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Strength of Amines as a base
The strength depends on the availability of the lone pair on the Nitrogen
Alkyl groups have a positive inductive affect, pushing electrons towards the nitrogen, making the lone pair more available
When an Amine group is close to a benzene ring, the electrons delocalise into the ring, meaning that the lone pair on the Nitrogen is less available
Order of strength: Ammonia<Primary<Secondary<Tertiary
If an amine is attached to a phenyl group, the further away the nitrogen is from the benzene ring the stronger a base it is (regardless of other alkyl groups)
Why is the below order of compounds listed in order of pH incorrect, and what would be the correct order:
Ammonia > Phenylamine > Ethylamine
Ethylamine > Phenylamine because there is no benzene ring present, no negative inductive effect. Therefore the lone pair is more available
Ethylamine > Ammonia because there is an alkyl group attached, pushing electrons/Positive inductive effect, meaning that the lone pair is more available
Ammonia > Phenylamine because there is no benzene ring present, no negative inductive effect present, lone pair is more available
Correct order is:
Ethylamine > Ammonia > Phenylamine

What is the order of base strength of these compounds?
Weakest to strongest.
Compound E is the weakest base.
Attached to a benzene ring which has a negative inductive effect. Lone pair is less available as a result
Compound G is the second weakest base.
It is a secondary amine. Alkyl group has a positive inductive effect, pushing electrons towards the nitrogen,
The Nitrogen’s proximity to the benzene ring decreases the compound’s strength as a base
the lone pair is delocalised into the ring
Benzene ring has a negative inductive effect, making the lone pair less available
Compound F is the strongest base.
Far away from the benzene ring so that there is no interaction between the lone pair and the benzene ring.
No negative inductive effect
Alkyl group has a positive inductive effect
Lone pair on the nitrogen is more available
What is the mechanism that occurs between halogenoalkanes/haloalkanes and amines
Nucleophilic Substitution
Give an equation for the preparation of 1,6-diaminohexane by the reaction of 1,6-dibromohexane with an excess of ammonia
CHBr + 2NH →
Strength of Amines as bases order
Aromatic < NH3 < 1o < 2o
Why are tertiary amines not the strongest bases
They are not soluble because they do not have a hydrogen available to form hydrogen bonds with water