SiO2 has no delocalised electrons</u></strong> so is an electrical insulator<br><br><br>(Si can form 4 bonds and it has 4 BP with Oxygen so no delocalised electrons)</p></li></ul><p></p>
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Give 2 possible reasons for producing hydrogen from aluminium rather than from fossil fuels


Explain the main hazard when using butane as a fuel in a portable heater in an enclosed space.
[2marks]

  • reduces CO2 emission which contributes to Global warming

  • Fossil fuels are non-renewable but aluminium can be recycled


    - in an enclosed space lot of Carbon monoxide can be produced
    - CO binds to haemoglobin irreversibly causing breahting difficulty


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<p>give the name and structural formula for product 3 and 4</p>

give the name and structural formula for product 3 and 4

alkene + acidified kmno4 = alcohol diol

but-1-ene + steam forms butan-2-ol as that 2nd C is more stable according to markivnovs law

<p>alk<strong>ene</strong> + <strong>acidified kmno4</strong> = alcohol <strong><u><mark data-color="yellow" style="background-color: yellow; color: inherit;">diol</mark></u></strong><br><br><strong>but-1-ene + steam forms butan-2-ol</strong> as that 2nd C is more stable according to markivnovs law</p>
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what i drew in red is WRONG, cuz that gives poly(but-2-ene) and we want poly(but-1-ene),
so draw with the ethyl group

(NOT 2 methly groups on 2 carbons)

<p>what i drew in red is WRONG, cuz that gives poly(but-2-ene) and we want poly(but-1-ene), <br>so draw with the ethyl group <br><br>(NOT 2 methly groups on 2 carbons)</p>
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