Chapter I: Solutions and the Phenomenon of Solubilization

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Flashcards covering Chapter I: Solutions and the phenomenon of solubilization, including concentration expressions, normality, electrolytes, and the Debye–Hückel model.

20 Terms

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What is an aqueous solution, and how are its components defined?

An aqueous solution is a homogeneous mixture formed by dissolving a solute (solid, liquid, or gas) in water, which acts as the solvent.

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How is molar concentration (CC) defined and mathematically expressed?

Molar concentration is the ratio of the number of moles of solute (nn) to the volume of solution (VV) in liters: C=nVC = \frac{n}{V}. It is expressed in mol⋅L−1\text{mol}\cdot\text{L}^{-1}.

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What is mass concentration (CmC_m), and what is its unit?

Mass concentration is the ratio of the mass of solute to the volume of the solution (Cm=mVC_m = \frac{m}{V}), expressed in g⋅L−1\text{g}\cdot\text{L}^{-1}.

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What is the mass concentration of a solution prepared by dissolving 250 g250\,\text{g} of sodium chloride in water to obtain 400 mL400\,\text{mL} of solution?

Cm=mV=250 g0.4 L=625.0 g⋅L−1C_m = \frac{m}{V} = \frac{250\,\text{g}}{0.4\,\text{L}} = 625.0\,\text{g}\cdot\text{L}^{-1}

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How is molality (bb) defined, and what is its formula?

Molality is the ratio of the number of moles of solute to the mass of solvent expressed in kilograms: b=nsolutemsolvent(kg)b = \frac{n_{\text{solute}}}{m_{\text{solvent}}(\text{kg})}.

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When dissolving 0.585 g0.585\,\text{g} of NaCl\text{NaCl} in 100 mL100\,\text{mL} of a solution with a density of 2.17 g⋅cm−32.17\,\text{g}\cdot\text{cm}^{-3}, what is the mass of the water (solvent)?

Mass of water=Mass of solution−Mass of solute=217 g−0.585 g=216.415 g\text{Mass of water} = \text{Mass of solution} - \text{Mass of solute} = 217\,\text{g} - 0.585\,\text{g} = 216.415\,\text{g} (or 0.216415 kg0.216415\,\text{kg}).

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What is the relationship between normality (NN) and molar concentration (CC)?

N=n(eˊqg)V=n⋅eqV=C⋅eqN = \frac{n(\text{éqg})}{V} = \frac{n \cdot eq}{V} = C \cdot eq, where eqeq is the equivalence factor (number of equivalents per mole).

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How is a gram-equivalent (eqg\text{eqg}) determined for an acid?

It is based on the number of H+H^+ ions the acid can donate upon complete dissociation (e.g., 1 mol1\,\text{mol} of HCl\text{HCl} corresponds to 1 eqg1\,\text{eqg}, and 1 mol1\,\text{mol} of H2SO4\text{H}_2\text{SO}_4 corresponds to 2 eqg2\,\text{eqg}).

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According to Brønsted's definition, how many gram-equivalents correspond to 1 mole1\,\text{mole} of hydrazine (H2N–NH2\text{H}_2\text{N–NH}_2)?

2 eqg2\,\text{eqg}, because 1 mole1\,\text{mole} of H2N–NH2\text{H}_2\text{N–NH}_2 accepts 2 moles2\,\text{moles} of H+H^+ through complete protonation.

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How is one equivalent gram (eqg\text{eqg}) defined for a salt?

One mole of positive (or negative) charges corresponds to 1 eqg1\,\text{eqg} of salt upon complete dissociation (e.g., 1 mol1\,\text{mol} of Na2SO4\text{Na}_2\text{SO}_4 yields 2 mol2\,\text{mol} of positive charges, corresponding to 2 eqg2\,\text{eqg}).

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How is one equivalent gram (eqg\text{eqg}) defined for oxidizing and reducing agents?

One mole of electrons exchanged corresponds to 1 eqg1\,\text{eqg} of oxidizing or reducing agent (e.g., when 1 mol1\,\text{mol} of Al\text{Al} loses 3 mol3\,\text{mol} of electrons, it corresponds to 3 eqg3\,\text{eqg}).

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What is the normality of a solution containing 98 g98\,\text{g} of phosphoric acid (H3PO4\text{H}_3\text{PO}_4, M=98 g⋅mol−1M = 98\,\text{g}\cdot\text{mol}^{-1}) dissolved in 500 mL500\,\text{mL} of solution?

N=6 NN = 6\,\text{N} (since n=1 moln = 1\,\text{mol}, and as a triprotic acid, neq=1×3=3 equivalentsn_{eq} = 1 \times 3 = 3\,\text{equivalents}, giving N=30.500 L=6 NN = \frac{3}{0.500\,\text{L}} = 6\,\text{N}).

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What is the formula for the mass percentage (%m/m\% m/m) of a solution?

%m/m=m1 solute(g)m2 solution(g)×100\% m/m = \frac{m_1\,\text{solute}(\text{g})}{m_2\,\text{solution}(\text{g})} \times 100

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What volume of pure hydrogen peroxide is present in 400 mL400\,\text{mL} of a 30% (v/v)30\%\,(v/v) solution?

v1=30×400 mL100=120 mLv_1 = \frac{30 \times 400\,\text{mL}}{100} = 120\,\text{mL}

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What are molar fraction (XiX_i) and mass fraction (WiW_i), and what is the sum of fractions in a mixture?

Molar fraction is Xi=ni∑iniX_i = \frac{n_i}{\sum_i n_i} and mass fraction is Wi=mi∑imiW_i = \frac{m_i}{\sum_i m_i}. Both are dimensionless, and their respective sums equal 11 (∑iXi=1\sum_i X_i = 1 and ∑iWi=1\sum_i W_i = 1).

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In aqueous solutions, what rule of thumb relates milligrams and liters to parts per million (ppm)?

1 mg1\,\text{mg} of solute dissolved in 1 L1\,\text{L} of water ≈1 ppm\approx 1\,\text{ppm}, because 1 L1\,\text{L} of water ≈1 kg=1,000,000 mg\approx 1\,\text{kg} = 1{,}000{,}000\,\text{mg}.

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How does the degree of dissociation (α\alpha) distinguish strong electrolytes from weak electrolytes?

α=Number of moles dissociated at equilibriumNumber of moles initially dissolved\alpha = \frac{\text{Number of moles dissociated at equilibrium}}{\text{Number of moles initially dissolved}}; α=1\alpha = 1 for a strong electrolyte, and 0<α<10 < \alpha < 1 for a weak electrolyte.

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Under what condition does an electrolyte solution exhibit ideal behavior rather than real (non-ideal) behavior?

A solution behaves ideally when it is very dilute, meaning solvation is complete, inter-ionic distances are large, and ion interactions are negligible. In concentrated solutions, interactions are non-negligible, causing real behavior.

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According to the Debye–Hückel model (1923), what is the formula for log⁡(γi)\log(\gamma_i) when the ionic strength is I<0.02 MI < 0.02\,\text{M}?

log⁡(γi)=−0.509Zi2I\log(\gamma_i) = -0.509 Z_i^2 \sqrt{I}, where ZiZ_i is the charge of ion ii and I=12∑Zi2CiI = \frac{1}{2} \sum Z_i^2 C_i.

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Why is the mean activity coefficient (γ±\gamma_{\pm}) introduced, and what is its formula for an electrolyte AmBn→mAn++nBm−A_m B_n \rightarrow m A^{n+} + n B^{m-}?

It is introduced because individual ion activity coefficients cannot be measured experimentally. It is defined as γ±=γAn+m×γBm−nm+n\gamma_{\pm} = \sqrt[m+n]{\gamma_{A^{n+}}^m \times \gamma_{B^{m-}}^n}.