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Linear Equation
An algebraic equation in which the variables that appear are only to degree one.
A system ℒ
A system ℒ ("script L") of linear equations is a set of linear equations that are supposed to hold simultaneously.
Solution to ℒ
A solution to ℒ is an assignment of variables making all the equations true simultaneously.
S(ℒ)
If ℒ is a system of linear equations, S(ℒ) is the set of all solutions to ℒ.
ℒ is consistent
ℒ is consistent if and only if it has a solution, i.e. S(ℒ) ≠ ∅ (empty set).
ℒ is inconsistent
ℒ is inconsistent if and only if S(ℒ) = ∅ (empty set).
ℒ₁ and ℒ₂ are equivalent
ℒ₁ and ℒ₂ are equivalent if and only if S(ℒ₁) = S(ℒ₂).
Matrix
A rectangular array of numbers.
Elementary Row Operations
1) Add a multiple of a row to another row
2) Swap 2 rows
3) Multiply a row through by a nonzero number (scaling)
Row Equivalent
Two matrixes of the same size are called row Equivalent if you can get from one to the other by doing elementary row operations.
Theorem: If the augmented matrices of ℒ₁ and ℒ₂ are row equivalent, then…
They have the same solution sets: S(ℒ₁) = S(ℒ₂).
Zero row, zero column, leading term
A row that is all zeroes
A column that is all zeroes
The leading term of a nonzero row is the left most nonzero term in the row
REF
A matrix M is in REF iff:
1) all zero rows (if any) are at the bottom
2) any leading term of a row is to the right of all leading terms in the rows above it
3) all entries in the column below a leading term are zero
RREF
M is in RREF iff M is in REF and:
4) all leading terms equal 1
5) all entries in the column above a leading term are zero
Unique Matrix Theorem
Given M, it is row equivalent to a unique matrix in RREF. REFs can be different; the RREF is always unique.
The number of pivots, pivot positions, pivot rows, and pivot columns are all uniquely determined by the original matrix M.
Poison Row
A poison row is all zeros except a nonzero entry in the last positino
The Trichotomy
Given a system of linear equations ℒ, one of the three must occur:
1) ℒ has no solutions → inconsistent
2) ℒ has exactly one solution → consistent
3) ℒ has infinitely many solutions → consistent
ℒ is inconsistent (poison row version)
ℒ is inconsistent iff its augmented matrix has an REF with one or more poison rows.
A vector
A matrix with one column
Linear Combination
Suppose v₁, …, vₚ ∈ ℝⁿ and c₁, …, cₚ ∈ ℝ. Then c₁v₁ + … + cₚvₚ ∈ ℝⁿ is called "the linear combination of v₁, …, vₚ with weights c₁, …, cₚ."
b ∈ Span(v₁, …, vₚ) Theorem
Let v₁, …, vₚ, b ∈ ℝⁿ. Then b ∈ Span(v₁, …, vₚ) iff [v₁ … vₚ | b] is the augmented matrix of a consistent system, i.e. the REF of that matrix has no poison rows.
m x n matrix
Let A be a matrix w/ m rows and n columns. Say A is an m x n matrix
Identity Matrix
Iₙ = the n × n square matrix with everything 0 except 1s down the diagonal.
Ax = b
b ∈ Span(columns of A) ⟺ b is a linear combination of the columns of A ⟺ Ax = b has a solution ⟺ the REF of [A | b] has no poison rows.
Let A be an m × n matrix Theorem
The following are equivalent:
1) For all b ∈ ℝᵐ, Ax = b has a solution
2) For all b ∈ ℝᵐ, b is a linear combination of the columns of A
3) The columns of A span ℝᵐ
4) The REF of A has a pivot in every row (no zero rows)
Algebraic Properties of Ac
1) A(c + d) = Ac + Ad
2) A(λc) = λ(Ac)
For ℒ: Ax = b, Homogeneous Case
b = 0
Always consistent because there is never a poison row.
For Ax = 0, x = 0 is always a solution ("the trivial solution").
Inhomogeneous Case
Ax = b, b ≠ 0
There may be no solutions (if there is a poison row).
Suppose there are solutions, say Ap = b; then p is "a particular solution."
Nontrivial Solution Theorum
Ax = 0 has a nontrivial solution ⟺ it has infinitely many solutions (either only the trivial one or infinitely many) ⟺ it has one or more free variables (i.e. the REF of A has at least one column without a pivot).
If ℒ is homogeneous, S(ℒ) is the span of a set of "basic" vectors.
Nullspace
Nul(A) = S(Ax = 0) = {v | Av = 0}
Nullspace + Thoerum
If p is a particular solution (Ap = b), then S(Ax = b) = p + Nul(A) = {p + w | w ∈ Nul(A)}.
0 is always in the null space.
Linear Dependence
v₁, …, vₚ are linearly dependent iff c₁v₁ + … + cₚvₚ = 0 has a nontrivial solution ⟺ it has free variables.
Linearly Independent
v₁, …, vₚ are linearly independent iff the only solution to c₁v₁ + … + cₚvₚ = 0 is the trivial solution (c₁ = … = cₚ = 0).
Shortcuts:
1) 0 by itself is linearly dependent because 1·0 = 0
2) 0, v₂, v₃, v₄ is linearly dependent
3) If some vectors are linearly dependent and we add more vectors to them, the new set stays linearly dependent
4) If a set of vectors is linearly independent, then any subset is also linearly independent
5) A single vector v is linearly dependent iff v = 0
6) v₁, v₂ are linearly dependent ⟺ one of them is a scalar multiple of the other
Linearly Dependent Theorems 1 and 2
1) Let v₁, …, vₚ ∈ ℝᵐ. They are linearly dependent ⟺ one of them is a linear combination of the others.
2) Let v₁, …, vₚ ∈ ℝᵐ. If p > m, they are automatically linearly dependent (p = # of vectors > m = max # of pivots).
Domain and Codomain
Let f: S → U be a map.
Domain(f) = S
Codomain(f) = U
The domain is the inputs. The codomain is where the outputs land.
Image Definition
If s ∈ S, f(s) is the "image" of s under f.
Pre-image and Range Definition
If u ∈ U, the pre-image of u = {s ∈ S | f(s) = u}.
Range(f) = {f(s) | s ∈ S}, "everything that gets outputted."
Onto
f is onto iff Range(f) = U.
One-to-one definition
f is one-to-one iff f(s₁) = f(s₂) ⟹ s₁ = s₂.
Kernel
The kernel of T = Ker(T) = {x ∈ ℝⁿ | T(x) = 0} = the preimage of 0.
One-to-one Kernel Theorem
If T: ℝⁿ → ℝᵐ is linear, T is one-to-one iff Ker(T) = {0}.
Standard Basic Vectors
The standard basis vectors e₁, …, eₙ of ℝⁿ are the columns of Iₙ = the n × n identity matrix.
Standard Matrix of T Theorem
Let T: ℝⁿ → ℝᵐ be a linear map. Then there exists a unique m × n matrix A such that T(x) = Ax for all x ∈ ℝⁿ. In fact A = [T(e₁) … T(eₙ)].
A = "the standard matrix of T."
Summary Theorem
Let T: ℝⁿ → ℝᵐ be linear, with standard matrix A (A is an m × n matrix and T(x) = Ax).
1) T is onto iff for all b ∈ ℝᵐ, T(x) = b has a solution
2) T is onto iff the columns of A span ℝᵐ, which holds iff REF(A) has a pivot in every row
3) T is one-to-one ⟺ (T(x) = T(y) ⟹ x = y) ⟺ Ker(T) = {0}, where Ker(T) = {x ∈ ℝⁿ | T(x) = 0}
4) T is one-to-one iff Nul(A) = {0}
Matrix Multiplication
A is m × p, B is p × n. Write B = [b₁ … bₙ].
Then AB = [Ab₁ Ab₂ … Abₙ].
Standard Matrix of UT
Suppose A is the standard matrix of T, so T(x) = Ax.
Suppose B is the standard matrix of U, so U(y) = By.
(UT)(x) = U(T(x)) = U(Ax) = B(Ax) = (BA)x
So BA is the standard matrix of UT.
Transpose
Let A be an m × n matrix. Aᵀ = A transpose = the n × m matrix you get from A by swapping rows and columns.
Transpose Theorums
a) (Aᵀ)ᵀ = A
b) (A + B)ᵀ = Aᵀ + Bᵀ
c) (λA)ᵀ = λAᵀ
d) (AB)ᵀ = BᵀAᵀ