methods 3

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first find the range of f(x) by competing the square, then use that range(output) of the inner function as the input of the outer function. do g(-4)

<p>first find the range of f(x) by competing the square, then use that range(output) of the inner function as the input of the outer function. do g(-4)</p>
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dilation parallel to the x-axis affects the x-value. dilation parallel to the y axis affects the y value. also remember to take out the dilation factor out the brackets before doing the translation!

<p>dilation parallel to the x-axis affects the x-value. dilation parallel to the y axis affects the y value. also remember to take out the dilation factor out the brackets before doing the translation!</p>
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first, obvious one, 9/4 units up. then its dilate by factor A parallel to the x-axis and translated by factor B left/right. so do two simultaneous equations and find a and B. dont flip the dilation for A because it is simply implied.

<p>first, obvious one, 9/4 units up. then its dilate by factor A parallel to the x-axis and translated by factor B left/right. so do two simultaneous equations and find a and B. dont flip the dilation for A because it is simply implied. </p>
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when they mention, width, think about margin of error. Here they mention the new interval has a greater width, hence has a greater margin of error than the origiinal. Hence, put togehter the inequality and solve it.

<p>when they mention, width, think about margin of error. Here they mention the new interval has a greater width, hence has a greater margin of error than the origiinal. Hence, put togehter the inequality and solve it. </p>
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<p>g(x)=sin(2x)</p>

g(x)=sin(2x)

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<p>add to bound refernce</p>

add to bound refernce

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<p>function was 3lnx and 2ln(12-x) as a piecenwise function</p><p></p>

function was 3lnx and 2ln(12-x) as a piecenwise function


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<p>1/27 is the prob for large claim</p>

1/27 is the prob for large claim

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since the quadratic function has to be more than 0, it would have no roots and hence no solutions

<p>since the quadratic function has to be more than 0, it would have no roots and hence no solutions</p>
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for this to be positive, either both have to be positive or both have to be negative.

<p>for this to be positive, either both have to be positive or both have to be negative.</p>
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this is conditional probability because it is basically saying somethingn is happening, then what is the probability because of that. Its a trick question because ti doesnt expleicity say that “given” .

<p>this is conditional probability because it is basically saying somethingn is happening, then what is the probability because of that. Its a trick question because ti doesnt expleicity say that “given” . </p>
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<p>f(x)=sin(x)(1+4cos(x))</p>

f(x)=sin(x)(1+4cos(x))

Trigger: transformations to get one function to another. Action: Expand to bring both functions to same template. Sub in the transformation into the function. And then solve it term for term. equating terms.

<p>Trigger: transformations to get one function to another. Action: Expand to bring both functions to same template. Sub in the transformation into the function. And then solve it term for term. equating terms. </p>
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Trigger: for what values of the variable will there be two/one/three solutions. Action: consider odd or even values. sub in to see.

<p>Trigger: for what values of the variable will there be two/one/three solutions. Action: consider odd or even values. sub in to see. </p>
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<p>remeeber to include, n is a set of all integers and the domain for n.</p>

remeeber to include, n is a set of all integers and the domain for n.

domain of n must be to a whole no. eg, for b, cant be equalto or less than 1/4. must be 0.

<p>domain of n must be to a whole no. eg, for b, cant be equalto or less than 1/4. must be 0.</p>
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so u find x in terms of a. then find a over the domain of a. then sub in the new found value of x into y. rearrange for a over domain of y. then put the two domains together.

<p>so u find x in terms of a. then find a over the domain of a. then sub in the new found value of x into y. rearrange for a over domain of y. then put the two domains together. </p>
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check endpoints to find min or max remaining area when askig for both and u only get one answer for x

<p>check endpoints to find min or max remaining area when askig for both and u only get one answer for x</p>
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<p>figure out what combinations will get me there.</p>

figure out what combinations will get me there.

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