Velocity and Acceleration Diagrams

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Flashcards covering the graphical construction and calculation of velocity and acceleration diagrams for four-bar link mechanisms and slider-crank mechanisms.

Last updated 3:22 PM on 10/14/26
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24 Terms

1
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What key information can be obtained from a velocity and acceleration diagram of a mechanism?

The velocity and acceleration of any point relative to any other point for one particular position of the mechanism.

2
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What types of mechanical transformations can a mechanism perform in a machine?

It can convert one speed to another speed, one force to another force, one torque to another torque, force to torque, one angular motion to another angular motion, angular motion to linear motion, and linear motion to angular motion.

3
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What are the three sequential steps required to find the velocity and acceleration of a mechanism using the graphical method?

  1. Sketch space diagram
  2. Sketch velocity diagram
  3. Sketch acceleration diagram
4
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If an actual link length is 1500 mm1500\,mm and the space diagram scale is 1 cm:50 mm1\,cm : 50\,mm, what length must be drawn in the space diagram?

30 cm30\,cm, calculated as 1500 mm×1 cm50 mm=30 cm1500\,mm \times \frac{1\,cm}{50\,mm} = 30\,cm.

5
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What is the difference between absolute velocity and relative velocity?

Absolute velocity is measured from a fixed point (normally the ground or rigidly attached to the ground and not moving), whereas relative velocity is measured relative to another point that may itself be moving.

6
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What is the direction of the relative velocity of one point on a rigid link relative to another point on the same link?

It must always be perpendicular (90∘90^\circ) to the axis of the rigid link (tangential velocity).

7
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What formula calculates the tangential velocity of point BB relative to pinned point AA on link ABAB rotating at angular velocity ω\omega?

vb=ω(AB)v_b = \omega(AB) (also denoted as (vB)A(v_B)_A).

8
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In a velocity diagram, how are fixed points such as AA and DD represented?

Because there is no relative motion between fixed points, their relative velocity is zero and they are represented by a single coincident point (a,da, d).

9
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In a four-bar mechanism velocity diagram, what proportion formula is used to locate an intermediate point PP on link BCBC?

bpbc=BPBC\frac{bp}{bc} = \frac{BP}{BC}

10
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How is the angular velocity of link CDCD (ωcd\omega_{cd}) calculated from the velocity diagram?

ωcd=vcdCD\omega_{cd} = \frac{v_{cd}}{CD}

11
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In velocity diagrams, how is the velocity of a piston or slider drawn and measured?

It is measured as radial velocity and drawn along the direction of motion (line of stroke) of the piston starting from the fixed point.

12
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What two velocity components occur when a slider CC slides along a link ABAB while the link rotates about point AA?

Tangential velocity ((vc)A Tangential(v_c)_A\text{ Tangential}, represented by vector ac1ac_1) and radial velocity ((vc)A Radial(v_c)_A\text{ Radial}, represented by vector c1c2c_1c_2).

13
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Why is it important to determine the acceleration of links in a mechanism?

Because acceleration produces inertia forces in the link which stress the component parts of the mechanism.

14
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What are the two acceleration components of one point on a link relative to another?

The radial component (centripetal acceleration due to the angular velocity of the link) and the tangential component (due to the angular acceleration of the link).

15
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What formulas are used to calculate the radial (centripetal) acceleration (aR)ab(a_R)_{ab} of link ABAB?

(aR)ab=ωab2(AB)(a_R)_{ab} = \omega_{ab}^2(AB) or (aR)ab=vab2AB(a_R)_{ab} = \frac{v_{ab}^2}{AB}

16
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What is the direction of the radial (centripetal) acceleration vector for a link ABAB rotating about point AA?

It acts parallel to the link and is directed towards the centre of rotation (towards point AA).

17
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Under what condition does tangential acceleration occur in a link, and how is it calculated?

It only occurs if the link has an angular acceleration (α rad/s2\alpha\,rad/s^2), and it is calculated using (aT)ab=αab(AB)(a_T)_{ab} = \alpha_{ab}(AB).

18
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What is the orientation of the tangential acceleration vector relative to the rigid link and the velocity diagram?

It acts perpendicular to the link and parallel to the velocity diagram vector.

19
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<p>In the vector diagram shown, what does the resultant vector from $$a$$ to $$b$$ represent?</p>

In the vector diagram shown, what does the resultant vector from aa to bb represent?

The true (resultant) acceleration of BB relative to AA ((aB)A(a_B)_A), formed by vectorially adding radial acceleration aRa_R (ab1ab_1) and tangential acceleration aTa_T (b1bb_1b).

20
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In Example 1, given crank AB=80 mmAB = 80\,mm rotating at a constant speed of 480 rad/s480\,rad/s, what is the velocity vabv_{ab}?

vab=ωab×AB=480×0.08=38.4 m/sv_{ab} = \omega_{ab} \times AB = 480 \times 0.08 = 38.4\,m/s

21
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In Example 5, why is the tangential acceleration of the crank (aT)ab(a_T)_{ab} equal to zero?

Because the crank rotates at a constant angular velocity (ω=300 rad/s\omega = 300\,rad/s), meaning its angular acceleration is zero (α=0\alpha = 0).

22
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In Example 5, given (aT)bc=4000 m/s2(a_T)_{bc} = 4000\,m/s^2 and BC=0.17 mBC = 0.17\,m, what is the angular acceleration of link BCBC (αbc\alpha_{bc})?

αbc=(aT)bcBC=40000.17=23529.41 rad/s2\alpha_{bc} = \frac{(a_T)_{bc}}{BC} = \frac{4000}{0.17} = 23529.41\,rad/s^2

23
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Can an output link in a four-bar mechanism have an angular acceleration if the input link rotates at a constant speed?

Yes. Even if the input link rotates at constant speed (α=0\alpha = 0), the varying geometry causes changing angular velocity in the follower link, resulting in an angular acceleration (such as α(CD)=150000 rad/s2\alpha(CD) = 150000\,rad/s^2 in Example 8).

24
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What is the first step when constructing a velocity diagram for a slider-crank mechanism?

Determine and draw the piston's axis (line of stroke) and place the fixed point.