13.2 - Integrals of Vector Functions; Projectile Motion

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Definite Integral of a Vector-Valued Function

∫abr(t) dt=(∫abf(t) dt∫abg(t) dt∫abh(t) dt)\int_a^b \mathbf{r}(t)\,dt = \begin{pmatrix} \int_a^b f(t)\,dt \\ \int_a^b g(t)\,dt \\ \int_a^b h(t)\,dt \end{pmatrix} where r(t)=(f(t)g(t)h(t))\mathbf{r}(t) = \begin{pmatrix} f(t) \\ g(t) \\ h(t) \end{pmatrix}

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Fundamental Theorem of Calculus for Vector Functions

∫abr(t) dt=[R(t)]ab=R(b)−R(a)\int_a^b \mathbf{r}(t)\,dt = [\mathbf{R}(t)]_a^b = \mathbf{R}(b) - \mathbf{R}(a) where R′(t)=r(t)\mathbf{R}'(t) = \mathbf{r}(t)

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General Antiderivative of a Vector Function

∫r(t) dt=R(t)+C\int \mathbf{r}(t)\,dt = \mathbf{R}(t) + \mathbf{C} where R′(t)=r(t)\mathbf{R}'(t) = \mathbf{r}(t) and C=(C1C2C3)\mathbf{C} = \begin{pmatrix} C_1 \\ C_2 \\ C_3 \end{pmatrix} is a constant vector

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Velocity Vector from Acceleration

v(t)=∫a(t) dt+C1\mathbf{v}(t) = \int \mathbf{a}(t)\,dt + \mathbf{C}_1 where C1\mathbf{C}_1 is determined using the initial condition v(0)=v0\mathbf{v}(0) = \mathbf{v}_0

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Position Vector from Velocity

r(t)=∫v(t) dt+C2\mathbf{r}(t) = \int \mathbf{v}(t)\,dt + \mathbf{C}_2 where C2\mathbf{C}_2 is determined using the initial condition r(0)=r0\mathbf{r}(0) = \mathbf{r}_0

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Projectile Motion Acceleration Vector

a(t)=(0−g)\mathbf{a}(t) = \begin{pmatrix} 0 \\ -g \end{pmatrix} where g=9.8 m/s2g = 9.8\,m/s^2

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Projectile Motion Initial Velocity Vector

v(0)=(v0cos⁡(α)v0sin⁡(α))\mathbf{v}(0) = \begin{pmatrix} v_0 \cos(\alpha) \\ v_0 \sin(\alpha) \end{pmatrix} where v0v_0 is the launch speed and α\alpha is the launch angle

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Projectile Motion Velocity Vector

v(t)=(v0cos⁡(α)v0sin⁡(α)−gt)\mathbf{v}(t) = \begin{pmatrix} v_0 \cos(\alpha) \\ v_0 \sin(\alpha) - g t \end{pmatrix}

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Projectile Motion Position Vector

r(t)=(x0+(v0cos⁡(α))ty0+(v0sin⁡(α))t−12gt2)\mathbf{r}(t) = \begin{pmatrix} x_0 + (v_0 \cos(\alpha)) t \\ y_0 + (v_0 \sin(\alpha)) t - \frac{1}{2} g t^2 \end{pmatrix}

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Time to Maximum Height in Projectile Motion

t=v0sin⁡(α)gt = \frac{v_0 \sin(\alpha)}{g} which occurs when the vertical velocity component satisfies vy(t)=0v_y(t) = 0

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Horizontal Range in Projectile Motion

x(t)=(v0cos⁡(α))tx(t) = (v_0 \cos(\alpha)) t evaluated at the time of flight tt where the vertical position component satisfies y(t)=0y(t) = 0

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r(t)\mathbf{r}(t)

Position vector at time tt

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v(t)\mathbf{v}(t)

Velocity vector at time tt

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a(t)\mathbf{a}(t)

Acceleration vector at time tt

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R(t)\mathbf{R}(t)

Antiderivative vector of r(t)\mathbf{r}(t)

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C\mathbf{C}

Constant vector of integration

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gg

Acceleration due to gravity (9.8 m/s29.8\,m/s^2)

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v0v_0

Initial launch speed (magnitude)

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α\alpha

Initial launch angle (elevation)

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v0\mathbf{v}_0

Initial velocity vector at time t=0t = 0

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r0\mathbf{r}_0

Initial position vector at time t=0t = 0

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tt

Elapsed time parameter

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x0x_0

Initial horizontal position at time t=0t = 0

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y0y_0

Initial vertical position at time t=0t = 0

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vy(t)v_y(t)

Vertical velocity component at time tt