Chem II Lab Final

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/47

encourage image

There's no tags or description

Looks like no tags are added yet.

48 Terms

1
New cards

Rate equation for reactants

Rate = -Δ[reactant]/Δt

2
New cards

Rate equation for products

Rate = Δ[product]/Δt

3
New cards

Overall reaction order

The sum of all individual exponents in the rate law.

4
New cards

Determining individual reaction orders

Use the method of initial rates and compare rate changes with concentration changes.

5
New cards

Rate law expression from data

Rate = k[A]^m[B]^n, solving for m and n using experimental data.

6
New cards

Effect of increasing concentration on reaction rate

It increases the frequency of collisions, which increases the rate.

7
New cards

Effect of increasing temperature on reaction rate

It increases particle energy, making collisions more effective.

8
New cards

Half-reaction method

Split the reaction into oxidation and reduction half-reactions, balance each, and then combine.

9
New cards

Rate constant (k)

A proportionality constant in the rate law that depends on temperature.

10
New cards

Monodentate ligand

A ligand that donates one pair of electrons to the metal.

11
New cards

Bidentate ligand

A ligand that donates two pairs of electrons to the metal.

12
New cards

Electromagnetic radiation arranged by frequency

Gamma > X-ray > UV > Visible > IR > Microwave > Radio.

13
New cards

Electromagnetic radiation arranged by wavelength

Radio > Microwave > IR > Visible > UV > X-ray > Gamma.

14
New cards

Purpose of color wheel

Helps determine the complementary color of a solution based on absorbed wavelength.

15
New cards

Equation for energy of radiation

E = hν or E = hc/λ.

16
New cards

Beer-Lambert Law

A = εbc, where A is absorbance, ε is molar absorptivity, b is path length, and c is concentration.

17
New cards

Absorbance calculation from transmittance

A = -log(T), where T = %T/100.

18
New cards

% transmittance calculation from absorbance

%T = 10^(-A) × 100.

19
New cards

Reaction quotient (Q)

Q = [products]^coeff / [reactants]^coeff using current concentrations.

20
New cards

Equilibrium constant (Kc)

Kc = [products]^coeff / [reactants]^coeff at equilibrium.

21
New cards

Calculating Kc from quantities

Plug equilibrium concentrations into Kc expression.

22
New cards

Le Châtelier’s Principle

A system at equilibrium will shift to oppose a disturbance.

23
New cards

Effect of concentration increase on equilibrium

The system shifts to consume the added substance.

24
New cards

Behavior of K with concentration changes

K remains constant unless temperature changes.

25
New cards

Effect of temperature increase on equilibrium in exothermic reaction

It shifts left; K decreases.

26
New cards

Effect of temperature increase on equilibrium in endothermic reaction

It shifts right; K increases.

27
New cards

Dissociation reaction of strong acid HCl

HCl → H⁺ + Cl⁻.

28
New cards

Dissociation reaction of weak acid HA

HA ⇌ H⁺ + A⁻.

29
New cards

Ka expression for weak acid

Ka = [H⁺][A⁻]/[HA].

30
New cards

Calculating [H3O⁺] from pH

[H3O⁺] = 10^(-pH).

31
New cards

Calculating [OH⁻] from pOH

[OH⁻] = 10^(-pOH).

32
New cards

Relationship between pH and pOH

pH + pOH = 14.

33
New cards

Calculating Ka from initial and equilibrium concentrations

Use ICE table and plug values into Ka = [H⁺][A⁻]/[HA].

34
New cards

Finding equilibrium concentrations from Ka and [HA]initial

Use an ICE table and solve for unknowns.

35
New cards

Determining acidity of a salt solution

Based on the nature of the cation and anion (acidic, basic, or neutral).

36
New cards

Components of a buffer

A weak acid and its conjugate base (or vice versa).

37
New cards

Buffer with highest capacity

One with high, equal concentrations of acid and base.

38
New cards

Calculating pH of a buffer

Use Henderson-Hasselbalch: pH = pKa + log([A⁻]/[HA]).

39
New cards

Dissolution equation for AgCl

AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq).

40
New cards

Ksp expression for AgCl

Ksp = [Ag⁺][Cl⁻].

41
New cards

Comparing Ksp values

Higher Ksp indicates more soluble in water.

42
New cards

Effect of temperature on Ksp in endothermic process

Ksp increases with temperature.

43
New cards

Effect of temperature on Ksp in exothermic process

Ksp decreases with temperature.

44
New cards

Calculating solubility from Ksp

Set up ICE table and solve using Ksp = x² (or other forms).

45
New cards

Common ion effect

Solubility decreases in the presence of a common ion.

46
New cards

Calculating temperature for spontaneity

T = ΔH° / ΔS°.

47
New cards

Gibbs Free Energy equation

ΔG° = ΔH° – TΔS°.

48
New cards

Condition for spontaneous reaction

When ΔG° < 0.