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what is the horizontal asymptote when the leading terms have the same degree
the leading coefficient
what is the horizontal asymptote when the leading term in the denominator dominates the numeration
y=0
what is the horizontal asymptote when the leading term in the numerator dominates the denominator
NONE
if the numerator has a degree that is exactly one more then the degree of the denominator, then f(x)
has a slant (oblique) asymptote
if the question asks you to find the end behavior as the imput values increase without bound, what does this mean
write your limit for as x—> positive infinity
to find the y-intercept of a rational function…
plug 0 in for x
what does “for what imput values of f are the output values of f equal to 0
what are the zeros
when solving for zeros you have to
watch out for holes but looking at both the numerator and the denominator
REMEMBER VERTICLE ASYMPTOTES (AKA what you are doing to find the domain) ARE NOT
ZEROS
a hole occurs ONLY when the factor in the BLANK fully cancels out with the factor in the BLANK
denominator/ numerator
there will be a verticle asymptote if the
denominator can NOT cancel out with the factors in the numerator
the rate of change is a decreasing rate when the graph is
CONCAVE DOWN
the rate of change is an increasing rate when the graph is
CONCAVE UP
the rate of change is increasing when the graph is
increasing