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3 terms a subset must satisfy
0 e W
closed under addition: if u e w then u+v e W
clsoed under scalar mulitplication if u e w, c e R, then cu e W
T or F: Every span is a subspace
T
Def of a Bases
a set of vectors is a basis for a subspace if B spans H and B is linearly independent
given a set of vectors to find the basis remove vectors that cause the set to NOT be linearly independent so it becomes linearly independent
Nul(A) (def, lives in and membership test)
Ax = 0
R^n
to test a specific u, compute Au
Col(A) (def, lives in and membership test)
spans of the comuns of A
R^m
b e Col(A) when Ax = b is consistent
Row(A) (def, lives in and membership test)
span of the rows of A or Col(A^T)
R^n
rr and compare with a basis of row space
how to find basis for Nul(A)
row reduce
solve for Ax = 0
write the sol in parametric vector form
vectors mulitple by the free variables from the basis
how to find basis for Col(A)
row reduce A to find pivot columns
select the corresponding pivot columns from the original matrix A
how to find basis for Row(A)
row reduce A to echelon form
the non zero rows form a basis
2 formula for basis
x = Pb[x]b
[x]b = Pb^-1*x
rank(A)
number of pivots
nullity(A)
number of free varibales
rank + nullity = number of columns
The basis thrm
any linearly independent set of numbers is automatically a basis
3 parts of a them that is how row operations affect determinats
multiple of 1 row added to another detB = detA
rows interchanged detB = - detA
a row is mulitpled by k then detB = kdetA
Is the matrix invertiable if the det = 0
No, the det must NOT equal 0 to be invertible
methods to find the det of a matrix (3)
cofactor expansion
choose row/colm to delete using Cij = (-1)^(i+j) * det(Aij) (pick the one with the most zeros)
if a triangluar matrix then the det(A) = product of the entries on the diagonal
crammers rule
xi = det(Ai(b))/det(A)
gives you the solution to a system
long version to find a determinant formula
a11a22a33 + a21a32a13 + a31a12a23 - a13a22a31 - a11a23a32 - a12a21a33
what is the adjugate matrix
The adjugate matrix is the transpose of the matrix of cofactors. [For instance, C12 goes in the (2, 1) position
how to know if W spans H?
vector \(\mathbf v\) spans a set \(W\), you check whether every vector in \(W\) can be written as a scalar multiple of \(\mathbf v\)
T or F: the span of any set of vectors in R³ is a subspace of R³
T
dimension of the spanned subspace is equal to
rank
def of a consistent matrix
there is NOT a pivot in the last colm
dim (Row (A) =
rank(A)
dim(nul(a)) =
nuliity = number of free variables
dimension of the space spanned by a set of vectors
equal to the rank = number of pivot columns