Chapter 10 Key Equations: Rotational Dynamics

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Vocabulary flashcards mapping each rotational motion concept and theorem to its corresponding key formula from Chapter 10 of University Physics Volume 1.

25 Terms

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Angular position

θ=sr\theta = \frac{s}{r}

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Angular velocity

ω=lim⁡Δt→0ΔθΔt=dθdt\omega = \lim_{\Delta t \to 0} \frac{\Delta \theta}{\Delta t} = \frac{d\theta}{dt}

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Tangential speed

vt=rωv_t = r\omega

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Angular acceleration

α=lim⁡Δt→0ΔωΔt=dωdt=d2θdt2\alpha = \lim_{\Delta t \to 0} \frac{\Delta \omega}{\Delta t} = \frac{d\omega}{dt} = \frac{d^2\theta}{dt^2}

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Tangential acceleration

at=rαa_t = r\alpha

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Average angular velocity

ωˉ=ω0+ωf2\bar{\omega} = \frac{\omega_0 + \omega_f}{2}

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Angular displacement

θf=θ0+ωˉt\theta_f = \theta_0 + \bar{\omega}t

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Angular velocity from constant angular acceleration

ωf=ω0+αt\omega_f = \omega_0 + \alpha t

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Angular velocity from displacement and constant angular acceleration

θf=θ0+ω0t+12αt2\theta_f = \theta_0 + \omega_0 t + \frac{1}{2}\alpha t^2

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Change in angular velocity

ωf2=ω02+2α(Δθ)\omega_f^2 = \omega_0^2 + 2\alpha(\Delta\theta)

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Total acceleration

a⃗=a⃗c+a⃗t\vec{\mathbf{a}} = \vec{\mathbf{a}}_c + \vec{\mathbf{a}}_t

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Rotational kinetic energy

K=12(∑jmjrj2)ω2K = \frac{1}{2}\left(\sum_j m_j r_j^2\right)\omega^2

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Moment of inertia

I=∑jmjrj2I = \sum_j m_j r_j^2

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Rotational kinetic energy in terms of the moment of inertia of a rigid body

K=12Iω2K = \frac{1}{2}I\omega^2

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Moment of inertia of a continuous object

I=∫r2 dmI = \int r^2\,dm

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Parallel-axis theorem

Iparallel-axis=Icenter of mass+md2I_{\text{parallel-axis}} = I_{\text{center of mass}} + md^2

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Moment of inertia of a compound object

Itotal=∑iIiI_{\text{total}} = \sum_i I_i

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Torque vector

τ⃗=r⃗×F⃗\vec{\boldsymbol{\tau}} = \vec{\mathbf{r}} \times \vec{\mathbf{F}}

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Magnitude of torque

∣τ⃗∣=r⊥F|\vec{\boldsymbol{\tau}}| = r_{\perp} F

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Total torque

τ⃗net=∑iτ⃗i\vec{\boldsymbol{\tau}}_{\text{net}} = \sum_i \vec{\boldsymbol{\tau}}_i

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Newton's second law for rotation

∑iτi=Iα\sum_i \tau_i = I\alpha

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Incremental work done by a torque

dW=(∑iτi)dθdW = \left(\sum_i \tau_i\right) d\theta

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Work-energy theorem

WAB=KB−KAW_{AB} = K_B - K_A

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Rotational work done by net force

WAB=∫θAθB(∑iτi)dθW_{AB} = \int_{\theta_A}^{\theta_B} \left(\sum_i \tau_i\right) d\theta

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Rotational power

P=τωP = \tau\omega