Physics Equation projectiles launched at an angle

If vi is given, how do you find vyi?

vyi=vi(sin(theta))

If vi is given, what is the equation for vxi?

Vxi = vi (cos(theta))

If vi is given, how do you find Ymax?

Ymax= vi • sin (theta) • (t) + gt²/2

If vi is given, how do you find time in the x-direction?

t= x/ vi (cos (theta))

If vi is given, how do you find time in the y-direction?

t= -2 vi (sin (theta))/ g

Whats the equation do you need to find vi when x & theta are given

vi = square root of xg / 2 sin (theta) cos (theta) $\frac{\sqrt{xg}}{2\sin\left(\right)\cos\left(\right)}$

What is the equation to find vi if y & theta are given?$\sqrt{\frac{2gy}{\sin\left(\right)^2}}$

Vi= square root of 2gy/ sin(theta)²

What is the equation to find vi of x, t and theta are given?$\frac{x}{\cos\left(\right)t}$

Vi= x/ cos(theta) t